【HDOJ】4029 Distinct Sub-matrix

思路是枚举矩阵列数，然后将字符矩阵转换成字符串，通过字符数组求不同子串数目。最后，减去不成立的情况。使用特殊字符分割可能的组合。

 /* 4029 */
 #include <iostream>
 #include <sstream>
 #include <string>
 #include <map>
 #include <queue>
 #include <set>
 #include <stack>
 #include <vector>
 #include <deque>
 #include <algorithm>
 #include <cstdio>
 #include <cmath>
 #include <ctime>
 #include <cstring>
 #include <climits>
 #include <cctype>
 #include <cassert>
 #include <functional>
 #include <iterator>
 #include <iomanip>
 using namespace std;
 //#pragma comment(linker,"/STACK:102400000,1024000")
 
 #define sti                set<int>
 #define stpii            set<pair<int, int> >
 #define mpii            map<int,int>
 #define vi                vector<int>
 #define pii                pair<int,int>
 #define vpii            vector<pair<int,int> >
 #define rep(i, a, n)     for (int i=a;i<n;++i)
 #define per(i, a, n)     for (int i=n-1;i>=a;--i)
 #define clr                clear
 #define pb                 push_back
 #define mp                 make_pair
 #define fir                first
 #define sec                second
 #define all(x)             (x).begin(),(x).end()
 #define SZ(x)             ((int)(x).size())
 #define lson            l, mid, rt<<1
 #define rson            mid+1, r, rt<<1|1
 
 const int maxr = ;
 const int maxn = 2e5+;
 const int base = ;
 map<int,int> tb;
 int a[maxn*];
 int height[maxn], rrank[maxn], sa[maxn*];
 int wa[maxn], wb[maxn], wc[maxn], wv[maxn];
 char s[maxr][maxr];
 int H[maxr][maxr];
 int r, c;
 
 bool c0(int *r, int a, int b) {
     return r[a]==r[b] && r[a+]==r[b+] && r[a+]==r[b+];
 }
 
 bool c12(int k, int *r, int a, int b) {
     if (k == )
         return r[a]<r[b] || (r[a]==r[b] && c12(, r, a+, b+));
     else
         return r[a]<r[b] || (r[a]==r[b] && wv[a+]<wv[b+]);
 }
 
 void sort(int *r, int *a, int *b, int n, int m) {
     int i;
 
     for (i=; i<n; ++i) wv[i] = r[a[i]];
     for (i=; i<m; ++i) wc[i] = ;
     for (i=; i<n; ++i) wc[wv[i]]++;
     for (i=; i<m; ++i) wc[i] += wc[i-];
     for (i=n-; i>=; --i) b[--wc[wv[i]]] = a[i];
 }
 
 #define F(x) ((x)/3 + ((x)%3==1 ? 0:tb))
 #define G(x) ((x)<tb ? (x)*3+1 : ((x)-tb)*3+2)
 void dc3(int *r, int *sa, int n, int m) {
     int i, j, *rn=r+n, *san=sa+n, ta=, tb=(n+)/, tbc=, p;
 
     r[n] = r[n+] = ;
     for (i=; i<n; ++i) if (i%!=) wa[tbc++] = i;
     sort(r+, wa, wb, tbc, m);
     sort(r+, wb, wa, tbc, m);
     sort(r, wa, wb, tbc, m);
     for (p=, rn[F(wb[])]=, i=; i<tbc; ++i)
         rn[F(wb[i])] = c0(r, wb[i-], wb[i]) ? p- : p++;
     if (p < tbc)
         dc3(rn, san, tbc, p);
     else
         for (i=; i<tbc; ++i) san[rn[i]] = i;
     for (i=; i<tbc; ++i)
         if (san[i] < tb)
             wb[ta++] = san[i] * ;
     if (n% == )
         wb[ta++] = n - ;
     sort(r, wb, wa, ta, m);
     for (i=; i<tbc; ++i) wv[wb[i]=G(san[i])] = i;
     for (i=,j=,p=; i<ta && j<tbc; ++p)
         sa[p] = c12(wb[j]%, r, wa[i], wb[j]) ? wa[i++] : wb[j++];
     while (i < ta) sa[p++] = wa[i++];
     while (j < tbc) sa[p++] = wb[j++];
 }
 
 void calheight(int *r, int *sa, int n) {
     int i, j, k = ;
 
     for (i=; i<=n; ++i) rrank[sa[i]] = i;
     for (i=; i<n; height[rrank[i++]]=k)
     for (k?k--:, j=sa[rrank[i]-]; r[j+k]==r[i+k]; ++k) ;
 }
 
 void printSa(int n) {
     for (int i=; i<=n; ++i)
         printf("%d ", sa[i]);
     putchar('\n');
 }
 
 void printHeight(int n) {
     for (int i=; i<=n; ++i)
         printf("%d ", height[i]);
     putchar('\n');
 }
 
 void solve() {
     __int64 ans = , tot, tmp;
     int n = ;
 
     memset(H, , sizeof(H));
     rep(w, , c+) {
         tb.clr();
         int cn = c - w + ;
         int cnt = cn + ;
         int sidx = ;
 
         rep(i, , r) {
             rep(j, , cn) {
                 H[i][j] = H[i][j] * base + s[i][j+w-]-'A';
                 if (tb.find(H[i][j]) == tb.end())
                     tb[H[i][j]] = cnt++;
             }
         }
 
         n = ;
         rep(j, , cn) {
             rep(i, , r)
                 a[n++] = tb[H[i][j]];
             a[n++] = sidx++;
         }
         a[n] = ;
 
         dc3(a, sa, n+, cnt+);
         calheight(a, sa, n);
 
         tot = ;
         rep(i, , n+)
             tot += (n - sa[i] - height[i]);
 
         tmp = n;
         rep(i, , cn) {
             tmp -= r;
             tot -= (r+) * tmp;
             --tmp;
         }
 
         ans += tot;
     }
 
     printf("%I64d\n", ans);
 }
 
 int main() {
     ios::sync_with_stdio(false);
     #ifndef ONLINE_JUDGE
         freopen("data.in", "r", stdin);
         freopen("data.out", "w", stdout);
     #endif
 
     int t;
 
     scanf("%d", &t);
     rep(tt, , t+) {
         scanf("%d %d", &r, &c);
         rep(i, , r)
             scanf("%s", s[i]);
         printf("Case #%d: ", tt);
         solve();
     }
 
     #ifndef ONLINE_JUDGE
         printf("time = %d.\n", (int)clock());
     #endif
 
     return ;
 }

数据生成器。

 from random import randint, shuffle
 import shutil
 import string
 
 def GenDataIn():
     with open("data.in", "w") as fout:
         t = 20
         uc = list(string.uppercase)
         fout.write("%d\n" % (t))
         for tt in xrange(t):
             n = randint(20, 50)
             m = randint(20, 50)
             fout.write("%d %d\n" % (n, m))
             for i in xrange(n):
                 line = ""
                 for j in xrange(m):
                     idx = randint(0, 25)
                     line += uc[idx]
                 fout.write("%s\n" % (line))
 
 def MovDataIn():
     desFileName = "F:\eclipse_prj\workspace\hdoj\data.in"
     shutil.copyfile("data.in", desFileName)
 
 if __name__ == "__main__":
     GenDataIn()
     MovDataIn()