Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

  1. Input: [1,3,5,4,7]
  2. Output: 3
  3. Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3.
  4. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.

题目地址: Longest Continuous Increasing Subsequence

难度: Easy

题意: 找出呈递增的趋势的子数组,返回最大长度

思路:

遍历数组,并计数,比较简单

  1. class Solution(object):
    def findLengthOfLCIS(self, nums):
  2. """
  3. :type nums: List[int]
  4. :rtype: int
  5. """
  6. n = len(nums)
  7. if n <= 1:
  8. return len(nums)
  9.  
  10. res = 0
  11. length = 1
  12. for i in range(n-1):
  13. if nums[i] < nums[i+1]:
  14. length += 1
  15. else:
  16. res = max(length, res)
  17. length = 1
  18. res = max(length, res)
  19. return res

时间复杂度: O(n)

空间复杂度: O(1)

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