两个list 求交集效率对比

__author__ = 'daitr'
#--coding:utf-8--
import datetime
#方法一:
#a=[2,3,4,5]
#b=[2,5,8]
#tmp = [val for val in a if val in b]
#print tmp
##[2, 5]
 
#方法二
#print list(set(a).intersection(set(b)))
#print list(set(a).union(set(b)))
#print list(set(b).difference(set(a))) # b中有而a中没有的
 
a,b= [],[]
for i in range(1,60000):
    a.append(i)
 
for j in range(40000,100000):
    b.append(j)
print a[-1]
print b[-1]
 
time1 = datetime.datetime.now()
#print time1
 
tmp = [val for val in a if val in b]
#print tmp
 
time2 = datetime.datetime.now()
#print time2
d1 = time2-time1
print d1
 
list(set(a).intersection(set(b)))
#print temp2
 
time3 = datetime.datetime.now()
#print time3
d2 = time3-time2
print d2