CodeForces 651A(水题)
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at a1 percent and second one is charged at a2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if not connected to a charger) or charges by 1 percent (if connected to a charger).
Game continues while both joysticks have a positive charge. Hence, if at the beginning of minute some joystick is charged by 1 percent, it has to be connected to a charger, otherwise the game stops. If some joystick completely discharges (its charge turns to 0), the game also stops.
Determine the maximum number of minutes that game can last. It is prohibited to pause the game, i. e. at each moment both joysticks should be enabled. It is allowed for joystick to be charged by more than 100 percent.
Input
The first line of the input contains two positive integers a1 and a2 (1 ≤ a1, a2 ≤ 100), the initial charge level of first and second joystick respectively.
Output
Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged.
Sample Input
3 5
6
4 4
5 题意 两个游戏机,每分钟充电电量加1,不充电量减2,只能给一台游戏机充电(可交换),当其中一台电量为0则停在,求持续的分钟数
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
int a1,a2;
while(cin>>a1>>a2)
{
if(a1<a2)
{
a2=a1+a2;
a1=a2-a1;
a2=a2-a1;
}
if(a1==&&a2==)
cout<<<<endl;
int t=;
while(a1>&&a2>)
{
if(a2>a1)
{
a2=a2-;
a1=a1+;
}
else
{
a1=a1-;
a2=a2+;
}
t++;
}
cout<<t<<endl;
}
return ;
}
CodeForces 651A(水题)的更多相关文章
- Codeforces Round #345(Div. 2)-651A.水题 651B.。。。 651C.去重操作 真是让人头大
A. Joysticks time limit per test 1 second memory limit per test 256 megabytes input standard input o ...
- Pearls in a Row CodeForces 620C 水题
题目:http://codeforces.com/problemset/problem/620/C 文章末有一些测试数据仅供参考 题目大意 给你一个数字串,然后将分成几个部分,要求每个部分中必须有一对 ...
- 【Codeforces自我陶醉水题篇~】(差17C code....)
Codeforces17A 题意: 有一种素数会等于两个相邻的素数相加 如果在2~n的范围内有至少k个这样的素数,就YES,否则就NO; 思路: 采用直接打表,后面判断一下就好了.那个预处理素数表还是 ...
- CodeForces 327B 水题。
I - 9 Time Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u Submit Statu ...
- Codeforces - 631B 水题
注意到R和C只与最后一个状态有关 /*H E A D*/ struct node2{ int kind,las,val,pos; node2(){} node2(int k,int l,int v,i ...
- 水题 Codeforces Round #302 (Div. 2) A Set of Strings
题目传送门 /* 题意:一个字符串分割成k段,每段开头字母不相同 水题:记录每个字母出现的次数,每一次分割把首字母的次数降为0,最后一段直接全部输出 */ #include <cstdio> ...
- 水题 Codeforces Round #300 A Cutting Banner
题目传送门 /* 水题:一开始看错题意,以为是任意切割,DFS来做:结果只是在中间切出一段来 判断是否余下的是 "CODEFORCES" :) */ #include <cs ...
- Codeforces Testing Round #8 B. Sheldon and Ice Pieces 水题
题目链接:http://codeforces.com/problemset/problem/328/B 水题~ #include <cstdio> #include <cstdlib ...
- Codeforces Round #356 (Div. 2)B. Bear and Finding Criminals(水题)
B. Bear and Finding Criminals time limit per test 2 seconds memory limit per test 256 megabytes inpu ...
- Codeforces Round #368 (Div. 2) A. Brain's Photos (水题)
Brain's Photos 题目链接: http://codeforces.com/contest/707/problem/A Description Small, but very brave, ...
随机推荐
- SQL学习--Select(一)TOP、派生表、连接、谓词
TOP关键字 WITH TIES t.title,sum(s.qty)as totalSales from sales s left join titles t on s.title_id=t.tit ...
- Android ViewPager使用方法小结
android-support-v4.jar 是谷歌提供给我们的一个兼容低版本安卓设备的软件包,里面包囊了只有在 Android 3.0 以上可用的API.而 ViewPager 就是其中之一.利用它 ...
- C语言笔记(二)
注释 编译器会用空格代替代码中原来的注释,并先于预处理指令执行/*…*/ 这种形式的注释不能嵌套只要斜杠(/)和星号(*)之间没有空格,都会被当作注释的开始.例如这样:y = x/*p; \ 是一个接 ...
- 菜鸟使用 centOS 安装 redis 并放入service 启动 记录
1.下载redis: wget http://download.redis.io/releases/redis-2.8.17.tar.gz 若wget 不可用,请先安装wget yum install ...
- OpenCV:OpenCV图像旋转的代码
OpenCV图像旋转的代码 cv::transpose( bfM, bfM ) 前提:使用两个矩阵Mat型进行下标操作是不行的,耗费的时间太长了.直接使用两个指针对拷贝才是王道.不知道和OpenCV比 ...
- python3:语法变动 及新特性
python3.0 对python2.x 升级后重大语法变动,幸好留下2.7.6及后续2版本,保持一些语法兼容. 原始地址:http://hi.baidu.com/jxq61/item/3a24883 ...
- MFC 缩放和显示IplImage
序言:使用OpenCV嵌入MFC的框内,图像大小不能和框大小进行匹配,因此需要缩放,使图像适用于MFC框. 后来找到了一种新的方法,此方案貌似u已经废弃. (1).在MFC中显示图片 void CAv ...
- Window8.1下安装Matplotlib库
有两种方法: 直接选用一些预打包库软件,如WinPython, Python(x,y), Enthought Canopy, or Continuum Anaconda.这些软件中已包含有Matplo ...
- 【sqli-labs】 less32 GET- Bypass custom filter adding slashes to dangrous chars (GET型转义了'/"字符的宽字节注入)
转义函数,针对以下字符,这样就无法闭合引号,导致无法注入 ' --> \' " --> \" \ --> \\ 但是,当MySQL的客户端字符集为gbk时,就可能 ...
- 【sqli-labs】 less27 GET- Error based -All you Union&Select Belong to us -String -Single quote(GET型基于错误的去除了Union和Select的单引号字符型注入)
看一下过滤函数 看一下/s是什么东西 那直接通过大小写就可以绕过了 http://192.168.136.128/sqli-labs-master/Less-27/?id=0'%a0uNion%a0s ...