c程序设计语言_习题1-18_删除输入流中每一行末尾的空格和制表符,并删除完全是空格的行
Write a program to remove all trailing blanks and tabs from each line of input, and to delete entirely blank lines.
其实做这道题目有两种思路:
1.后向模式:利用getline()先将输入流中,每一行完全接收,然后从接收的line字符串中末尾,往前扫,直到发现第一个非空格和制表符字符;
2.前向模式:每接收一个字符,都要进行输出、判断。
/* K&R2 1-18 p31: Write a program to remove trailing blanks and tabs
from each line of input, and to delete entirely blank lines. The program specification is ambiguous: does "entirely blank lines"
mean lines that contain no characters other than newline, or does
it include lines composed of blanks and tabs followed by newline?
The latter interpretation is taken here. This implementation does not use any features not introduced in the
first chapter of K&R2. As a result, it can't use pointers to
dynamically allocate a buffer to store blanks that it has seen, so
it must limit the number of blanks that are allowed to occur
consecutively. (This is the value of MAXQUEUE, minus one.) It is intended that this implementation "degrades gracefully."
Even though a particular input might have 1000 or more blanks or
tabs in a row, causing a problem for a single pass, multiple passes
through the file will correct the problem. The program signals the
need for such an additional pass by returning a failure code to the
operating system. (EXIT_FAILURE isn't mentioned in the first
chapter of K&R, but I'm making an exception here.) */ #include <stdio.h>
#include <stdlib.h> #define MAXQUEUE 1001 int advance(int pointer)
{
if (pointer < MAXQUEUE - )
return pointer + ;
else
return ;
} int main(void)
{
char blank[MAXQUEUE];
int head, tail;
int nonspace;
int retval;
int c; retval = nonspace = head = tail = ;
while ((c = getchar()) != EOF) {
if (c == '\n') {
head = tail = ;
if (nonspace)
putchar('\n');
nonspace = ;
}
else if (c == ' ' || c == '\t') {
//能执行这个if,只能说明输入行中字符溢出了。
if (advance(head) == tail) {
putchar(blank[tail]);
tail = advance(tail);
nonspace = ;
retval = EXIT_FAILURE;
}
//只要遇到空格和制表符,就先存起来
blank[head] = c;
head = advance(head);
}
else { //一次性把前面积攒的空格和制表符输出来
while (head != tail) {
putchar(blank[tail]);
tail = advance(tail);
}
putchar(c);
nonspace = ;
}
} return retval;
}
Chris Sidi writes:
Ben, I thought your solution to 1-18 was really neat (it didn't occur to me
when I was doing the exercise), the way it degrades gracefully and
multiple passes can get rid of huge blocks of whitespace. However, if there is a huge block of non-trailing whitespace (eg "A",2000
spaces, "B\n") your program returns an error when there's not a need for
it. And if someone were to use your program till it passes it will loop
infinitely: $ perl -e 'print "A"," "x2000,"B\n";' > in
$ until ./a.out < in > out; do echo failed, running another pass; cp out
in; done
failed, running another pass
failed, running another pass
failed, running another pass
[snip] Below I have added a variable spaceJustPrinted to your program and check
to see if the spaces printed early are trailing. I hope you like the
minor improvement. (Though I can understand if you don't give a [1] :))
[1] expletive deleted - RJH.
/* K&R2 1-18 p31: Write a program to remove trailing blanks and tabs
from each line of input, and to delete entirely blank lines. The program specification is ambiguous: does "entirely blank lines"
mean lines that contain no characters other than newline, or does
it include lines composed of blanks and tabs followed by newline?
The latter interpretation is taken here. This implementation does not use any features not introduced in the
first chapter of K&R2. As a result, it can't use pointers to
dynamically allocate a buffer to store blanks that it has seen, so
it must limit the number of blanks that are allowed to occur
consecutively. (This is the value of MAXQUEUE, minus one.) It is intended that this implementation "degrades gracefully."
Even though a particular input might have 1000 or more trailing
blanks or tabs in a row, causing a problem for a single pass,
multiple passes through the file will correct the problem. The
program signals the need for such an additional pass by returning a
failure code to the operating system. (EXIT_FAILURE isn't mentioned
in the first chapter of K&R, but I'm making an exception here.) */ #include <stdio.h>
#include <stdlib.h> #define MAXQUEUE 1001 int advance(int pointer)
{
if (pointer < MAXQUEUE - )
return pointer + ;
else
return ;
} int main(void)
{
char blank[MAXQUEUE];
int head, tail;
int nonspace;
int retval;
int c;
int spaceJustPrinted; /*boolean: was the last character printed whitespace?*/ retval = spaceJustPrinted = nonspace = head = tail = ; while ((c = getchar()) != EOF) {
if (c == '\n') {
head = tail = ;
if (spaceJustPrinted == ) /*if some trailing whitespace was printed...*/
retval = EXIT_FAILURE; if (nonspace) {
putchar('\n');
spaceJustPrinted = ; /* this instruction isn't really necessary since
spaceJustPrinted is only used to determine the
return value, but we'll keep this boolean
truthful */
nonspace = ; /* moved inside conditional just to save a needless
assignment */
}
}
else if (c == ' ' || c == '\t') {
if (advance(head) == tail) {
putchar(blank[tail]); /* these whitespace chars being printed early
are only a problem if they are trailing,
which we'll check when we hit a \n or EOF */
spaceJustPrinted = ;
tail = advance(tail);
nonspace = ;
} blank[head] = c;
head = advance(head);
}
else {
while (head != tail) {
putchar(blank[tail]);
tail = advance(tail);
}
putchar(c);
spaceJustPrinted = ;
nonspace = ;
}
} /* if the last line wasn't ended with a newline before the EOF,
we'll need to figure out if trailing space was printed here */
if (spaceJustPrinted == ) /*if some trailing whitespace was printed...*/
retval = EXIT_FAILURE; return retval;
}
c程序设计语言_习题1-18_删除输入流中每一行末尾的空格和制表符,并删除完全是空格的行的更多相关文章
- c程序设计语言_习题1-16_自己编写getline()函数,接收整行字符串,并完整输出
Revise the main routine of the longest-line program so it will correctly print the length of arbitra ...
