周赛-Expression 分类: 比赛 2015-08-02 09:35 3人阅读 评论(0) 收藏
A. Expression
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers a, b, c on the blackboard. The task was to insert signs of operations ‘+’ and ‘*’, and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let’s consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:
1+2*3=7
1*(2+3)=5
1*2*3=6
(1+2)*3=9
Note that you can insert operation signs only between a and b, and between b and c, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.
It’s easy to see that the maximum value that you can obtain is 9.
Your task is: given a, b and c print the maximum value that you can get.
Input
The input contains three integers a, b and c, each on a single line (1 ≤ a, b, c ≤ 10).
Output
Print the maximum value of the expression that you can obtain.
Sample test(s)
input
1
2
3
output
9
input
2
10
3
output
60
枚举飘过
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <queue>
#include <stack>
#include <map>
#include <list>
#include <algorithm>
#define LL long long
#define RR freopen("output.txt","r",stdoin)
#define WW freopen("input.txt","w",stdout)
using namespace std;
const int MAX = 100100;
int main()
{
int a,b,c;
int Max;
while(~scanf("%d %d %d",&a,&b,&c))
{
Max=0;
Max=max(Max,a+b+c);
Max=max(Max,a*(b+c));
Max=max(Max,(a+b)*c);
Max=max(Max,a*b*c);
Max=max(Max,a*b+c);
Max=max(Max,a+b*c);
printf("%d\n",Max);
}
return 0;
}
版权声明:本文为博主原创文章,未经博主允许不得转载。
周赛-Expression 分类: 比赛 2015-08-02 09:35 3人阅读 评论(0) 收藏的更多相关文章
- Hdu 1507 Uncle Tom's Inherited Land* 分类: Brush Mode 2014-07-30 09:28 112人阅读 评论(0) 收藏
Uncle Tom's Inherited Land* Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (J ...
- iOS开源库--最全的整理 分类: ios相关 2015-04-08 09:20 486人阅读 评论(0) 收藏
youtube下载神器:https://github.com/rg3/youtube-dl 我擦咧 vim插件:https://github.com/Valloric/YouCompleteMe vi ...
- Jquery easy UI 上中下三栏布局 分类: ASP.NET 2015-02-06 09:19 368人阅读 评论(0) 收藏
效果图: 源代码: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://w ...
- C# IIS应用程序池辅助类 分类: C# Helper 2014-07-19 09:50 249人阅读 评论(0) 收藏
using System.Collections.Generic; using System.DirectoryServices; using System.Linq; using Microsoft ...
- PIGS 分类: POJ 图论 2015-08-10 09:15 3人阅读 评论(0) 收藏
PIGS Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 18209 Accepted: 8277 Description Mir ...
- Babelfish 分类: 哈希 2015-08-04 09:25 2人阅读 评论(0) 收藏
Babelfish Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 36398 Accepted: 15554 Descripti ...
- java 解决JFrame不能设置背景色的问题 分类: Java Game 2014-08-15 09:48 119人阅读 评论(0) 收藏
这段时间比较多,于是写一写JAVA的一些IT技术文章.如有JAVA高手请加QQ:314783246,互相讨论. 在Java的GUI设计中,Frame和JFrame两者之间有很大差别,上次刚学时编一个窗 ...
- Poj 2528 Mayor's posters 分类: Brush Mode 2014-07-23 09:12 84人阅读 评论(0) 收藏
Mayor's posters Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 40570 Accepted: 11798 ...
- Poj 2349 Arctic Network 分类: Brush Mode 2014-07-20 09:31 93人阅读 评论(0) 收藏
Arctic Network Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 9557 Accepted: 3187 De ...
随机推荐
- .NET业务实体类验证组件Fluent Validation
认识Fluent Vaidation. 看到NopCommerce项目中用到这个组建是如此的简单,将数据验证从业务实体类中分离出来,真是一个天才的想法,后来才知道这个东西是一个开源的轻量级验证组建. ...
- redhat vim编辑器永久添加行号
cd ~ vim .vimrc 第一行加入: set nu :wq 保存退出,即可 如果想取消设置,同理删除set nu即可
- swift语言实战晋级-1 Swift开发环境的搭建
想要进行Swift的学习,必须要有个开发环境.简单的说就是装好了Xcode的Mac系统.那么接下来我们就简单了解一下这方面的内容. 1.1 下载Xcode Xcode是苹果公司出的编程工具,类似于微软 ...
- PostgreSQL pg_dump pg_dumpall and restore
pg_dump dumps a database as a text file or to other formats. Usage: pg_dump [OPTION]... [DBNAME] Gen ...
- Summary: Trie Data Structure
Implement a Trie Data Structure, and search() & insert() function: we need to implement both Cla ...
- srcolltop 的用法
document.body.scrollTop用法 网页可见区域宽: document.body.clientWidth;网页可见区域高: document.body.clientHeight;网页可 ...
- [原创]java WEB学习笔记56:Struts2学习之路---Struts 版本的 登录 demo
本博客的目的:①总结自己的学习过程,相当于学习笔记 ②将自己的经验分享给大家,相互学习,互相交流,不可商用 内容难免出现问题,欢迎指正,交流,探讨,可以留言,也可以通过以下方式联系. 本人互联网技术爱 ...
- B/S与C/S区别
B/S (Brower/Server)-->浏览器/服务器 程序完全部署在服务器上,用户通过浏览器访问应用程序,它是基于internet产物(在应用服务器中部署运行程序) c/s(Client/ ...
- cocos2d-x游戏开发之动画
MyGame.h中声明动画函数: class MyGame : public cocos2d::Layer{public: static Scene* createScene(); void U ...
- Cocos2d-x游戏开发之计时器
首先写一个计时器的头文件GameTimer.h: #ifndef _GAME_TIMER_H_ #define _GAME_TIMER_H_ #include "cocos2d.h" ...