bufferToggle(open: Observable, () => close: Observalbe : Observalbe<T[]>)

bufferToggle take two args, first is opening observable, seconde is a function which return an observable for closing.

The closeing observalbe only execute after opening emit value.

const source$ = Rx.Observable.interval(500);
const open$ = Rx.Observable.interval(1500);
const close$ = Rx.Observable.interval(1000); /** ---0---1---2---3---4---5---6---7---8---9----.... (source) -----------1-----------2-----------3--------... (open) --- ---x --- ---x --- ---x... (close)
bufferToggle(open$, () => close$) ------------------([2,3])-----([5.6])-----([8,9])--...
*/ const foo$ = source$.bufferToggle(open$, () => {
return close$;
}); foo$.subscribe(
(x) => console.debug("Next: " + x),
(err) => console.error(err),
() => console.info("DONE")
) /* "Next: 2,3"
"Next: 5,6"
"Next: 8,9"
"Next: 11,12"
...
*/

bufferWhen( () => Observable):

bufferWhen takes a function which return observable.

const source$ = Rx.Observable.interval(500);
const close$ = Rx.Observable.interval(1000); /** ---0---1---2---3---4---5---6---7---8---9----.... (source) -------0-------1-------2-------3-------4---.... (close) bufferWhen(()=>close$) -------(0)-----([1,2])-([3,4])-([5,6])--......
*/ const foo$ = source$.bufferWhen(() => close$); foo$.subscribe(
(x) => console.debug("Next: " + x),
(err) => console.error(err),
() => console.info("DONE")
) /* "Next: 0"
"Next: 1,2"
"Next: 3,4"
"Next: 5,6"
"Next: 7,8"
...
*/

[RxJS] Transformation operator: bufferToggle, bufferWhen的更多相关文章

  1. [RxJS] Transformation operator: repeat

    Operator repeat() is somewhat similar to retry(), but is not for handling operators. In this lesson ...

  2. [RxJS] Transformation operator: buffer, bufferCount, bufferTime

    This lesson will teach you about another horizontal combination operator: buffer and its variants. B ...

  3. [RxJS] Transformation operator: scan

    All of the combination operators take two or more observables as input. These operators may also be ...

  4. [RxJS] Transformation operator: map and mapTo

    We made our first operator called multiplyBy, which looks a bit useful, but in practice we don't nee ...

  5. [RxJS] Utility operator: do

    We just saw map which is a transformation operator. There are a couple of categories of operators, s ...

  6. rxjs自定义operator

    rxjs自定义operator

  7. [RxJS] Creation operator: of()

    RxJS is a lot about the so-called "operators". We will learn most of the important operato ...

  8. [RxJS] Connection operator: multicast and connect

    We have seen how Subjects are useful for sharing an execution of an RxJS observable to multiple obse ...

  9. [RxJS] Combination operator: withLatestFrom

    Operator combineLatest is not the only AND-style combinator. In this lesson we will explore withLate ...

随机推荐

  1. 【小结】有关mysql扩展库和mysqli扩展库的crud操作封装

    现阶段php如果要操作mysql数据库 php给我们提供了3套库 1.mysql扩展库   面向过程操作 2.mysqli扩展库  面向对象操作和面向过程操作并存  安全性和效率高于mysql扩展库 ...

  2. gcc/g++命令认识

    gcc & g++是gnu中最主要和最流行的c & c++编译器 . g++用来针对c++的处理命令,以.cpp为后缀,对于c语言后缀名一般为.c.这时候命令换做gcc即可. 下面以T ...

  3. iOS 图片转NSData-b

    iOS开发中 UIImage可能经常需要转为NSData 上传 传递等等 有两个比较常用的方法 UIImageJPEGRepresentation UIImagePNGRepresentation 第 ...

  4. 上传XML文件字符编码问题

    1.上传的XML文件的空格的字符编码和倒入到数据库的空格的字符编码不是一种编码格式,导致导入到数据库的数据和XML文件的数据不一致的情况,进而使展示到界面上的数据在进行搜索时不能搜索出来.解决办法: ...

  5. python 学习笔记整理

    首先自我批评一下,说好的一天写一篇博客,结果不到两天,就没有坚持了,发现自己做什么事情都没有毅力啊!不能持之以恒.但是,这次一定要从写博客开始来改掉自己的一个坏习惯. 可是写博客又该写点什么呢? 反正 ...

  6. BZOJ 2226 LCMSum

    Description Given \(n\), calculate the sum \(LCM(1,n) + LCM(2,n) + \cdots + LCM(n,n)\), where \(LCM( ...

  7. IndexedDB demo showcase

    var dbGlobals = new Object(); dbGlobals.db = null; dbGlobals.description = "This database is us ...

  8. 【HDOJ】2780 Su-Su-Sudoku

    模拟+DFS. /* 2780 */ #include <cstdio> #include <cstring> #include <cstdlib> ][]; ][ ...

  9. 【HDOJ】1422 重温世界杯

    简单题. #include <stdio.h> #define MAXN 100005 int wi[MAXN], li[MAXN]; ]; int main() { int n, tot ...

  10. poj2752 bzoj3670

    2752这是一道关于next函数的题(其实好像也可以用后缀数组暴力搞搞,但大概会超时)根据next[i]=max{j} (s[0..j]=s[i-j..i] j<i)不难发现这正是某个串既是前缀 ...