CF816B Karen and Coffee
思路:
有点类似于区间修改点查询的树状数组。
实现:
#include <iostream>
#include <cstdio>
using namespace std; const int MAXN = ;
int a[MAXN], n, k, q; int main()
{
cin >> n >> k >> q;
for (int i = ; i < n; i++)
{
int l, r;
scanf("%d %d", &l, &r);
a[l]++; a[r + ]--;
}
for (int i = ; i < MAXN; i++) a[i] += a[i - ];
for (int i = ; i < MAXN; i++)
if (a[i] >= k) a[i] = ;
else a[i] = ;
for (int i = ; i < MAXN; i++) a[i] += a[i - ];
for (int i = ; i < q; i++)
{
int l, r;
scanf("%d %d", &l, &r);
printf("%d\n", a[r] - a[l - ]);
}
return ;
}
CF816B Karen and Coffee的更多相关文章
- B. Karen and Coffee
B. Karen and Coffee time limit per test 2.5 seconds memory limit per test 512 megabytes input standa ...
- CodeForces 816B Karen and Coffee(前缀和,大量查询)
CodeForces 816B Karen and Coffee(前缀和,大量查询) Description Karen, a coffee aficionado, wants to know the ...
- codeforces round #419 B. Karen and Coffee
To stay woke and attentive during classes, Karen needs some coffee! Karen, a coffee aficionado, want ...
- Karen and Coffee CodeForces - 816B (差分数组+预处理前缀和)
To stay woke and attentive during classes, Karen needs some coffee! Karen, a coffee aficionado, want ...
- Codeforces Round #419 (Div. 2) B. Karen and Coffee
To stay woke and attentive during classes, Karen needs some coffee! Karen, a coffee aficionado, want ...
- Codeforces816B Karen and Coffee 2017-06-27 15:18 39人阅读 评论(0) 收藏
B. Karen and Coffee time limit per test 2.5 seconds memory limit per test 512 megabytes input standa ...
- Codeforces Round #419 (Div. 2) B. Karen and Coffee(经典前缀和)
http://codeforces.com/contest/816/problem/B To stay woke and attentive during classes, Karen needs s ...
- Karen and Coffee CF 816B(前缀和)
Description To stay woke and attentive(专注的) during classes, Karen needs some coffee! Karen, a coffee ...
- CF 816B Karen and Coffee【前缀和/差分】
To stay woke and attentive during classes, Karen needs some coffee! Karen, a coffee aficionado, want ...
随机推荐
- Redis持久化方式--RDB和AOF
转载于:https://www.cnblogs.com/xingzc/p/5988080.html Redis提供了RDB持久化和AOF持久化 RDB机制的优势和略施 RDB持久化是指在指定的时间间隔 ...
- 洛谷 P1608 路径统计
P1608 路径统计 题目描述 “RP餐厅”的员工素质就是不一般,在齐刷刷的算出同一个电话号码之后,就准备让HZH,TZY去送快餐了,他们将自己居住的城市画了一张地图,已知在他们的地图上,有N个地方, ...
- Redis集群方案收集
说明: 如果不考虑客户端分片去实现集群,那么市面上基本可以说就三种方案最成熟,它们分别如下所示: 系统 贡献者 是否官方Redis实现 编程语言 Twemproxy Twitter 是 C Redis ...
- Eclipse错误:Syntax error on tokens, delete these tokens问题解决
错误:Syntax error on tokens, delete these tokens 出现这样的错误一般是括号.中英文字符.中英文标点.代码前面的空格,尤其是复制粘贴的代码,去掉即可.
- day2-搭建hdfs分布式集群
1.搭建hdfs分布式集群 4.1 hdfs集群组成结构: 4.2 安装hdfs集群的具体步骤: 一.首先需要准备N台linux服务器 学习阶段,用虚拟机即可! 先准备4台虚拟机:1个namenode ...
- Sharpdevelop如何在项目中添加类文件
点击文件-新建-文件,然后再工程内创建文件 或者工程-添加-新建项
- vux 实现多栏滚动
1.PopupPicker 组件 <!-- vux-ui --> <template> <div> <!-- 标题栏 --> <x-header ...
- react-native redux 操作
1.项目目录 2.redux (1)app/redux/action/action.js /** * 步骤一 * 行为 action */ // 定义行为名称 export const CHANGE_ ...
- 修改mysql root密码
mysql密码丢失后,在mysql命令行下执行如下命令,即可将root用户密码清空: mysqld_safe --skip-grant-tables& mysql修改密码 mysql修改,可在 ...
- FineUI之使用SQL脚本从数据库表中生成对应的输入控件
在WEB开发时.常常须要根据数据库表中的字段建立对应的输入控件,来获取输入的数据.每次都须要按字段来敲,显然太低效.并且easy出错.这里提供一个SQL脚本生成对应输入控件的方法. USE DBDem ...