暴力枚举——Help Me with the Game
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 3394 | Accepted: 2172 |
Description
Input
Output
The description of the position of the pieces is a comma-separated
list of terms describing the pieces of the appropriate player. The
description of a piece consists of a single upper-case letter that
denotes the type of the piece (except for pawns, for that this
identifier is omitted). This letter is immediatelly followed by the
position of the piece in the standard chess notation -- a lower-case
letter between "a" and "h" that determines the column ("a" is the
leftmost column in the input) and a single digit between 1 and 8 that
determines the row (8 is the first row in the input).
The pieces in the description must appear in the following order:
King("K"), Queens ("Q"), Rooks ("R"), Bishops ("B"), Knights ("N"), and
pawns. Note that the numbers of pieces may differ from the initial
position because of capturing the pieces and the promotions of pawns. In
case two pieces of the same type appear in the input, the piece with
the smaller row number must be described before the other one if the
pieces are white, and the one with the larger row number must be
described first if the pieces are black. If two pieces of the same type
appear in the same row, the one with the smaller column letter must
appear first.
Sample Input
+---+---+---+---+---+---+---+---+
|.r.|:::|.b.|:q:|.k.|:::|.n.|:r:|
+---+---+---+---+---+---+---+---+
|:p:|.p.|:p:|.p.|:p:|.p.|:::|.p.|
+---+---+---+---+---+---+---+---+
|...|:::|.n.|:::|...|:::|...|:p:|
+---+---+---+---+---+---+---+---+
|:::|...|:::|...|:::|...|:::|...|
+---+---+---+---+---+---+---+---+
|...|:::|...|:::|.P.|:::|...|:::|
+---+---+---+---+---+---+---+---+
|:P:|...|:::|...|:::|...|:::|...|
+---+---+---+---+---+---+---+---+
|.P.|:::|.P.|:P:|...|:P:|.P.|:P:|
+---+---+---+---+---+---+---+---+
|:R:|.N.|:B:|.Q.|:K:|.B.|:::|.R.|
+---+---+---+---+---+---+---+---+
Sample Output
White: Ke1,Qd1,Ra1,Rh1,Bc1,Bf1,Nb1,a2,c2,d2,f2,g2,h2,a3,e4
Black: Ke8,Qd8,Ra8,Rh8,Bc8,Ng8,Nc6,a7,b7,c7,d7,e7,f7,h7,h6
Source
#include<cstdio>
#include<string.h>
using namespace std;
char str[][];
char s[];
int main()
{
int i,j;
int first=;
for(i=; i<; i++)
{
scanf("%s",s);
getchar();
scanf("%s",s);
for(j=; j<; j++)
str[i][j]=s[j*+];
}
printf("White: ");
for(i=; i>=; i--)
for(j=; j<; j++)
{
if(str[i][j]=='K')
{
if(first==)
{
printf("K%c%d",'a'+j,-i);
first=;
}
else printf(",K%c%d",'a'+j,-i);
}
}
for(i=; i>=; i--)
for(j=; j<; j++)
{
if(str[i][j]=='Q')
{
if(first==)
{
printf("Q%c%d",'a'+j,-i);
first=;
}
else printf(",Q%c%d",'a'+j,-i);
}
}
for(i=; i>=; i--)
for(j=; j<; j++)
{
if(str[i][j]=='R')
{
if(first==)
{
printf("R%c%d",'a'+j,-i);
first=;
}
else printf(",R%c%d",'a'+j,-i);
}
}
for(i=; i>=; i--)
for(j=; j<; j++)
{
if(str[i][j]=='B')
{
if(first==)
{
printf("B%c%d",'a'+j,-i);
first=;
}
else printf(",B%c%d",'a'+j,-i);
}
}
for(i=; i>=; i--)
for(j=; j<; j++)
{
if(str[i][j]=='N')
{
if(first==)
{
printf("N%c%d",'a'+j,-i);
first=;
}
else printf(",N%c%d",'a'+j,-i);
}
}
for(i=; i>=; i--)
for(j=; j<; j++)
{
if(str[i][j]=='P')
{
if(first==)
{
printf("%c%d",'a'+j,-i);
first=;
}
else printf(",%c%d",'a'+j,-i);
}
}
first=;
printf("\n");
printf("Black: ");
for(i=; i<=; i++)
for(j=; j<; j++)
{
if(str[i][j]=='k')
{
if(first==)
{
printf("K%c%d",'a'+j,-i);
first=;
}
else printf(",K%c%d",'a'+j,-i);
}
}
for(i=; i<=; i++)
for(j=; j<; j++)
{
if(str[i][j]=='q')
{
if(first==)
{
printf("Q%c%d",'a'+j,-i);
first=;
}
else printf(",Q%c%d",'a'+j,-i);
}
}
for(i=; i<=; i++)
for(j=; j<; j++)
{
if(str[i][j]=='r')
{
if(first==)
{
printf("R%c%d",'a'+j,-i);
first=;
}
else printf(",R%c%d",'a'+j,-i);
}
}
for(i=; i<=; i++)
for(j=; j<; j++)
{
if(str[i][j]=='b')
{
if(first==)
{
printf("B%c%d",'a'+j,-i);
first=;
}
else printf(",B%c%d",'a'+j,-i);
}
}
for(i=; i<=; i++)
for(j=; j<; j++)
{
if(str[i][j]=='n')
{
if(first==)
{
printf("N%c%d",'a'+j,-i);
first=;
}
else printf(",N%c%d",'a'+j,-i);
}
}
for(i=; i<=; i++)
for(j=; j<; j++)
{
if(str[i][j]=='p')
{
if(first==)
{
printf("%c%d",'a'+j,-i);
first=;
}
else printf(",%c%d",'a'+j,-i);
}
}
return ;
}
暴力枚举——Help Me with the Game的更多相关文章
- CodeForces 742B Arpa’s obvious problem and Mehrdad’s terrible solution (暴力枚举)
题意:求定 n 个数,求有多少对数满足,ai^bi = x. 析:暴力枚举就行,n的复杂度. 代码如下: #pragma comment(linker, "/STACK:1024000000 ...
