HDU 5914 Triangle 【构造】 (2016中国大学生程序设计竞赛(长春))
Triangle
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 0 Accepted Submission(s): 0Problem DescriptionMr. Frog has n sticks, whose lengths are 1,2, 3⋯n respectively. Wallice is a bad man, so he does not want Mr. Frog to form a triangle with three of the sticks here. He decides to steal some sticks! Output the minimal number of sticks he should steal so that Mr. Frog cannot form a triangle with
any three of the remaining sticks.InputThe first line contains only one integer T (T≤20), which indicates the number of test cases.For each test case, there is only one line describing the given integer n (1≤n≤20).
OutputFor each test case, output one line “Case #x: y”, where x is the case number (starting from 1), y is the minimal number of sticks Wallice should steal.Sample Input3
4
5
6Sample OutputCase #1: 1
Case #2: 1
Case #3: 2
题目链接:
http://acm.hdu.edu.cn/showproblem.php?pid=5914
题目大意:
给你1~N(N<=20)长度的木棒,求至少拿掉几根使得剩余的木棒构成不了三角形。
题目思路:
【模拟】
画画前几个就可以得出,剩下的木棒是斐波那契数列1,2,3,5,8,13。N只有20,打表。
//
//by coolxxx
//#include<bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<string>
#include<iomanip>
#include<map>
#include<stack>
#include<queue>
#include<set>
#include<bitset>
#include<memory.h>
#include<time.h>
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
//#include<stdbool.h>
#include<math.h>
#define min(a,b) ((a)<(b)?(a):(b))
#define max(a,b) ((a)>(b)?(a):(b))
#define abs(a) ((a)>0?(a):(-(a)))
#define lowbit(a) (a&(-a))
#define sqr(a) ((a)*(a))
#define swap(a,b) ((a)^=(b),(b)^=(a),(a)^=(b))
#define mem(a,b) memset(a,b,sizeof(a))
#define eps (1e-10)
#define J 10000
#define mod 1000000007
#define MAX 0x7f7f7f7f
#define PI 3.14159265358979323
#pragma comment(linker,"/STACK:1024000000,1024000000")
#define N 104
using namespace std;
typedef long long LL;
double anss;
LL aans,sum;
int cas,cass;
int n,m,lll,ans;
int a[]={,,,,,,,,,,,,,,,,,,,,};
int main()
{
#ifndef ONLINE_JUDGEW
// freopen("1.txt","r",stdin);
// freopen("2.txt","w",stdout);
#endif
int i,j,k;
// init();
// for(scanf("%d",&cass);cass;cass--)
for(scanf("%d",&cas),cass=;cass<=cas;cass++)
// while(~scanf("%s",s))
// while(~scanf("%d",&n))
{
scanf("%d",&n);
printf("Case #%d: ",cass);
printf("%d\n",a[n]);
}
return ;
}
/*
// //
*/
HDU 5914 Triangle 【构造】 (2016中国大学生程序设计竞赛(长春))的更多相关文章
- HDU 5916 Harmonic Value Description 【构造】(2016中国大学生程序设计竞赛(长春))
Harmonic Value Description Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Ja ...
- HDU 5920 Ugly Problem 【模拟】 (2016中国大学生程序设计竞赛(长春))
Ugly Problem Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Tota ...
- HDU 5912 Fraction 【模拟】 (2016中国大学生程序设计竞赛(长春))
Fraction Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Su ...
- HDU 6150 - Vertex Cover | 2017 中国大学生程序设计竞赛 - 网络选拔赛
思路来自 ICPCCamp /* HDU 6150 - Vertex Cover [ 构造 ] | 2017 中国大学生程序设计竞赛 - 网络选拔赛 题意: 给了你一个贪心法找最小覆盖的算法,构造一组 ...
- 2016中国大学生程序设计竞赛 - 网络选拔赛 C. Magic boy Bi Luo with his excited tree
Magic boy Bi Luo with his excited tree Problem Description Bi Luo is a magic boy, he also has a migi ...
- 2016中国大学生程序设计竞赛(长春) Ugly Problem 模拟+大数减法
传送门:http://acm.hdu.edu.cn/showproblem.php?pid=5920 我们的思路是: 对于一个串s,先根据s串前一半复制到后一半构成一个回文串, 如果这个回文串比s小, ...
- 2016中国大学生程序设计竞赛(长春)-重现赛 1010Ugly Problem 回文数 模拟
Ugly Problem Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Tota ...
- 2016中国大学生程序设计竞赛 - 网络选拔赛 1004 Danganronpa
Problem Description Chisa Yukizome works as a teacher in the school. She prepares many gifts, which ...
- 2016中国大学生程序设计竞赛 - 网络选拔赛 1011 Lweb and String
Problem Description Lweb has a string S. Oneday, he decided to transform this string to a new sequen ...
随机推荐
- Spring读书笔记-----Spring的Bean之设置Bean值
[java] view plaincopyprint? Java实例的属性值可以有很多种数据类型.基本类型值.字符串类型.java实例甚至其他的Bean实例.java集合.数组等.所以Spring允许 ...
- Parse和Convert的区别
DateTime.Parse是转换String为DateTime Convert.ToDateTime是转换继承自Object的对象为DateTime的. 你得到一个object对象,你想把它转换为D ...
- spring 的 PropertyPlaceholderConfigurer读取的属性怎么访问 (java访问方式,不是xml中的占位符哦)及此类的应用
一.1.占位符的应用:(@Autowired注解方式,不需要建立set与get方法了,xml注入也不需要写了) http://www.cnblogs.com/susuyu/archive/2012/0 ...
- Object-C 类实现
这篇为Object-C添加方法的后续. 这里我们应该在类的实现(.m)文件中写 #import "Photo.h" @implementation Photo - (NSStrin ...
- 关于Java中的选择排序法和冒泡排序法
一,这种方法是直接传入一个数组进行排序(选择排序法) public static void selectSort(int arr[]){ for (int i = 0; i < arr.leng ...
- 需要 了解 j2ee 框架
只要你是用java来做WEB应用,绝对少不了使用j2ee框架,目前流行的有 l\5qa_{z Y(/VW&K&: )zt*am; 1)struts 2)spring ...
- hdoj(3790) 最短路径
最短路径问题 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Subm ...
- C++primer(第五版)读书笔记&习题解答---CHAPTER 3
C++标准库类型包括:string,vector和迭代器,其中string是可变长的字符序列,vector存放的是某种给定类型对象的可变长序列,迭代器是string和vector的配套类型,常被用于访 ...
- 237. Delete Node in a Linked List(C++)
237. Delete Node in a Linked Lis t Write a function to delete a node (except the tail) in a singly l ...
- CentOS 6.4 64位 安装 mysql 5.6.24
下载安装包 由于官网访问及版本选择下载不太方便,使用 suho 的源进行下载 http://mirrors.sohu.com/mysql/MySQL-5.6/ 下载如下三个安装包: MySQL-ser ...