[LeetCode&Python] Problem 892. Surface Area of 3D Shapes

On a N * N grid, we place some 1 * 1 * 1 cubes.

Each value v = grid[i][j] represents a tower of v cubes placed on top of grid cell (i, j).

Return the total surface area of the resulting shapes.

 

Example 1:

Input: [[2]]
Output: 10

Example 2:

Input: [[1,2],[3,4]]
Output: 34

Example 3:

Input: [[1,0],[0,2]]
Output: 16

Example 4:

Input: [[1,1,1],[1,0,1],[1,1,1]]
Output: 32

Example 5:

Input: [[2,2,2],[2,1,2],[2,2,2]]
Output: 46

Note:

• 1 <= N <= 50
• 0 <= grid[i][j] <= 50

class Solution(object):
    def surfaceArea(self, grid):
        """
        :type grid: List[List[int]]
        :rtype: int
        """
        allside=0
        overlap=0

        for i, v in enumerate(grid):
            for j, z in enumerate(v):
                if z==0:
                    continue

                allside+=4*z+2

                if i!=0:
                    overlap+=min(z,grid[i-1][j])
                if i!=len(grid)-1:
                    overlap+=min(z,grid[i+1][j])
                if j!=0:
                    overlap+=min(z,grid[i][j-1])
                if j!=len(grid[0])-1:
                    overlap+=min(z,grid[i][j+1])

        return allside-overlap