Java for LeetCode 236 Lowest Common Ancestor of a Binary Tree

解题思路一：

DFS到每个节点的路径，根据路径算出LCA：

public class Solution {
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
		if (root == p || root == q)
			return root;
		List pList = new ArrayList<TreeNode>(), qList = new ArrayList<TreeNode>();
		getPath(root,p,pList);
		getPath(root,q,qList);
		for(int i=0;i<Math.min(pList.size(), qList.size());i++){
			if(pList.get(i)!=qList.get(i))
				return (TreeNode) pList.get(i-1);
		}
		return (TreeNode) pList.get(Math.min(pList.size(), qList.size())-1);
	}
 
	private boolean getPath(TreeNode root, TreeNode p, List<TreeNode> path) {
		path.add(root);
		if (root == p)
			return true;
		if (root.left != null) {
			if (getPath(root.left, p, path))
				return true;
			path.remove(path.size() - 1);
		}
		if (root.right != null) {
			if (getPath(root.right, p, path))
				return true;
			path.remove(path.size() - 1);
		}
		return false;
	}
}

解题思路二：

后续遍历+并查集（《数据结构》第11章内容），实现的时间空间，复杂度略高

解题思路三：并查集+Tarjan算法

参考：http://baike.baidu.com/link?url=oJBohljiyLYv4B0lFr5nbXOeYQ6B1PD4jAYAAZ0v2jKWR_ygiKyNFYqfIgWYbST0meiByvGTFNEjftX7vst90q#3_1