bzoj5293: [Bjoi2018]求和

题目链接

bzoj5293: [Bjoi2018]求和

题解

暴力

对于lca为1的好坑啊....

代码

#include<cmath>
#include<cstdio>
#include<algorithm>
inline int read() {
 	int x = 0,f = 1;
    char c  = getchar();
    while(c < '0' || c > '9')c = getchar();
    while(c <= '9' && c >= '0')x = x * 10 + c - '0',c = getchar();
    return x * f ;
}
#define int long long
const int mod = 998244353;
const int maxn = 300007;
struct node {
    int v,next;
} edge[maxn << 1];
int head[maxn], num = 0 ;
inline void add_edge(int u,int v) {
    edge[++ num].v = v; edge[num].next = head[u];head[u] = num;
} 
int P[maxn][57];
int n,m;
int deep[maxn] = {-1},sum[maxn][57];
int dad[maxn][27];
void dfs(int x,int fa) {
    for(int i = 0; dad[x][i]; ++ i) dad[x][i + 1] = dad[dad[x][i]][i];
    for(int i = head[x];i ;i = edge[i].next) {
        int v = edge[i].v;
        if(v == fa)continue;
        deep[v] = deep[x] + 1; dad[v][0] = x;
        dfs(v,x);
    }
}
int k ;
int lca(int x,int y) {
    if(deep[x] > deep[y]) std::swap(x,y);
    for(int i = k;i >= 0;-- i) if(deep[dad[y][i]] >= deep[x]) y = dad[y][i];
    if(y == x) return x;
    for(int i = k;i >= 0;-- i) if(dad[y][i] != dad[x][i]) y = dad[y][i],x = dad[x][i];
    return dad[x][0];
}
main() {
    n = read();
    for(int i = 1;i <= n;++ i) {
        P[i][0] = 1,P[i][1] = i;
        for(int j = 2;j <= 50;++ j)
            P[i][j] = (long long) P[i][j - 1] * i % mod;
    }
    for(int i = 1;i <= n;++ i) for(int j = 1;j <= 50;++ j) P[i][j] = (P[i][j] + P[i - 1][j]) % mod;
    k = log2(n) + 1;
    for(int u,v, i = 1;i < n;++ i) {
        u = read(), v = read();
        add_edge(u,v); add_edge(v,u);
    }
    int m = read();
    dfs(1,0);
    while(m --) {
        int a = read(),b = read(),k = read();
        int LCA = lca(a,b);
        if(LCA == 1) {
            printf("%lld\n",(P[deep[a]][k] + P[deep[b]][k]) % mod);
        }
        else if(LCA == b || LCA == a) {
            if(LCA == a)  std::swap(a,b);
                printf("%lld\n",(P[deep[a]][k] - P[deep[b] - 1][k] + mod ) % mod);
        }
        else printf("%lld\n",((P[deep[a]][k] + P[deep[b]][k] - P[deep[LCA]][k] - P[deep[LCA] - 1][k]) % mod + mod) % mod);
    }
    return 0;
}