hdu 1022 Train Problem I【模拟出入栈】
Train Problem I
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 53352 Accepted Submission(s): 20006
Problem Description
As the new term comes, the Ignatius Train Station is very busy nowadays. A lot of student want to get back to school by train(because the trains in the Ignatius Train Station is the fastest all over the world ^v^). But here comes a problem, there is only one railway where all the trains stop. So all the trains come in from one side and get out from the other side. For this problem, if train A gets into the railway first, and then train B gets into the railway before train A leaves, train A can't leave until train B leaves. The pictures below figure out the problem. Now the problem for you is, there are at most 9 trains in the station, all the trains has an ID(numbered from 1 to n), the trains get into the railway in an order O1, your task is to determine whether the trains can get out in an order O2.
Input
The input contains several test cases. Each test case consists of an integer, the number of trains, and two strings, the order of the trains come in:O1, and the order of the trains leave:O2. The input is terminated by the end of file. More details in the Sample Input.
Output
The output contains a string "No." if you can't exchange O2 to O1, or you should output a line contains "Yes.", and then output your way in exchanging the order(you should output "in" for a train getting into the railway, and "out" for a train getting out of the railway). Print a line contains "FINISH" after each test case. More details in the Sample Output.
Sample Input
3 123 321
3 123 312
Sample Output
Yes.
in
in
in
out
out
out
FINISH
No.
FINISH
Hint
Hint For the first Sample Input, we let train 1 get in, then train 2 and train 3. So now train 3 is at the top of the railway, so train 3 can leave first, then train 2 and train 1. In the second Sample input, we should let train 3 leave first, so we have to let train 1 get in, then train 2 and train 3. Now we can let train 3 leave. But after that we can't let train 1 leave before train 2, because train 2 is at the top of the railway at the moment. So we output "No.".
Author
Ignatius.L
就是要判断这样的入栈顺序能否可以的出那样的出栈顺序。
AC代码如下:
//1022
#include<stdio.h>
#include<string.h>
int main()
{
int n;
while(scanf("%d",&n)!=EOF)
{
char in[10],out[10],s[10]; //in:入栈顺序 out:出栈顺序 s:栈
int p[1000],top=0,i=0,j=0,k=0; //p:记录出入栈情况
scanf("%s %s",in,out);
//printf("%d\n%s\n%s\n",n,in,out);
while(i<=n)
{
if(k>0&&s[k-1]==out[j])
{
k--;
j++;
p[top]=0;
top++;
}
else
{
s[k]=in[i];
p[top]=1;
top++;
k++;
i++;
}
}
if(j>=n)
{
printf("Yes.\n");
for(i=0;i<top-1;i++)
{
if(p[i]==1)
printf("in\n");
else
printf("out\n");
}
printf("FINISH\n");
}
else
printf("No.\nFINISH\n");
}
return 0;
}
---------------------
作者:yongtaozheng
来源:CSDN
原文:https://blog.csdn.net/Twinkle_sone/article/details/95165762
版权声明:本文为博主原创文章,转载请附上博文链接!
hdu 1022 Train Problem I【模拟出入栈】的更多相关文章
- HDU 1022 Train Problem I 模拟栈题解
火车进站,模拟一个栈的操作,额外的栈操作,查看能否依照规定顺序出栈. 数据量非常少,故此题目非常easyAC. 直接使用数组模拟就好. #include <stdio.h> const i ...
- HDU - 1022 Train Problem I STL 压栈
Train Problem I Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- HDOJ/HDU 1022 Train Problem I(模拟栈)
Problem Description As the new term comes, the Ignatius Train Station is very busy nowadays. A lot o ...
- HDU 1022 Train Problem I (数据结构 —— 栈)
Problem Description As the new term comes, the Ignatius Train Station is very busy nowadays. A lot o ...
- HDU 1022 Train Problem I(栈的操作规则)
传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1022 Train Problem I Time Limit: 2000/1000 MS (Java/Ot ...
- hdu 1022 Train Problem I(栈的应用+STL)
Train Problem I Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- Hdu 1022 Train Problem I 栈
Train Problem I Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- HDU 1022.Train Problem I【栈的应用】【8月19】
Train Problem I Problem Description As the new term comes, the Ignatius Train Station is very busy n ...
- hdu 1022:Train Problem I(数据结构,栈,递归,dfs)
Train Problem I Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)T ...
随机推荐
- gj的交换机在升级了ios之后最新数据不刷新,
下午2点开始升级5点结束,之后监控项获取不到最新数据,显示网络接口一直是down的状态,但是登上设备之后显示的是正常up状态, 怀疑是自动发现规则的问题,但是查看之后都是1个小时,应该不会, 这时候诡 ...
- ipcs
用于报告Linux中进程间通信设施的状态,显示的信息包括消息列表.共享内存和信号量的信息
- Linux 系统管理——账号管理
一.用户账号管理 1.用户账户概述 用户账户的常见分类: 超级用户:root uid=0 gid=0 权限最大 普通用户:uid>=500 做一般权限的系统管理,权限有限. 程序用户:1 ...
- 回归模型的性能评价指标(Regression Model Performance Evaluation Metric)
回归模型的性能评价指标(Performance Evaluation Metric)通常有: 1. 平均绝对误差(Mean Absolute Error, MAE):真实目标y与估计值y-hat之间差 ...
- c博客作业-我的第一篇博客
1.你对网络专业或者计算机专业了解是怎样的? 以前接触计算机,只是把它当作娱乐的工具,并没有太过了解,现在我通过查阅了解了一些计算机的知识. 计算机专业的学生要学习的不仅是会使用,而且要学习计算机的基 ...
- Hadoop综合大作业总评
作业来源:https://edu.cnblogs.com/campus/gzcc/GZCC-16SE1/homework/3363 1.把python爬取的数据传到linux 2.把数据的逗号代替为 ...
- 第09组 Beta冲刺(4/4)
队名:软工9组 组长博客:https://www.cnblogs.com/cmlei/ 作业博客:https://edu.cnblogs.com/campus/fzu/SoftwareEngineer ...
- 运行OpenGL红宝书第9版源码时Visual Studio提示“无法启动程序...ALL_BUILD。拒绝访问“的问题的解决办法
问题描述: OpenGL红宝书第9版源码采用CMake编译后,用相应的Visual Studio(如VS2012)打开“vermilion9.sln”解决方案,并运行时Visual Studio提示“ ...
- HTTP、MQTT、Websocket、WebService区别
相同点: HTTP.MQTT.Websocket均为OSI 7层模型的[应用层协议]注意. WebService并非通信协议,而是一种远程接口调用(RPC)的框架技术. 不同点: MQTT MQTT协 ...
- SQLServer charindex函数, 查 某个字符 或 某个字符串 在 另一个字符串中的位置
一:charindex()语法 CHARINDEX ( expression1 , expression2 [ , start_location ] ) 解析: expression1 必需 ---要 ...