如何解决cuffdiff运行结果中表达量为0的情况?

cuffdiff -o cdiffout -b ref.fasta -u -p 15 --library-type fr-firststrand \
-L H_3,O_3,F_3 cuffmergeout/merged.gtf \
tophatout/H-1-3/accepted_hits.bam,tophatout/H-2-3/accepted_hits.bam,tophatout/H-3-3/accepted_hits.bam \
tophatout/O-1-3/accepted_hits.bam,tophatout/O-2-3/accepted_h its.bam,tophatout/O-3-3/accepted_hits.bam \
tophatout/F-1-3/accepted_hits.bam,tophatout/F-2-3/accepted_hits.bam,tophatout/F-3-3/accepted
_hits.bam

Processed 33185 loci. [***************] 100%
Performed 0 isoform-level transcription difference tests
Performed 0 tss-level transcription difference tests
Performed 0 gene-level transcription difference tests
Performed 0 CDS-level transcription difference tests
Performed 0 splicing tests
Performed 0 promoter preference tests
Performing 0 relative CDS output tests
Writing isoform-level FPKM tracking
Writing TSS group-level FPKM tracking
Writing gene-level FPKM tracking
Writing CDS-level FPKM tracking
Writing isoform-level count tracking
Writing TSS group-level count tracking
Writing gene-level count tracking
Writing CDS-level count tracking
Writing isoform-level read group tracking
Writing TSS group-level read group tracking
Writing gene-level read group tracking
Writing CDS-level read group tracking
Writing read group info
Writing run info

解决办法:先使用 cuffquant 对每个样本估计 gene 和 transcript 的表达量,然后再用 cuffdiff 进行差异表达的分析。

原理是:distribute your computational load over a cluster;save your time.

cuffdiff problem--Performed 0 isoform-level transcription difference tests的更多相关文章

  1. [Codechef TASTR] Level of Difference - 后缀数组,容斥原理

    [Codechef TASTR] Level of Difference Description 给定两个字符串,求恰好在一个字符串中出现过的本质不同的子串数量. Solution 设 \(U(S)\ ...

  2. [LeetCode&Python] Problem 107. Binary Tree Level Order Traversal II

    Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left ...

  3. [LeetCode&Python] Problem 429. N-ary Tree Level Order Traversal

    Given an n-ary tree, return the level order traversal of its nodes' values. (ie, from left to right, ...

  4. UVa 11389 - The Bus Driver Problem 难度:0

    题目 https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&a ...

  5. HDU 2101 A + B Problem Too 分类: ACM 2015-06-16 23:57 18人阅读 评论(0) 收藏

    A + B Problem Too Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others ...

  6. Hibernate Validator 6.0.9.Final - JSR 380 Reference Implementation: Reference Guide

    Preface Validating data is a common task that occurs throughout all application layers, from the pre ...

  7. 【译】Android 6.0 Changes (机翻加轻微人工校对)

    Android 6.0 Changes In this document Runtime Permissions Doze and App Standby Apache HTTP Client Rem ...

  8. HDU4971 A simple brute force problem.(强连通分量缩点 + 最大权闭合子图)

    题目 Source http://acm.hdu.edu.cn/showproblem.php?pid=4971 Description There's a company with several ...

  9. This problem will occur when running in 64 bit mode with the 32 bit Oracle client components installed(在64位模式下运行安装了32位的Oracle客户端组件时,会发生此问题)

    部署win服务时出现下面的问题: 在事件查看器中看到如下错误: 日志名称: Application来源: ***调度服务日期: 2014/5/21 12:53:21事件 ID: 0任务类别: 无级别: ...

随机推荐

  1. 关于 js 动态生成html 绑定事件失效的问题

    在实际问题中,也只到使用新版jq 的on 事件 进行动态元素的绑定: 是这样 (但是依然没有效果——): $('dom节点').on('click',function(){}) 之后经过查阅发现:正确 ...

  2. restful demo 演示; jquery min1.1;

    [说明]上午建立了一个restful风格的一个测试,运行通过:下午试了试postman,想看看http请求的具体过程,但是chrome浏览器的network面板也可以查看,并且很方便,就索性用它了 一 ...

  3. xampp怎么操作数据库mysql

    1.打开软件的主界面,打开Apache和MySQL,然后点击MySQL后面的admin.且我操作时,Apache,MySQL要启动,才打的开. 2.打开MySQL,报错. 09:00:23 [mysq ...

  4. Bridge Method

    1.java编译器采用Bridge Method 来兼容本该使用泛型的地方使用了非泛型的问题. public class TestBridgeMethod { public static void m ...

  5. SQLServer: 用 ApexSQLLog 恢复 SQL Server 数据

    https://blog.csdn.net/yenange/article/details/50512312

  6. OpenCV3计算机视觉+python(三)

    使用OpenCV3处理图像 下面要介绍的内容都与图像处理有关,这时需要修改图像,比如要使用具有艺术性的滤镜.外插(extrapolate)某些部分.分割.粘贴或其他需要的操作. 不同色彩空间的转换 O ...

  7. C++实现计算器功能(包括计算含未知量的式子),输出后缀表达式

    大概描述        用c++语言在vc中实现部分数学计算功能.其中实现的数学计算功能包括加减乘除运算.开方计算.自然对数运算.以10为底的对数运算.幂计算.正弦余弦计算. 由用户输入要计算的表达式 ...

  8. 剑指offer 面试63题

    面试63题 题目:股票的最大利润 题:假设把某股票的价格按照时间先后顺序存储在数组中,请问买卖该股票一次可获得的最大利润是多少?例如,一只股票在某些时间节点的价格为{9,11,8,5,7,12,16, ...

  9. Simple Tips for Collection in Python

    I believe that the following Python code is really not hard to understand. But I think we should use ...

  10. django用户信息扩展

    Django封装了好多东西,拿来用就可以了,帮我们封装类用户的登录认证,用户的表 所以Django自带有用户表,当扩展用户表后一些表就会被替换 用户认证相关的    功能放在django.contri ...