CF 447B(DZY Loves Strings-贪心)
1 second
256 megabytes
standard input
standard output
DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its value wc.
For each special string s = s1s2... s|s| (|s| is
the length of the string) he represents its value with a function f(s), where
Now DZY has a string s. He wants to insert k lowercase
letters into this string in order to get the largest possible value of the resulting string. Can you help him calculate the largest possible value he could get?
The first line contains a single string s (1 ≤ |s| ≤ 103).
The second line contains a single integer k (0 ≤ k ≤ 103).
The third line contains twenty-six integers from wa to wz.
Each such number is non-negative and doesn't exceed 1000.
Print a single integer — the largest possible value of the resulting string DZY could get.
abc
3
1 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
41
In the test sample DZY can obtain "abcbbc", value = 1·1 + 2·2 + 3·2 + 4·2 + 5·2 + 6·2 = 41.
贪心,不难想到取最大的w扔在末尾
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<algorithm>
#include<functional>
#include<iostream>
#include<cmath>
#include<cctype>
#include<ctime>
using namespace std;
#define For(i,n) for(int i=1;i<=n;i++)
#define Fork(i,k,n) for(int i=k;i<=n;i++)
#define Rep(i,n) for(int i=0;i<n;i++)
#define ForD(i,n) for(int i=n;i;i--)
#define RepD(i,n) for(int i=n;i>=0;i--)
#define Forp(x) for(int p=pre[x];p;p=next[p])
#define Lson (x<<1)
#define Rson ((x<<1)+1)
#define MEM(a) memset(a,0,sizeof(a));
#define MEMI(a) memset(a,127,sizeof(a));
#define MEMi(a) memset(a,128,sizeof(a));
#define INF (2139062143)
#define F (100000007)
#define MAXN (1000+10)
long long mul(long long a,long long b){return (a*b)%F;}
long long add(long long a,long long b){return (a+b)%F;}
long long sub(long long a,long long b){return (a-b+(a-b)/F*F+F)%F;}
typedef long long ll;
char s[MAXN];
int k,w[MAXN];
int main()
{
// freopen("Strings.in","r",stdin);
// freopen(".out","w",stdout); scanf("%s\n%d",s+1,&k); int len=strlen(s+1); int p=0;
Fork(i,'a','z') cin>>w[i],p=max(p,w[i]); ll ans=0;
For(i,len) ans+=w[s[i]]*i; if (k) ans+=(len+1+len+k)*k/2*p; cout<<ans<<endl; return 0;
}
CF 447B(DZY Loves Strings-贪心)的更多相关文章
- CF447B DZY Loves Strings 贪心
DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter ...
- [CodeForces - 447B] B - DZY Loves Strings
B - DZY Loves Strings DZY loves collecting special strings which only contain lowercase letters. For ...
- Codeforces Round #254 (Div. 1) D - DZY Loves Strings
D - DZY Loves Strings 思路:感觉这种把询问按大小分成两类解决的问题都很不好想.. https://codeforces.com/blog/entry/12959 题解说得很清楚啦 ...
- Codeforces Round #254 (Div. 1) D. DZY Loves Strings hash 暴力
D. DZY Loves Strings 题目连接: http://codeforces.com/contest/444/problem/D Description DZY loves strings ...
- Codeforces Round #FF (Div. 2):B. DZY Loves Strings
B. DZY Loves Strings time limit per test 1 second memory limit per test 256 megabytes input standard ...
- CF 444C DZY Loves Physics(图论结论题)
题目链接: 传送门 DZY Loves Chemistry time limit per test1 second memory limit per test256 megabytes Des ...
- CF 445B DZY Loves Chemistry(并查集)
题目链接: 传送门 DZY Loves Chemistry time limit per test:1 second memory limit per test:256 megabytes D ...
- CF 444A(DZY Loves Physics-低密度脂蛋白诱导子图)
A. DZY Loves Physics time limit per test 1 second memory limit per test 256 megabytes input standard ...
- CF 444B(DZY Loves FFT-时间复杂度)
B. DZY Loves FFT time limit per test 1 second memory limit per test 256 megabytes input standard inp ...
随机推荐
- 01背包问题(回溯法)python实现
接上一篇,相同的01背包问题,上一篇採用动态规划的方法,如今用回溯法解决. 回溯法採用深度优先策略搜索问题的解.不多说.代码例如以下: bestV=0 curW=0 curV=0 bestx=None ...
- CGContext含义
代码 含义 CGContextRef context = UIGraphicsGetCurrentContext(); 设置上下文 CGContextMoveToPoint 开始画线 CGContex ...
- 三大表连接方式详解之Nested loop join和 Sort merge join
在早期版本,Oracle提供的是nested-loop join,两表连接就相当于二重循环,假定两表分别有m行和n行 如果内循环是全表扫描,时间复杂度就是O(m*n) 如果内循 ...
- oracle 11gR2 如何修改 private ip
1.1 修改 private ip1.1.1 确保crs集群是打开的可以用olsnodes –s 检查集群的状态./olsnodes -sP570a ActiveP570b Active1.1 ...
- Mac 安装cmake小问题
今天用 brew install cmake. ==> Downloading https://homebrew.bintray.com/bottles/cmake-3.9.6.sierra.b ...
- 又一个设计工具 Framer X Preview
又一个设计工具 Framer X Preview 所说比 Sketch 和 Figma 都要好用,不知道是不是真的 ~~ To give you a little background, I've b ...
- 不得了,微软原生提供 AI 人工智能 API,而且面向网页开放
微软原生人工智能(AI) API 不得了,微软原生提供 AI 人工智能 API,而且面向网页开放
- Function 和 eval 知识点总结
1 Function 1.1 函数的创建方式 1 函数声明 2 函数表达式 3 new Function // 1 function foo() {} // 2 var foo = function( ...
- Hibernate框架学习(六)——一对多&多对一关系
一.关系表达 1.表中的表达 2.实体中的表达 3.orm元数据中的表达 一对多:(在Customer.hbm.xml中添加) 多对一:(在LinkMan.hbm.xml中添加) 最后别忘了在hibe ...
- 路飞学城Python-Day20(元类的练习题)
练习一:在元类中控制把自定义类的数据属性都变成大写 class MyDef(type): def __new__(cls, class_name, class_attr, class_dic): up ...