372. Delete Node in a Linked List【LintCode java】

Description

Implement an algorithm to delete a node in the middle of a singly linked list, given only access to that node.

Example

Linked list is 1->2->3->4, and given node 3, delete the node in place 1->2->4

解题：删除指定的结点。由于java没有delete 或者 free，如果要要删除的结点是最后一个节点，在不知道头结点的情况下，是不能删除的。代码如下：

/**
 * Definition for ListNode.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int val) {
 *         this.val = val;
 *         this.next = null;
 *     }
 * }
 */
 
public class Solution {
    /*
     * @param node: the node in the list should be deletedt
     * @return: nothing
     */
    public void deleteNode(ListNode node) {
        // write your code here
        if(node == null || node.next == null)
            return;
 
        node.val = node.next.val;
        node.next = node.next.next;
        return;
 
    }
}