【Codeforces 711C】Coloring Trees
【链接】 我是链接,点我呀:)
【题意】
连续相同的数字分为一段
你可以改变其中0为1~m中的某个数字(改变成不同数字需要不同花费)
问你最后如果要求分成恰好k段的话,最少需要多少花费
【题解】
dp[i][j][k]前i棵树,分成j段,第j段最后一棵树颜色为m的最小花费
很好转移了,分情况就好
【代码】
import java.io.*;
import java.util.*;
public class Main {
static InputReader in;
static PrintWriter out;
public static void main(String[] args) throws IOException{
//InputStream ins = new FileInputStream("E:\\rush.txt");
InputStream ins = System.in;
in = new InputReader(ins);
out = new PrintWriter(System.out);
//code start from here
new Task().solve(in, out);
out.close();
}
static int N = 100;
static class Task{
int n,m,k;
long dp[][][] = new long[N+10][N+10][N+10];
int p[][] = new int[N+10][N+10];
int c[] = new int[N+10];
//dp[i][j][k]前i棵树,分成j段,第j段最后一棵树颜色为m的最小花费
public void solve(InputReader in,PrintWriter out) {
n = in.nextInt(); m = in.nextInt();k = in.nextInt();
for (int i = 1;i <= n;i++) c[i] = in.nextInt();
for (int i = 1;i <= n;i++)
for (int j = 1;j <= m;j++)
p[i][j] = in.nextInt();
for (int i = 0;i <=N;i++)
for (int j = 0;j <= N;j++)
for(int k = 0;k <=N;k++)
dp[i][j][k] = -1;
if (c[1]==0) {
for (int j = 1;j <= m;j++) {
dp[1][1][j] = p[1][j];
}
}else {
dp[1][1][c[1]] = 0;
}
for (int i = 1;i < n;i++)
for (int j = 1;j <= k;j++)
for (int l = 1;l <= m;l++) {
if (dp[i][j][l]!=-1) {
if(c[i+1]==0) {
for (int l2=1;l2<=m;l2++) {
long temp = dp[i][j][l] + p[i+1][l2];
if (l2==l){
if (dp[i+1][j][l2]==-1) {
dp[i+1][j][l2] = temp;
}else {
dp[i+1][j][l2] = Math.min(dp[i+1][j][l2],temp);
}
}else {
if (dp[i+1][j+1][l2]==-1) {
dp[i+1][j+1][l2] = temp;
}else {
dp[i+1][j+1][l2] = Math.min(dp[i+1][j+1][l2], temp);
}
}
}
}else {
//c[i+1]=x
if (c[i+1]==l) {
if (dp[i+1][j][l]==-1) {
dp[i+1][j][l] = dp[i][j][l];
}else {
dp[i+1][j][l] = Math.min(dp[i+1][j][l], dp[i][j][l]);
}
}else {
if (dp[i+1][j+1][c[i+1]]==-1) {
dp[i+1][j+1][c[i+1]] = dp[i][j][l];
}else {
dp[i+1][j+1][c[i+1]] = Math.min(dp[i+1][j+1][c[i+1]], dp[i][j][l]);
}
}
}
}
}
//dp[n][k][1~m]
long ma = -1;
for (int i = 1;i <= m;i++)
if (dp[n][k][i]!=-1) {
if (ma==-1)
ma = dp[n][k][i];
else
ma = Math.min(ma, dp[n][k][i]);
}
out.println(ma);
}
}
static class InputReader{
public BufferedReader br;
public StringTokenizer tokenizer;
public InputReader(InputStream ins) {
br = new BufferedReader(new InputStreamReader(ins));
tokenizer = null;
}
public String next(){
while (tokenizer==null || !tokenizer.hasMoreTokens()) {
try {
tokenizer = new StringTokenizer(br.readLine());
}catch(IOException e) {
throw new RuntimeException(e);
}
}
return tokenizer.nextToken();
}
public int nextInt() {
return Integer.parseInt(next());
}
}
}
【Codeforces 711C】Coloring Trees的更多相关文章
- codeforces 711C C. Coloring Trees(dp)
题目链接: C. Coloring Trees time limit per test 2 seconds memory limit per test 256 megabytes input stan ...
