Wiggle Sort 解答
Question
Given an unsorted array nums
, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3]...
.
For example, given nums = [3, 5, 2, 1, 6, 4]
, one possible answer is [1, 6, 2, 5, 3, 4]
.
Solution 1
仔细观察题目,有个条件很重要就是nums[0] <= nums[1] >= nums[2] <= nums[3]...
.也就是说对于奇书的 i 我们要保证 nums[i - 1] <= nums[i] <= nums[i + 1] 所以第一个想法是1. 先排序 2. 交换每个nums[i] 和 nums[i + 1]
Time complexity O(n log n).
public class Solution {
public void wiggleSort(int[] nums) {
if (nums == null || nums.length < 2)
return;
Arrays.sort(nums);
for (int i = 1; i < nums.length - 1; i = i + 2) {
int tmp = nums[i];
nums[i] = nums[i + 1];
nums[i + 1] = tmp;
}
}
}
Solution 2
分奇偶来思考。
如果i是奇数,那么nums[i]应该大于nums[i - 1],否则交换
如果i是偶数,那么nums[i]应该小于nums[i - 1],否则交换
public class Solution {
public void wiggleSort(int[] nums) {
if (nums == null)
return;
for (int i = 1; i < nums.length; i++) {
if (i % 2 == 1) {
if (nums[i] < nums[i - 1])
swap(nums, i, i - 1);
} else {
if (nums[i] > nums[i - 1])
swap(nums, i, i - 1);
}
}
}
private void swap(int[] nums, int x, int y) {
int tmp = nums[x];
nums[x] = nums[y];
nums[y] = tmp;
}
}
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