Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 8), you are supposed to point out the strictly dominant color.

Input Specification:

Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (≤) and N (≤) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.

Output Specification:

For each test case, simply print the dominant color in a line.

Sample Input:

5 3
0 0 255 16777215 24
24 24 0 0 24
24 0 24 24 24

Sample Output:

24

思路:初始化tmp为0,cnt为0,每次输入一个数与tmp比较如果相同cnt++,否则更新tmp值,因为题意是所求的值总会超过一半数据,所以最后留下来的tmp一定就是目标值。
 #include <stdio.h>
int n,m;
int a[][];
int main()
{
scanf("%d %d",&m,&n);
int tmp=,cnt=;
for(int i=;i<n;i++){
for(int j=;j<m;j++){
scanf("%d",&a[i][j]);
if(a[i][j]==tmp){
cnt++;
}else{
tmp=a[i][j];
cnt=;
}
}
}
printf("%d\n",tmp);
return ;
}

PAT (Advanced Level) Practice 1054 The Dominant Color (20 分)的更多相关文章

  1. PAT (Advanced Level) Practice 1027 Colors in Mars (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1027 Colors in Mars (20 分) 凌宸1642 题目描述: People in Mars represent the c ...

  2. PAT (Advanced Level) Practice 1019 General Palindromic Number (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1019 General Palindromic Number (20 分) 凌宸1642 题目描述: A number that will ...

  3. PAT (Advanced Level) Practice 1011 World Cup Betting (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1011 World Cup Betting (20 分) 凌宸1642 题目描述: With the 2010 FIFA World Cu ...

  4. PAT (Advanced Level) Practice 1005 Spell It Right (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1005 Spell It Right (20 分) 凌宸1642 题目描述: Given a non-negative integer N ...

  5. PAT (Advanced Level) Practice 1001 A+B Format (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1001 A+B Format (20 分) 凌宸1642 题目描述: Calculate a+b and output the sum i ...

  6. PAT (Advanced Level) Practice 1027 Colors in Mars (20 分)

    People in Mars represent the colors in their computers in a similar way as the Earth people. That is ...

  7. PAT (Advanced Level) Practice 1019 General Palindromic Number (20 分) (进制转换,回文数)

    A number that will be the same when it is written forwards or backwards is known as a Palindromic Nu ...

  8. PAT (Advanced Level) Practice 1005 Spell It Right (20 分) (switch)

    Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output e ...

  9. PAT (Advanced Level) Practice 1011 World Cup Betting (20 分) (找最值)

    With the 2010 FIFA World Cup running, football fans the world over were becoming increasingly excite ...

随机推荐

  1. coroutine - yield from

    yield from yield from x 表达式对 x 对象所做的第一件事是,调用 iter(x),从中获取迭代器.因 此, x 可以是任何可迭代的对象. 可是,如果 yield from 结构 ...

  2. 集智学院 “Deep X:Deep Learning with Deep Knowledge”的公开讲座---总结

    人工智能旨在了解人类智能的本质,并创造出能模仿人类智能做出反应的智能机器,目前在一些领域已经取得显著的成功,如AI玩游戏.问答系统.自动驾驶.无人机.机器人.翻译.人脸识别.语音识别等领域.深度学习的 ...

  3. [Linux]命令返回值以及错误对照表

    Linux执行完命令之后默认会有一个返回值 # ls app backupconfig.json Doc manage.py __pycache__ settings.py # echo $? 0 错 ...

  4. python pandas合并多个excel(xls和xlsx)文件(弹窗选择文件夹和保存文件)

    # python pandas合并多个excel(xls和xlsx)文件(弹窗选择文件夹和保存文件) import tkinter as tk from tkinter import filedial ...

  5. Webpack中hash、chunkhash和contenthash三者的区别

    在webpack中有三种的方式生成哈希值,分别为hash.chunkhash和contenthash.这三种方式有着不同的用处,或者说在webpack的不同环境中,会使用不同的方式生成哈希值.那为什么 ...

  6. JVM类加载器是否可以加载自定义的String

    前言 曾经有一次,面试官问到类加载机制,相信大多数小伙伴都可以答上来双亲委派机制,也都知道JVM出于安全性的考虑,全限定类名相同的String是不能被加载的.但是如果加载了,会出现什么样的结果呢?异常 ...

  7. 使用Visual Studio Comunity 2019开发Unity C#脚本没有自动补全的解决方法

    最近开始试着玩Unity3D,要为场景中的物体编辑脚本.Unity3D推荐的脚本语言是C#,在Unity打开C#就会使用Visual Studio来进行编辑. 启动Visual Studio之后注意到 ...

  8. .net core 轻量级容器 ServiceProvider 源码分析

    首先看 ServiceCollection 的定义 //定义 public class ServiceCollection : IServiceCollection { private readonl ...

  9. 解决.net core3.1使用docker部署在Ubuntu上连接sqlserver报error:35的问题

    最近把一个项目从core2.2迁移至core3.1,在本地win上跑没有问题,但是上线到生产Ubuntu docker环境下连接不上sqlserver报以下错误. A connection was s ...

  10. Redis 为什么这么快?

    1. 纯内存操作,肯定快 数据存储在内存中,读取的时候不需要进行磁盘的 IO 2. 单线程,无锁竞争损耗 单线程保证了系统没有线程的上下文切换 使用单线程,可以避免不必要的上下文切换和竞争条件,没有多 ...