53. Maximum Subarray(动态规划 求最大子数组)

 

Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

For example, given the array [-2,1,-3,4,-1,2,1,-5,4],
the contiguous subarray [4,-1,2,1] has the largest sum = 6.

递归方程;

dp[i] = dp[i-1]+nums[i] ,dp[i-1]>0

dp[i] = nums[i] ,else

 class Solution {
     public int maxSubArray(int[] nums) {
         int dp[] = new int[nums.length+1];
         int max = nums[0];
         dp[0] = nums[0];
         for(int i =1;i<nums.length;i++){
             if(dp[i-1]<=0)
                 dp[i] = nums[i];
             else
                 dp[i] = dp[i-1]+nums[i];
             max = Math.max(dp[i],max);
         }
         return max;
     }
 }