Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, ..., N and pop randomly. You are supposed to tell if a given sequence of numbers is a possible pop sequence of the stack. For example, if M is 5 and N is 7, we can obtain 1, 2, 3, 4, 5, 6, 7 from the stack, but not 3, 2, 1, 7, 5, 6, 4.

Input Specification:

Each input file contains one test case. For each case, the first line contains 3 numbers (all no more than 1000): M (the maximum capacity of the stack), N (the length of push sequence), and K (the number of pop sequences to be checked). Then K lines follow, each contains a pop sequence of N numbers. All the numbers in a line are separated by a space.

Output Specification:

For each pop sequence, print in one line "YES" if it is indeed a possible pop sequence of the stack, or "NO" if not.

Sample Input:

5 7 5
1 2 3 4 5 6 7
3 2 1 7 5 6 4
7 6 5 4 3 2 1
5 6 4 3 7 2 1
1 7 6 5 4 3 2

Sample Output:

YES
NO
NO
YES
NO
 #include <iostream>
#include <stack>
using namespace std;
int M, N, K;
int main()
{
cin >> M >> N >> K;
for (int i = ; i < K; ++i)
{
stack<int>s;
int a, b = , flag = ;
for (int j = ; j < N; ++j)
{
cin >> a;
while (s.size() < M && (s.empty() || s.top() != a))
s.push(b++);
if (s.top() == a)
s.pop();
else
flag = ;
}
if (flag == )
cout << "Yes" << endl;
else
cout << "No" << endl;
}
return ;
}

PAT甲级——A1051 Pop Sequence的更多相关文章

  1. PAT 甲级 1051 Pop Sequence

    https://pintia.cn/problem-sets/994805342720868352/problems/994805427332562944 Given a stack which ca ...

  2. PAT 甲级 1051 Pop Sequence (25 分)(模拟栈,较简单)

    1051 Pop Sequence (25 分)   Given a stack which can keep M numbers at most. Push N numbers in the ord ...

  3. A1051. Pop Sequence

    Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, ..., N and p ...

  4. 【PAT】1051 Pop Sequence (25)(25 分)

    Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, ..., N and p ...

  5. PAT Advanced 1051 Pop Sequence (25) [栈模拟]

    题目 Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, -, N and ...

  6. PAT 甲级 1085 Perfect Sequence

    https://pintia.cn/problem-sets/994805342720868352/problems/994805381845336064 Given a sequence of po ...

  7. PAT甲级——A1085 Perfect Sequence

    Given a sequence of positive integers and another positive integer p. The sequence is said to be a p ...

  8. PAT甲级——1140.Look-and-say Sequence (20分)

    Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213 ...

  9. PAT甲级题解分类byZlc

    专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d& ...

随机推荐

  1. 为什么程序员都不喜欢使用switch,而是大量的 if……else if ?

    作者:熊爸爸 原文:http://3g.163.com/tech/article/E02RDE6C0511SDDL.html 请用5秒钟的时间查看下面的代码是否存在bug. OK,熟练的程序猿应该已经 ...

  2. FastJSON实现详解

    摘要:“快”作为程序员追逐的终极目标之一,而FastJSON则很好的证明了这一特性.本期<问底>,静行将带大家见证它序列化和反序列化的实现过程,一起领略它的“快”感. 还记得电影<功 ...

  3. SSH整合时执行hibernate查询报错:java.lang.ClassCastException: com.ch.hibernate.Depart

    今天在整合ssh三个框架时,有一个功能,是查询所有员工信息,且员工表和部门表是多对一的映射关系,代码能正常运行到查询得到一个List集合,但在页面展示的时候,就报异常了, java.lang.Clas ...

  4. HDU-1492-The number of divisors(约数) about Humble Numbers -求因子总数+唯一分解定理的变形

    A number whose only prime factors are 2,3,5 or 7 is called a humble number. The sequence 1, 2, 3, 4, ...

  5. 三种方法实现MNIST 手写数字识别

    MNIST数据集下载: import tensorflow as tf from tensorflow.examples.tutorials.mnist import input_data mnist ...

  6. HTML5 新模块元素兼容问题

    新增块元素默认样式 下列HTML5新模块元素在IE8.9版本浏览器中没有被定义默认样式.为解决该问题,给下列元素添加“block”显示属性. 代码: article, aside, details, ...

  7. Spring - JUnit整合测试

    1.导包:test.jar - (依赖 aop.jar) 2.使用@RunWith注解创建spring容器 - @RunWith(SpringJUnit4ClassRunner.class) 3.使用 ...

  8. 连接 MySQL 报错:Lost connection to MySQL server at 'reading authorization packet', system error: 34

    报错信息: Lost connection to MySQL server at 解决方案: use mysql; ; flush privileges; 参考: https://blog.csdn. ...

  9. windows 内核下获取进程路径

    windows 内核下获取进程路径 思路:1):在EPROCESS结构中获取.此时要用到一个导出函数:PsGetProcessImageFileName,申明如下: NTSYSAPI UCHAR *  ...

  10. leetcode-95-不同的二叉搜索树②*

    题目描述: 方法一:递归 # Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self. ...