Scala List FAQ: How do I add elements to a Scala List?

This is actually a trick question, because you can't add elements to a ScalaList; it's an immutable data structure, like a Java String.

Prepending elements to Scala Lists

One thing you can do when working with a Scala List is to create a newList from an existing List. This sort of thing is done often in functional programming, and the general approach looks like this:

scala> val p1 = List("Kim")
p1: List[String] = List(Kim) scala> val p2 = "Julia" :: p1
p2: List[String] = List(Julia, Kim) scala> val p3 = "Judi" :: p2
p3: List[String] = List(Judi, Julia, Kim)

Those examples show how to create a series of lists. The initial list namedp1 contains one string, then p2 contains two strings, and finally p3 contains three strings.

While that approach looks cumbersome in a small example, it makes sense in larger, real-world code. You can see more/better examples of this approach in my tutorial titled, Scala List class examples.

Use a ListBuffer when you want a "List" you can modify

If you want to use a Scala sequence that has many characteristics of a Listand is also mutable (you can add and remove elements in it), use theListBuffer class instead, like this:

import scala.collection.mutable.ListBuffer

var fruits = new ListBuffer[String]()
fruits += "Apple"
fruits += "Banana"
fruits += "Orange"

Then convert it to a List if/when you need to:

val fruitsList = fruits.toList

Scala REPL example

Here's what this List and ListBuffer example looks like using the Scala command line (REPL):

scala> import scala.collection.mutable.ListBuffer
import scala.collection.mutable.ListBuffer scala> var fruits = new ListBuffer[String]()
fruits: scala.collection.mutable.ListBuffer[String] = ListBuffer() scala> fruits += "Apple"
res0: scala.collection.mutable.ListBuffer[String] = ListBuffer(Apple) scala> fruits += "Banana"
res1: scala.collection.mutable.ListBuffer[String] = ListBuffer(Apple, Banana) scala> fruits += "Orange"
res2: scala.collection.mutable.ListBuffer[String] = ListBuffer(Apple, Banana, Orange) scala> val fruitsList = fruits.toList
fruitsList: List[String] = List(Apple, Banana, Orange)
 

More functional ways to work with Scala lists

Depending on your needs, there are other, "more functional" ways to work with Scala lists, and I work through some of those in my Scala List examples. But for my needs today, I just wanted to work with a Scala Listlike I'd work with a Java List (ArrayListLinkedList), and this approach suits me.

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