冒泡排序

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冒泡排序是比较简单的排序方法,它的思路是重复的走过要排序的序列,一次比较两个元素,如果顺序错误,就交换元素的位置,直到没有元素需要交换位置。

原 始 6 1 8 5 9 7
第一次 1 6 8 5 9 7
第二次 1 6 8 5 9 7
第三次 1 6 5 8 9 7
第四次 1 6 5 8 9 7
第五次 1 6 5 8 7 9

……

第N次 1 5 6 7 8 9

代码实现:

1.lst = [6,1,8,5,9,7]
2.for i in range(len(lst)-1):
3. for j in range(len(lst)-1):
4. if lst[j] > lst[j+1]:
5. tmp = lst[j]
6. lst[j] = lst[j+1]
7. lst[j+1] = tmp
8.print lst


选择排序

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" alt="" longdesc="http://www.cnblogs.com/resn/p/__SVG__undefined" width="133.984" height="23.9844" />

选择排序是从等待排序的数组里选择一个最小(或者最大)的元素,拿出来放入新的数组,直到取出全部元素。

原 始 6 1 8 5 9 7 3
第一次 1 6 8 5 9 7 3
第二次 1 3 8 5 9 7 6
第三次 1 3 5 8 9 7 6
第四次 1 3 5 6 9 7 8
第五次 1 3 5 6 7 9 8
第六次 1 3 5 6 7 8 9

每一次排序后最小的数组放在已排序的序列的最后

实现代码

1.lst = [6,1,8,5,9,7,3]
2.for i in range(len(lst)):
3. tmp = lst[i]
4. pos = i
5. for j in range(i+1,len(lst)):
6. if tmp > lst[j]:
7. tmp = lst[j]
8. pos = j
9. a_tmp = lst[i]
10. lst[i] = tmp
11. lst[pos] = a_tmp
12.
13.print lst


插入排序

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" 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插入排序是一种简单直观的排序算法,原理是通过构建有序序列,对于未排序的数据,在已排序的序列中从后想前扫描,找到相应位置后插入。插入排序通常采用in-place排序,即 只需要用到O(1) 的额外空间的排序。

算法描述:

  1. 从第一个元素开始,记该元素已经排序,
  2. 获取下一个元素作为新元素,在已经排序的序列中,从后向前扫描
  3. 如果该元素(已排序的序列中的元素)大于新元素,,则将该元素移到下一位置
  4. 重复步骤3, 直到找到已排序的元素小雨或等于新元素的位置
  5. 将心元素插入该位置
  6. 重复步骤2 ~步骤5 ,直到排序完成

在排序时,如果元素比较的操作代价比较大,可以采用二分查找,来减少操作。 
实现代码:

1.lst = [6,1,8,5,9,7,2,4,6,9,2,32,45,76,8,3,3,4]
2.
3.for i in range(len(lst)):
4. for j in range(i,0,-1):
5. if lst[j-1] >lst[j]:
6. tmp = lst[j-1]
7. lst[j-1] = lst[j]
8. lst[j] = tmp


快速排序 quick sort

又称 划分交换排序;排序n个元素,需要Ο(n log n)次比较 ,最坏情况时需要,Ο(n2)次比较,但这种状况并不常见。

设 有序列 lst = [3,0,1,8,7,2,5,4,9,6] , i= 0 j=9 k = lst[0]

0 1 2 3 4 5 6 7 8 9
3 0 1 8 7 2 5 4 9 6
2 0 1 8 7 3 5 4 9 6
2 0 1 3 7 8 5 4 9 6
2 0 1 3 7 8 5 4 9 6
  1. 以3为基准,从右向左找比 3 小的值 ,j–
  2. 找到第一个小于三的数字2, lst[i] lst[j]交换位置;
  3. 从左向右找第一大于3的数字 8 ,交换 lst[i] lst[j]位置 i++

    1. 继续从右向左找比3小的数字,直到 i==j 此时第一趟 完成,3的当前位置为正确位置
  4. 此时大序列可分为两个小序列 
    sub_lst_01 = [2,0,1] 
    sub_lst_01 = [7,8,5,4,9,6] 
    按照第一趟排序的规则 对两个子序列进行排序,直到所有子序列长度为1。
2 0 1
1 0 2

以2为基准,从右向左找比2小的值,找到数字1 比2小,交换两者位置 
此时从左向右找比2大的数字,未找到,2的位置为排序后的正确位置

1 0
0 1

以1为基准,从右向左找比1小的数字,找到0比1小,交换两者位置 
从左向右找比1 大的数字,未找到,1的位置为排序后的正确位置 
0| 
-| 
此时序列只剩0 ,长度为1 ,0 的位置为排序后的正确位置

7 8 5 4 9 6
6 8 5 4 9 7
6 7 5 4 9 8
6 4 5 7 9 8
. . . . . .
5 4 6 . 8 9
5 4 . . . .
4 5 6 7 8 9
  1. 以7为基准,从右向左找到比7小的数字6,交换两者位置
  2. 从左向右查找到比7大的数字8 交换两者位置
  3. 从右向左找到比7小的数字4,交换两者位置
  4. 从左向右查找到比7大的数字,未找到,则7的位置为排序后的正确位置 
    产生两个子序列 [6,4,5] [8,9]

重复以上操作,直到所有的序列排序完成。

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