希望能帮助一些linq新手。

开门见山

读这篇文章之前,我先说下,每一种搜索结果集,我都以三种方式变现出来,为啦更好的理解,希望不要嫌我啰嗦。

1.简单的linq语法

            //1
var ss = from r in db.Am_recProScheme
select r;
//2
var ss1 = db.Am_recProScheme;
//3
string sssql = "select * from Am_recProScheme";

2.带where的查询

            //1
var ss = from r in db.Am_recProScheme
where r.rpId > 10
select r;
//2
var ss1 = db.Am_recProScheme.Where(p => p.rpId > 10);
//3
string sssql = "select * from Am_recProScheme where rpid>10";

3.简单的函数计算(count,min,max,sum)

            //1
////获取最大的rpId
//var ss = (from r in db.Am_recProScheme
// select r).Max(p => p.rpId);
////获取最小的rpId
//var ss = (from r in db.Am_recProScheme
// select r).Min(p => p.rpId);
//获取结果集的总数
//var ss = (from r in db.Am_recProScheme
// select r).Count();
//获取rpId的和
var ss = (from r in db.Am_recProScheme
select r).Sum(p => p.rpId); //2
//var ss1 = db.Am_recProScheme.Max(p=>p.rpId);
//var ss1 = db.Am_recProScheme.Min(p => p.rpId);
//var ss1 = db.Am_recProScheme.Count() ;
var ss1 = db.Am_recProScheme.Sum(p => p.rpId);
Response.Write(ss); //3
string sssql = "select max(rpId) from Am_recProScheme";
sssql = "select min(rpId) from Am_recProScheme";
sssql = "select count(1) from Am_recProScheme";
sssql = "select sum(rpId) from Am_recProScheme";

4.排序order by desc/asc

            var ss = from r in db.Am_recProScheme
where r.rpId > 10
orderby r.rpId descending //倒序
// orderby r.rpId ascending //正序
select r; //正序
var ss1 = db.Am_recProScheme.OrderBy(p => p.rpId).Where(p => p.rpId > 10).ToList();
//倒序
var ss2 = db.Am_recProScheme.OrderByDescending(p => p.rpId).Where(p => p.rpId > 10).ToList(); string sssql = "select * from Am_recProScheme where rpid>10 order by rpId [desc|asc]";

5.top(1)

            //如果取最后一个可以按倒叙排列再取值
var ss = (from r in db.Am_recProScheme
select r).FirstOrDefault(); //()linq to ef 好像不支持 Last()
var ss1 = db.Am_recProScheme.FirstOrDefault();
//var ss1 = db.Am_recProScheme.First(); string sssql = "select top(1) * from Am_recProScheme";

6.跳过前面多少条数据取余下的数据

            //1
var ss = (from r in db.Am_recProScheme
orderby r.rpId descending
select r).Skip(10); //跳过前10条数据,取10条之后的所有数据
//2
var ss1 = db.Am_recProScheme.OrderByDescending(p => p.rpId).Skip(10).ToList();
//3
string sssql = "select * from (select ROW_NUMBER()over(order by rpId desc) as rowNum, * from [Am_recProScheme]) as t where rowNum>10";

7.分页数据查询

            //1
var ss = (from r in db.Am_recProScheme
where r.rpId > 10
orderby r.rpId descending
select r).Skip(10).Take(10); //取第11条到第20条数据 //2 Take(10): 数据从开始获取,获取指定数量(10)的连续数据
var ss1 = db.Am_recProScheme.OrderByDescending(p => p.rpId).Where(p => p.rpId > 10).Skip(10).Take(10).ToList();
//3
string sssql = "select * from (select ROW_NUMBER()over(order by rpId desc) as rowNum, * from [Am_recProScheme]) as t where rowNum>10 and rowNum<=20";

8.包含,类似like '%%'

            //1
var ss = from r in db.Am_recProScheme
where r.SortsText.Contains("张")
select r;
//2
var ss1 = db.Am_recProScheme.Where(p => p.SortsText.Contains("张")).ToList();
//3
string sssql = "select * from Am_recProScheme where SortsText like '%张%'";

9.分组group by

            //1
var ss = from r in db.Am_recProScheme
orderby r.rpId descending
group r by r.recType into n
select new
{
n.Key, //这个Key是recType
rpId = n.Sum(r => r.rpId), //组内rpId之和
MaxRpId = n.Max(r => r.rpId),//组内最大rpId
MinRpId = n.Min(r => r.rpId), //组内最小rpId
};
foreach (var t in ss)
{
Response.Write(t.Key + "--" + t.rpId + "--" + t.MaxRpId + "--" + t.MinRpId);
}
//2
var ss1 = from r in db.Am_recProScheme
orderby r.rpId descending
group r by r.recType into n
select n;
foreach (var t in ss1)
{
Response.Write(t.Key + "--" + t.Min(p => p.rpId));
}
//3
var ss2 = db.Am_recProScheme.GroupBy(p => p.recType);
foreach (var t in ss2)
{
Response.Write(t.Key + "--" + t.Min(p => p.rpId));
}
//4
string sssql = "select recType,min(rpId),max(rpId),sum(rpId) from Am_recProScheme group by recType";

