手动部署servlet

1.编写servlet，在tomcat\webapps目录下新建文件Test，Test目录如下

Test

|

classes   web.xml

|

test01

|

Servletfirst.java

Servletfirst.java文件内容如下

 package test01;

 import java.io.IOException;
 import java.io.PrintWriter;

 import javax.servlet.ServletException;
 import javax.servlet.http.HttpServlet;
 import javax.servlet.http.HttpServletRequest;
 import javax.servlet.http.HttpServletResponse;

 public class Servletfirst extends HttpServlet {
     public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException,IOException {
         PrintWriter out=response.getWriter();
         out.println("Hello world!");
     }
     public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException,IOException {
         doGet(request, response);
     }
 }

2.在命令行模式下往classpath变量中添加servlet-api.jar的路径，例如set classpath=%classpath%;E:\Program Files\tomcat\lib\servlet-api.jar
进入Servletfirst.java的目录，编译.java文件生成.class文件，javac -d . Servletfirst.java

3.配置web.xml文件

 <servlet>
         <servlet-name>Servletfirst</servlet-name>
         <servlet-class>test01.Servletfirst</servlet-class>
     </servlet>
     <servlet-mapping>
     <servlet-name>Servletfirst</servlet-name>
     <url-pattern>/hello</url-pattern>
     </servlet-mapping>

4.在tomcat\bin目录下执行startup.bat开启服务器
5.在浏览器地址栏里输入http://localhost:8080/Test/hello就能访问servlet了。