- c程序设计语言_习题7-6_对比两个输入文本文件_输出它们不同的第一行_并且要记录行号
Write a program to compare two files, printing the first line where they differ. Here's Rick's solut ...
- c程序设计语言_习题8-4_重新实现c语言的库函数fseek(FILE*fp,longoffset,intorigin)
fseek库函数 #include <stdio.h> int fseek(FILE *stream, long int offset, int origin); 返回:成功为0,出错 ...
- c程序设计语言_习题8-6_利用malloc()函数,重新实现c语言的库函数calloc()
The standard library function calloc(n,size) returns a pointer to n objects of size size , with the ...
- c程序设计语言_习题1-19_编写函数reverse(s)将字符串s中字符顺序颠倒过来。
Write a function reverse(s) that reverses the character string s . Use it to write a program that re ...
- c程序设计语言_习题1-13_统计输入中单词的长度,并且根据不同长度出现的次数绘制相应的直方图
Write a program to print a histogram of the lengths of words in its input. It is easy to draw the hi ...
- c程序设计语言_习题1-11_学习单元测试,自己生成测试输入文件
How would you test the word count program? What kinds of input are most likely to uncover bugs if th ...
- c程序设计语言_习题1-9_将输入流复制到输出流,并将多个空格过滤成一个空格
Write a program to copy its input to its output, replacing each string of one or more blanks by a si ...
- 如何删除datatable中的一行数据
在C#中,如果要删除DataTable中的某一行,大约有以下几种办法: 1,使用DataTable.Rows.Remove(DataRow),或者DataTable.Rows.RemoveAt(ind ...
随机推荐
- [Guava官方文档翻译] 6. 用Guava辅助Throwable异常处理 (Throwables Explained)
我的技术博客经常被流氓网站恶意爬取转载.请移步原文:http://www.cnblogs.com/hamhog/p/3537508.html ,享受整齐的排版.有效的链接.正确的代码缩进.更好的阅读体 ...
- 九度OJ 1547 出入栈 -- 动态规划
题目地址:http://ac.jobdu.com/problem.php?pid=1547 题目描述: 给定一个初始为空的栈,和n个操作组成的操作序列,每个操作只可能是出栈或者入栈. 要求在操作序列的 ...
- OpenJudge/Poj 2000 Gold Coins
1.链接地址: http://bailian.openjudge.cn/practice/2000 http://poj.org/problem?id=2000 2.题目: 总Time Limit: ...
- 专题三、ArrayList遍历方式以及效率比较
一.遍历方式 ArrayList支持三种遍历方式. 1.第一种,随机访问,它是通过索引值去遍历 由于ArrayList实现了RandomAccess接口,它支持通过索引值去随机访问元素. 代码如下: ...
- Android开发系列之学习路线图
通过前面的3篇博客已经简单的介绍了Android开发的过程并写了一个简单的demo,了解了Android开发的环境以及一些背景知识. 接下来这篇博客不打算继续学习Android开发的细节,先停一下,明 ...
- Memcache存储大数据的问题
Memcached存储单个item最大数据是在1MB内,假设数据超过1M,存取set和get是都是返回false,并且引起性能的问题. 我们之前对排行榜的数据进行缓存,因为排行榜在我们全部sql se ...
- 005.ClearStoredGroups方法
Delphi procedure ClearStoredGroups; 类型:procedure 可见性:protected 所在单元:System.RegularExpressionsCore 父类 ...
- (转载)SQL语句导入导出大全
SQL语句导入导出大全 /******* 导出到excel EXEC master..xp_cmdshell 'bcp SettleDB.dbo.shanghu out c:\temp1.xls -c ...
- Vijos p1165 火烧赤壁 离散化+单调栈
题目链接:https://vijos.org/p/1165 题意:输入n(n <= 20,000)段线段的端点,问所有线段的长度总和为多少? input: -1 1 5 11 2 9 outpu ...
- 【BZOJ】1013: [JSOI2008]球形空间产生器sphere
[BZOJ]1013: [JSOI2008]球形空间产生器sphere 题意:给n+1个n维的点的坐标,要你求出一个到这n+1个点距离相等的点的坐标: 思路:高斯消元即第i个点和第i+1个点处理出一个 ...