POJ 2021 Relative Relatives

Relative Relatives

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 3339		Accepted: 1462

Description

Today is Ted's 100th birthday. A few weeks ago, you were selected by the family to contact all of Ted's descendants and organize a surprise party. To make this task easier, you created an age-prioritized list of everyone descended from Ted. Descendants of the same age are listed in dictionary order.

The only materials you had to aid you were birth certificates. Oddly enough, these birth certificates were not dated. They simply listed the father's name, the child's name, and the father's exact age when the baby was born.

Input

Input to this problem will begin with line containing a single integer n indicating the number of data sets. Each data set will be formatted according to the following description.

A single data set has 2 components: 

1. Descendant Count - A line containing a single integer X (where 0 < X < 100) indicating the number of Ted's descendants.
2. Birth Certificate List - Data for X birth certificates, with one certificate's data per line. Each certificate's data will be of the format "FNAME CNAME FAGE" where: 
   • FNAME is the father's name.
   • CNAME is the child's name.
   • FAGE is the integer age of the father on the date of CNAMEs birth.

Note:

• Names are unique identifiers of individuals and contain no embedded white space.
• All of Ted's descendants share Ted's birthday. Therefore, the age difference between any two is an integer number of years. (For those of you that are really picky, assume they were all born at the exact same hour, minute, second, etc... of their birth year.)
• You have a birth certificate for all of Ted's descendants (a complete collection).

Output

For each data set, there will be X+1 lines of output. The first will read, "DATASET Y", where Y is 1 for the first data set, 2 for the second, etc. The subsequent X lines constitute your age-prioritized list of Ted's descendants along with their ages using the format "NAME AGE". Descendants of the same age will be listed in dictionary order.

Sample Input

2
1
Ted Bill 25
4
Ray James 40
James Beelzebub 17
Ray Mark 75
Ted Ray 20

Sample Output

DATASET 1
Bill 75
DATASET 2
Ray 80
James 40
Beelzebub 23
Mark 5
题目大意：Ted近年100岁，给出n行，每行有两个字符串和一个数字，第一个字符串为父亲的名字，后面为儿子的名字以及父亲比儿子大多少岁，输出整个家族中除了Ted之外所有人的年龄，按年龄从大到小输出，如果年龄相同，则按照名字字典序从小到大输出。

#include <stdio.h>
#include <string>
#include <map>
#include <algorithm>
#include <vector>
#include <iostream>
#include <queue>
using namespace std;

typedef struct
{
    int age;
    string name;
}Person;

//父亲和儿子名字键值对
multimap<string, string> father_son;
//儿子和儿子年龄键值对
map<string, int> son_age;
//儿子和儿子比父亲少多少岁键值对
map<string, int> person_toage;
//家族中每个成员
vector<Person> Family;

bool cmp(const Person &p1, const Person &p2)
{
    if (p1.age == p2.age)
    {
        return p1.name < p2.name;
    }
    else
    {
        return p1.age > p2.age;
    }
}

//用BFS遍历得出家族中每个人的年龄
void BFS()
{
    queue<pair<string, int> > Queue;
    Queue.push(make_pair("Ted", ));
    while(!Queue.empty())
    {
        pair<string, int> p = Queue.front();
        Queue.pop();
        int nCount = father_son.count(p.first);
        if (nCount != )
        {
            //遍历父亲的所有儿子
            multimap<string, string>::iterator iter;
            for (iter = father_son.lower_bound(p.first); iter != father_son.upper_bound(p.first); iter++)
            {
                //儿子的年龄等于父亲的年龄减去父子年龄之差
                son_age[iter->second] = p.second - person_toage[iter->second];
                Person temp;
                temp.name = iter->second;
                temp.age = son_age[iter->second];
                Family.push_back(temp);
                //将当前儿子入队，作为后序的父亲
                Queue.push(make_pair(iter->second, son_age[iter->second]));
            }
        }
    }
}

int main()
{
    int nCase, n, age, nDataset = ;
    string father, son;
    cin>>nCase;
    while(nCase--)
    {
        cin>>n;
        father_son.clear();
        son_age.clear();
        person_toage.clear();
        Family.clear();
        son_age.insert(make_pair("Ted", ));
        ++nDataset;
        for (int i = ; i < n; i++)
        {
            cin>>father>>son>>age;
            father_son.insert(make_pair(father, son));
            person_toage.insert(make_pair(son, age));
        }
        BFS();
        sort(Family.begin(), Family.end(), cmp);
        cout<<"DATASET "<<nDataset<<endl;
        for (vector<Person>::iterator iter = Family.begin(); iter != Family.end(); iter++)
        {
            cout<<iter->name<<" "<<iter->age<<endl;
        }
    }
    return ;
}