7. If you want to carry on a long-running task, what do you need to do?

IntentService;Service

Service:执行的操作,依然是在UI线程中执行;如果是耗时的操作,或者是阻塞的操作,那么,会阻塞UI线程,造成ANR现象的出现。

A Service is an application component representing either an application's desire to perform a longer-running operation while not interacting with the user or to supply functionality for other applications to use. Each service class must have a corresponding <service> declaration in its package's AndroidManifest.xml. Services can be started with Context.startService() and Context.bindService().

Note that services, like other application objects, run in the main thread of their hosting process. This means that, if your service is going to do any CPU intensive (such as MP3 playback) or blocking (such as networking) operations, it should spawn its own thread in which to do that work. More information on this can be found in Processes and Threads. The IntentService class is available as a standard implementation of Service that has its own thread where it schedules its work to be done.

IntentService: 会创建一个自己的独立线程,区别于UI线程。这样,任何耗时的操作,都可以通过IntentService来实现。

IntentService is a base class for Services that handle asynchronous requests (expressed as Intents) on demand. Clients send requests through startService(Intent) calls; the service is started as needed, handles each Intent in turn using a worker thread, and stops itself when it runs out of work.

This "work queue processor" pattern is commonly used to offload tasks from an application's main thread. The IntentService class exists to simplify this pattern and take care of the mechanics. To use it, extend IntentService and implement onHandleIntent(Intent). IntentService will receive the Intents, launch a worker thread, and stop the service as appropriate.

All requests are handled on a single worker thread -- they may take as long as necessary (and will not block the application's main loop), but only one request will be processed at a time.

IntentService的源码:
在使用的时候,只需要定义一个构造函数,提供一个Name;然后,重写onHandleIntent(Intent)方法,在该方法中,可以写上耗时操作,会导致阻塞的操作。
然后,就可以了。按照使用Service那样使用。但是,耗时操作时放到onHandleIntent(Intent)中。
因为,该方法是在独立线程中执行的,不会影响到UI线程。
-----从下面IntentService的实现可知。
-----如果,有多个耗时操作的执行请求,发送给该IntentService来执行,那么,如何处理呢?
因为,只是创建了一个IntentService,对应只是创建了一个Thread;每次发出执行请求,
系统都会回调该方法:
@Override
public void onStart(Intent intent, int startId) {
super.onStart(intent, startId);
Message msg = mServiceHandler.obtainMessage();
msg.arg1 = startId;
msg.obj = intent;
mServiceHandler.sendMessage(msg);
}
也就是,每个执行请求(Intent),变成了每个Message。

每个Message的实际处理,由派生类中的onHandleIntent方法来执行。
所以,即使有多个耗时操作的执行请求,但是每次该IntentService每次只执行一个耗时操作。

IntentService的源码:

package android.app;
import android.content.Intent;
import android.os.Handler;
import android.os.HandlerThread;
import android.os.IBinder;
import android.os.Looper;
import android.os.Message;

/**
* An abstract {@link Service} that serializes the handling of the Intents passed upon service
* start and handles them on a handler thread.
*
* <p>To use this class extend it and implement {@link #onHandleIntent}. The {@link Service} will
* automatically be stopped when the last enqueued {@link Intent} is handled.
*/
public abstract class IntentService extends Service {
private volatile Looper mServiceLooper;
private volatile ServiceHandler mServiceHandler;
private String mName;

private final class ServiceHandler extends Handler {
public ServiceHandler(Looper looper) {
super(looper);
}

@Override
public void handleMessage(Message msg) {
onHandleIntent((Intent)msg.obj);
stopSelf(msg.arg1);
}
}

public IntentService(String name) {
super();
mName = name;
}

@Override
public void onCreate() {
super.onCreate();
HandlerThread thread = new HandlerThread("IntentService[" + mName + "]");
thread.start();

mServiceLooper = thread.getLooper();
mServiceHandler = new ServiceHandler(mServiceLooper);
}

@Override
public void onStart(Intent intent, int startId) {
super.onStart(intent, startId);
Message msg = mServiceHandler.obtainMessage();
msg.arg1 = startId;
msg.obj = intent;
mServiceHandler.sendMessage(msg);
}

@Override
public void onDestroy() {
mServiceLooper.quit();
}

@Override
public IBinder onBind(Intent intent) {
return null;
}

/**
* Invoked on the Handler thread with the {@link Intent} that is passed to {@link #onStart}.
* Note that this will be invoked from a different thread than the one that handles the
* {@link #onStart} call.
*/
protected abstract void onHandleIntent(Intent intent);
}

IntentServicce;Looper;long-running task的更多相关文章

  1. get running task , process and service

    public class MyActivityManager extends ExpandableListActivity { private static final String NAME = & ...