- 【codeforces 415D】Mashmokh and ACM(普通dp)
[codeforces 415D]Mashmokh and ACM 题意:美丽数列定义:对于数列中的每一个i都满足:arr[i+1]%arr[i]==0 输入n,k(1<=n,k<=200 ...
- 【42.07%】【codeforces 558A】Lala Land and Apple Trees
time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...
- 【27.91%】【codeforces 734E】Anton and Tree
time limit per test3 seconds memory limit per test256 megabytes inputstandard input outputstandard o ...
- 【codeforces 755C】PolandBall and Forest
time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...
- 【codeforces 750F】New Year and Finding Roots
time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard o ...
- 【22.73%】【codeforces 606D】Lazy Student
time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard o ...
- 【codeforces 707E】Garlands
[题目链接]:http://codeforces.com/contest/707/problem/E [题意] 给你一个n*m的方阵; 里面有k个联通块; 这k个联通块,每个连通块里面都是灯; 给你q ...
- 【codeforces 707C】Pythagorean Triples
[题目链接]:http://codeforces.com/contest/707/problem/C [题意] 给你一个数字n; 问你这个数字是不是某个三角形的一条边; 如果是让你输出另外两条边的大小 ...
随机推荐
- 移动端html touch事件
诸如智能手机和平板电脑一类的移动设备通常会有一(capacitive touch-sensitivescreen),以捕捉用户的手指所做的交互.随着移动网络的发展,其能够支持越来越复杂的应用,web开 ...
- MySQL基础 — 详细安装
MySQL--安装 打开MySQL 5.5 安装文件开始: 点击Next 打上勾,再点击Next 点击Custom,说明如下: Typical(典型安装) Installs the mo ...
- [App Store Connect帮助]六、测试 Beta 版本(3.1)管理测试员:添加内部测试员
您可以添加至多 25 个内部测试员(您的 App Store Connect 用户)使用“TestFlight Beta 版测试”来测试您的 App.在您上传了至少一个构建版本之后,才可添加测试员. ...
- 【题解】TES-Intelligence Test
[题解]\(TES-Intelligence\) \(Test\) 逼自己每天一道模拟题 传送:\(TES-Intelligence\) \(Test\) \([POI2010]\) \([P3500 ...
- printf的整型
参 数 说 明 %d 输出数字长为变量数值的实际长度 %md 输出m位(不足补空格,大于m位时按实际长度输出) %-md m含义同上.左对齐输出 %ld l(小写字母)表示输出“长整型”数据 %m1 ...
- 类似QQ消息左滑删除的Demo
最近在网上学到一篇类似QQ消息左滑删除的demo,完善了下代码,感觉还不错,特此分享一波: CustomSwipeListView.java 是个继承自ListView的类,里面调用了自定义View ...
- opencv总结
2018-02-2623:59:02 唉,这软件我很烦躁,今天又搞了好几遍,出错提示的时候总是出问题! 而且,无论什么错误,都是提示一堆乱码! 定义ROI区域有两种方法,第一种是使用cv:Rect.顾 ...
- karma+requirejs+angular 测试
http://karma-runner.github.io/0.8/plus/RequireJS.html karma 不是测试框架,只是一个运行测试框架的服务器 karma测试的原理是,将所有的文件 ...
- UIPageViewController 翻页、新手引导--UIScrollView:pagingEnabled
UIPageViewController 翻页.新手引导--UIScrollView:pagingEnabled
- dwarfdump --arch=arm64 --lookup
解析友盟错误信息重要指令: dwarfdump --arch=arm64 --lookup 0x1001edbc4 /Users/zhoujunbo/Library/Developer/Xcode/A ...