剑指Offer08 二进制中1的个数

 /*************************************************************************
     > File Name: 08_NumOf1InBinary.c
     > Author: Juntaran
     > Mail: JuntaranMail@gmail.com
     > Created Time: 2016年08月29日 星期一 20时40分15秒
  ************************************************************************/

 #include <stdio.h>

 int NumberOf1_1(int n)
 {
     int count = ;
     int flag = ;
     while (flag < n)
     {
         if (n & flag)
             count ++;
         flag = flag << ;
     }
     return count;
 }

 int NumberOf1_2(int n)
 {
     int count = ;
     while (n)
     {
         ++ count;
         n = (n - ) & n;
     }
     return count;
 }

 int main()
 {
     int ret1 = ;
     int ret2 = ;

     int n = ;
     ret1 = NumberOf1_1(n);
     ret2 = NumberOf1_2(n);
     printf("ret1 is %d\n", ret1);
     printf("ret2 is %d\n", ret2);
 }