- 2014牡丹江网络赛ZOJPretty Poem(暴力枚举)
/* 将给定的一个字符串分解成ABABA 或者 ABABCAB的形式! 思路:暴力枚举A, B, C串! */ 1 #include<iostream> #include<cstri ...
- HNU 12886 Cracking the Safe(暴力枚举)
题目链接:http://acm.hnu.cn/online/?action=problem&type=show&id=12886&courseid=274 解题报告:输入4个数 ...
- 51nod 1116 K进制下的大数 (暴力枚举)
题目链接 题意:中文题. 题解:暴力枚举. #include <iostream> #include <cstring> using namespace std; ; ; ch ...
- Codeforces Round #349 (Div. 1) B. World Tour 最短路+暴力枚举
题目链接: http://www.codeforces.com/contest/666/problem/B 题意: 给你n个城市,m条单向边,求通过最短路径访问四个不同的点能获得的最大距离,答案输出一 ...
- bzoj 1028 暴力枚举判断
昨天梦到这道题了,所以一定要A掉(其实梦到了3道,有两道记不清了) 暴力枚举等的是哪张牌,将是哪张牌,然后贪心的判断就行了. 对于一个状态判断是否为胡牌,1-n扫一遍,然后对于每个牌,先mod 3, ...
- POJ-3187 Backward Digit Sums (暴力枚举)
http://poj.org/problem?id=3187 给定一个个数n和sum,让你求原始序列,如果有多个输出字典序最小的. 暴力枚举题,枚举生成的每一个全排列,符合即退出. dfs版: #in ...
- hihoCoder #1179 : 永恒游戏 (暴力枚举)
题意: 给出一个有n个点的无向图,每个点上有石头数个,现在的游戏规则是,设置某个点A的度数为d,如果A点的石子数大于等于d,则可以从A点给每个邻接点发一个石子.如果游戏可以玩10万次以上,输出INF, ...
- CCF 201312-4 有趣的数 (数位DP, 状压DP, 组合数学+暴力枚举, 推公式, 矩阵快速幂)
问题描述 我们把一个数称为有趣的,当且仅当: 1. 它的数字只包含0, 1, 2, 3,且这四个数字都出现过至少一次. 2. 所有的0都出现在所有的1之前,而所有的2都出现在所有的3之前. 3. 最高 ...
- hdu 1172 猜数字(暴力枚举)
题目 这是一道可以暴力枚举的水题. //以下两个都可以ac,其实差不多一样,呵呵 //1: //4 wei shu #include<stdio.h> struct tt { ],b[], ...
随机推荐
- ODBC错误处理
ODBC 中的错误处理 ODBC 中的错误是使用来自每个 ODBC 函数调用的返回值和 SQLError 函数或 SQLGetDiagRec 函数的返回值进行报告的.SQLError 函数用于 ODB ...
- [转]CentOS更改yum源与更新系统
[1] 首先备份/etc/yum.repos.d/CentOS-Base.repo mv /etc/yum.repos.d/CentOS-Base.repo /etc/yum.repos.d/Cent ...
- 一步一步配置NLB(续)之深入测试
在这里http://blog.csdn.net/haoxiaozigang1/article/details/12198679跟大家分享了NLB配置的过程,下面写一些对NLB不同情况的下测试的结果: ...
- js方法控制html表格的增加和删除
<!DOCTYPE html> <html> <head> <title>linshi3.html</title> <meta htt ...
- POJ 1850 Code 字符串 难度:1
题意: 1 如果是严格升序的字母字符串,那么可以输出非0解码,否则不能译码输出0 2 字符串解码 遵循递增原则,其值为 到现在为止的所有按字母序小于该字符串的数量 + 1; #include < ...
- nginx不支持pathinfo 导致thinkphp出错解决办法
location / { if (!-e $request_filename) { rewrite ^(.*)$ /index.php?s=$1 last; break; } } 然后项目配置下url ...
- [开发笔记]-FireWorks常用操作快捷键
一.工具快捷键 指针.选择后方对象[V],[0] 部分选定[A],[1] 选取框.椭圆选取框[M] 套索.多边形套索[L] 裁剪.导出区域[C] 魔术棒[W] 线条工具[N] 钢笔工具[P] 矩形.圆 ...
- 第48套题【tarjan】【图&树的连通性】【并查集】
Problem 1 图的连通性
- 解决VS2010控制台程序运行结束不显示请按任意键继续
在VS2010里的控制台应用程序在运行时,结果画面一闪而过,不管是用F5 还是用Ctrl + F5都是一样,导致无法看到结果. 网上有不少的办法,说是都是在程序最后加一个要程序暂停的语句( syste ...
- Linux下screen命令
//1.列出当前的screenscreen -ls //2.新建一个screen,直接在命令行键入screen命令 screen -S [会话名称][root@www.lnuxidc.com ~]# ...