  2. How to:Aborting a long running task in TPL

    http://social.msdn.microsoft.com/Forums/vstudio/en-US/d0bcb415-fb1e-42e4-90f8-c43a088537fb/aborting- ...

  3. asp.net web api long running task

    http://stackoverflow.com/questions/17577016/long-running-task-in-webapi http://blog.stephencleary.co ...

  4. C#并行编程-Task

    菜鸟学习并行编程,参考<C#并行编程高级教程.PDF>,如有错误,欢迎指正. 目录 C#并行编程-相关概念 C#并行编程-Parallel C#并行编程-Task C#并行编程-并发集合 ...

  5. 【转】【C#】【Thread】【Task】多线程

    多线程 多线程在4.0中被简化了很多,仅仅只需要用到System.Threading.Tasks.::.Task类,下面就来详细介绍下Task类的使用. 一.简单使用 开启一个线程,执行循环方法,返回 ...

  6. TaskTracker任务初始化及启动task源码级分析

    在监听器初始化Job.JobTracker相应TaskTracker心跳.调度器分配task源码级分析中我们分析的Tasktracker发送心跳的机制,这一节我们分析TaskTracker接受JobT ...

  7. 【Hadoop代码笔记】Hadoop作业提交之TaskTracker获取Task

    一.概要描述 在上上一篇博文和上一篇博文中分别描述了jobTracker和其服务(功能)模块初始化完成后,接收JobClient提交的作业,并进行初始化.本文着重描述,JobTracker如何选择作业 ...

  8. Hadoop作业提交之TaskTracker获取Task

    [Hadoop代码笔记]Hadoop作业提交之TaskTracker获取Task 一.概要描述 在上上一篇博文和上一篇博文中分别描述了jobTracker和其服务(功能)模块初始化完成后,接收JobC ...

  9. Task Cancellation: Parallel Programming

    http://beyondrelational.com/modules/2/blogs/79/posts/11524/task-cancellation-parallel-programming-ii ...

随机推荐

  1. P4语法(1)基础数据类型和Header

    文章学习自:P4语言编程详解 由于原文有一点的年份,所以也继续阅读了相关的最新规范. P4语言规范 基础数据类型 布尔型(bool) 运算符 描述 and 双目运算符,结果为布尔型 or 双目运算符, ...

  2. C的强制转换和C++的强制转换(转)

    C的强制转换: (type)<expression> 其中,type为类型描述符,如int,float等.<expression>为表达式.经强制类型转换运算符运算后,返回一个 ...

  3. window 安装 nvm

    下载地址 https://github.com/coreybutler/nvm-windows/releases 设置淘宝镜像 nvm node_mirror https://npm.taobao.o ...

  4. 判断form表单每个input字段是否有内容

    //---------------------------------------------------input失去焦点时判断是否有值 btn_click: function () { //inp ...

  5. poj 1274 The Perfect Stall (二分匹配)

    The Perfect Stall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 17768   Accepted: 810 ...

  6. 转:使用 python Matplotlib 库 绘图 及 相关问题

     使用 python Matplotlib 库绘图      转:http://blog.csdn.net/daniel_ustc/article/details/9714163 Matplotlib ...

  7. [bzoj3712][PA2014]Fiolki

    description 题面 data range \[ 0\le m<n\le 200000,0\le k\le 500000\] solution 之前本人一直煞笔地思考暴力是否可行 考虑按 ...

  8. [CF622F]The Sum of the k-th Powers

    题目大意:给你$n,k(n\leqslant10^9,k\leqslant10^6)$,求:$$\sum\limits_{i=1}^ni^k\pmod{10^9+7}$$ 题解:可以猜测是一个$k+1 ...

  9. usaco中遇到的问题

    numbers are integers with unique digits 意思是数字中的每一个数字都是不一样的& 让一个图成为强连通图只需添加max(出度为0,入度为0)的点,然后如果图 ...

  10. SPOJ - PHRASES

    题意: 给n个字符串,求出最长的子串.使得子串在每个字符串中不重叠地至少出现2次.输出子串长度. 题解: 用后缀数组求出height数组,之后二分答案.check时对height数组进行分组,并维护每 ...