HDU 1686 Oulipo(优化的KMP)
Oulipo
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 17441 Accepted Submission(s):
6938
a book, La disparition, without the letter 'e'. He was a member of the Oulipo
group. A quote from the book:
Tout avait Pair normal, mais tout
s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain,
l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait
au roman : stir son tapis, assaillant à tout instant son imagination,
l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un
non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la
raison : tout avait l’air normal mais…
Perec would probably have scored
high (or rather, low) in the following contest. People are asked to write a
perhaps even meaningful text on some subject with as few occurrences of a given
“word” as possible. Our task is to provide the jury with a program that counts
these occurrences, in order to obtain a ranking of the competitors. These
competitors often write very long texts with nonsense meaning; a sequence of
500,000 consecutive 'T's is not unusual. And they never use spaces.
So we
want to quickly find out how often a word, i.e., a given string, occurs in a
text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite
strings over that alphabet, a word W and a text T, count the number of
occurrences of W in T. All the consecutive characters of W must exactly match
consecutive characters of T. Occurrences may overlap.
number: the number of test cases to follow. Each test case has the following
format:
One line with the word W, a string over {'A', 'B', 'C', …, 'Z'},
with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
One line
with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤
1,000,000.
should contain a single number, on a single line: the number of occurrences of
the word W in the text T.
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN
3
0
- #include <iostream>
- #include<cstdio>
- #include<string>
- #include<cstring>
- int next[], num;
- char a[], b[];
- int lena, lenb;
- void get_next()//自身和自身比较,找某种特征
- {
- int i, j;
- i = ; next[] = -; j = -;
- while (i<lenb)
- {
- if (j == - || b[i] == b[j])//匹配成功的话,继续下一位
- {
- i++;
- j++;
- if (b[i] == b[j])
- {
- next[i] = next[j];
- }
- else
- {
- next[i] = j;
- }
- }
- else//否则返回到可以匹配的位置
- {
- j = next[j];
- }
- }
- }
- void index_KMP()
- {
- int i, j;
- i = ;
- j = ;
- num = ;
- while (i<lena)
- {
- if (a[i] == b[j] || j == -) //进行两个字符串的匹配
- {
- i++;//匹配成功,往后继续匹配
- j++;
- }
- else//匹配完成一次,代表出现了一次,记录下来
- {
- j = next[j];
- }
- if (j == lenb)//匹配失败,寻找数组中可以匹配的位置
- {
- num++;
- j = next[j];
- }
- }
- printf("%d\n", num);
- }
- int main()
- {
- int n;
- while (scanf("%d", &n) != EOF)
- {
- getchar();
- while (n--)
- {
- gets(b);
- gets(a);
- lena = strlen(a);
- lenb = strlen(b);
- get_next();
- index_KMP();
- }
- }
- return ;
- }
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