10.连接查询 

            //1
var ss = from r in db.Am_recProScheme
join w in db.Am_Test_Result on r.rpId equals w.rsId
orderby r.rpId descending
select r;
//2
var ss1 = db.Am_recProScheme.Join(db.Am_Test_Result, p => p.rpId, r => r.rsId, (p, r) => p).OrderByDescending(p => p.rpId).ToList();
//3
string sssql = "select r.* from [Am_recProScheme] as r inner join [dbo].[Am_Test_Result] as t on r.[rpId] = t.[rsId] order by r.[rpId] desc";

11.sql中的In

            //1
var ss = from p in db.Am_recProScheme
where (new int?[] { 24, 25,26 }).Contains(p.rpId)
select p;
foreach (var p in ss)
{
Response.Write(p.Sorts);
}
//2
string st = "select * from Am_recProScheme where rpId in(24,25,26)";

如果你是linq新手,建议这十个常用的查询标记学习,再加上视图,基本上就能解决大部分的查询问题啦。

转载:http://www.cnblogs.com/knowledgesea/p/3897665.html

Linq语法的更多相关文章

  1. Linq语法详细

    闲言碎语 近期比较忙,但还是想写点什么,就分享一些基础的知识给大家看吧,希望能帮助一些linq新手,如果有其它疑问,可以进右上角群,进行交流探讨,谢谢. 开门见山 读这篇文章之前,我先说下,每一种搜索 ...

  2. Linq语法详细(转)

    原文地址:http://www.cnblogs.com/knowledgesea/p/3897665.html 开门见山 读这篇文章之前,我先说下,每一种搜索结果集,我都以三种方式变现出来,为啦更好的 ...

  3. Linq To Sql中实现Left Join与Inner Join使用Linq语法与lambda表达式

    当前有两个表,sgroup与sgroupuser,两者通过gKey关联,而sgroup表记录的是组,而sgroupuser记录是组中的用户,因此在sgroupuser中不一定有数据.需要使用Left ...

  4. Lamda和Linq语法对比详细

    本人转载:http://www.cnblogs.com/knowledgesea/p/3897665.html 闲言碎语 近期比较忙,但还是想写点什么,就分享一些基础的知识给大家看吧,希望能帮助一些l ...

  5. Linq 语法举例

    1.简单的linq语法 //1 var ss = from r in db.Am_recProScheme select r; //2 var ss1 = db.Am_recProScheme; // ...

  6. LinQ 语法基础

    LINQ (Language-Integrated Query,语言集成查询). LINQ to Objects.LINQ to SQL.LINQ to DataSet和LINQ to XML,它们分 ...

  7. Linq语法常见普通语法

    闲言碎语 近期比较忙,但还是想写点什么,就分享一些基础的知识给大家看吧,希望能帮助一些linq新手,如果有其它疑问,可以进右上角群,进行交流探讨,谢谢. 开门见山 读这篇文章之前,我先说下,每一种搜索 ...

  8. C# LINQ语法详解

    1.简单的linq语法 var ss = from r in db.Am_recProScheme select r; var ss1 = db.Am_recProScheme; string sss ...

  9. LINQ语法类似于SQL的语法

    LINQ语法类似于SQL的语法如下, Models.BookStoreEntities 是从添加新建项中的数据--->ADO.NET实体数据模型--->从数据库生成--->使用5.0 ...

随机推荐

  1. HDU 3342

    #include<stdio.h> #include<string.h> int degree[101],vis[101],map[101][101]; int main() ...

  2. 初谈SQL Server逻辑读、物理读、预读【转】

    前言 本文涉及的内容均不是原创,是记录自己在学习IO.执行计划的过程中学习其他大牛的博客和心得并记录下来,之所以想写下来是为了记录自己在追溯的过程遇到的几个问题,并把这些问题弄清楚. 本章最后已贴出原 ...

  3. Asm Shader Reference --- Shader Model 2.0 part

    ps部分 ps_2_0 概览   Instruction Set                                   Name Description Instruction slot ...

  4. [POJ3684]Physics Experiment

      Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 1363   Accepted: 476   Special Judge ...

  5. 个性CMD设置方法(转载)

    原文地址http://wenku.baidu.com/link?url=DB8X-eHwE_VGtggBmKsBimdzXeGI_6Ga90W9PmX2Px2eUqdXOnq7FhEIzsqBfTqT ...

  6. NOIP2001 Car的旅行路线

    题四 Car的旅行路线(30分) 问题描述 又到暑假了,住在城市A的Car想和朋友一起去城市B旅游.她知道每个城市都有四个飞机场,分别位于一个矩形的四个顶点上,同一个城市中两个机场之间有一条笔直的高速 ...

  7. POJ 3468 A Simple Problem with Integers 线段树 区间更新

    #include<iostream> #include<string> #include<algorithm> #include<cstdlib> #i ...

  8. 使用C#模拟ASP.NET页面中按钮点击

    c# 模拟Asp.net页面中的某个按钮的点击,向web服务器发出请求 主要就组织要提交的数据,然后以post方式提交. 假设我们有如下的网页 1 <% @ Page Language = &q ...

  9. epoll原理解释(转)

    转自:http://yaocoder.blog.51cto.com/2668309/888374   首先我们来定义流的概念,一个流可以是文件,socket,pipe等等可以进行I/O操作的内核对象. ...

  10. [一]初识Poi

    示例代码: package com.lxl.poi; import java.io.FileOutputStream; import org.apache.poi.hssf.usermodel.HSS ...