[PAT] 1142 Maximal Clique(25 分)
1142 Maximal Clique(25 分)
A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the clique are adjacent. A maximal clique is a clique that cannot be extended by including one more adjacent vertex. (Quoted from https://en.wikipedia.org/wiki/Clique_(graph_theory)
Now it is your job to judge if a given subset of vertices can form a maximal clique.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers Nv (≤ 200), the number of vertices in the graph, and Ne, the number of undirected edges. Then Ne lines follow, each gives a pair of vertices of an edge. The vertices are numbered from 1 to Nv.
After the graph, there is another positive integer M (≤ 100). Then M lines of query follow, each first gives a positive number K (≤ Nv), then followed by a sequence of K distinct vertices. All the numbers in a line are separated by a space.
Output Specification:
For each of the M queries, print in a line Yes if the given subset of vertices can form a maximal clique; or if it is a clique but not a maximal clique, print Not Maximal; or if it is not a clique at all, print Not a Clique.
Sample Input:
8 10
5 6
7 8
6 4
3 6
4 5
2 3
8 2
2 7
5 3
3 4
6
4 5 4 3 6
3 2 8 7
2 2 3
1 1
3 4 3 6
3 3 2 1
Sample Output:
Yes
Yes
Yes
Yes
Not Maximal
Not a Clique
题意:
clique是一个无向图的点的子集,clique里每两个不同的点都是相连的。最大clique是不能扩展更多相连点的clique。
判断给定的点的子集是否为一个最大的clique。
思路:
将输入存在一个二维数组(矩阵)内,对于每一个查询,先判断是否为clique(每两个点对应的二维数组为1),再判断是否为max clique(遍历给定点之外的点是否和给定的点都有连线)。
题解:
#include<cstdlib>
#include<cstdio>
#include<vector>
using namespace std;
][];
int main() {
int nv, ne, m;
scanf("%d %d", &nv, &ne);
; i < ne; i++) {
int a, b;
scanf("%d %d", &a, &b);
vertex[a][b] = vertex[b][a] = ;
}
scanf("%d", &m);
; i < m; i++) {
int k;
scanf("%d", &k);
vector<);
vector<int> verts;
; j < k; j++) {
int t;
scanf("%d", &t);
verts.push_back(t);
v[t] = true;
}
//判断是否为clique
//只要给定查询中的每两个点对应矩阵上的值为0,说明它不是clique
bool isClique = true;
; j < verts.size(); j++) {
; r < verts.size(); r++) {
) {
printf("Not a Clique\n");
isClique = false;
break;
}
}
if (!isClique) break;
}
if (!isClique) continue;
//如果是clique,
//并且还存在给定之外的点与给定的所有点对应矩阵的值为1
//说明其不是max clique
bool notMaximal = false;
; j <= nv; j++) {
if (v[j] == true) continue;
bool isMaxClique = false;
; r < verts.size(); r++) {
) {
isMaxClique = true;
break;
}
}
if (!isMaxClique) {
printf("Not Maximal\n");
notMaximal = true;
break;
}
}
if (!notMaximal) printf("Yes\n");
}
;
}
[PAT] 1142 Maximal Clique(25 分)的更多相关文章
- PAT 1142 Maximal Clique[难]
1142 Maximal Clique (25 分) A clique is a subset of vertices of an undirected graph such that every t ...
- PAT 1142 Maximal Clique
A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...
- 1142. Maximal Clique (25)
A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...
- PTA PAT排名汇总(25 分)
PAT排名汇总(25 分) 计算机程序设计能力考试(Programming Ability Test,简称PAT)旨在通过统一组织的在线考试及自动评测方法客观地评判考生的算法设计与程序设计实现能力,科 ...
- PAT A1142 Maximal Clique (25 分)——图
A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...
- PAT 甲级 1142 Maximal Clique
https://pintia.cn/problem-sets/994805342720868352/problems/994805343979159552 A clique is a subset o ...
- PAT 甲级 1078 Hashing (25 分)(简单,平方二次探测)
1078 Hashing (25 分) The task of this problem is simple: insert a sequence of distinct positive int ...
- PAT 甲级 1070 Mooncake (25 分)(结构体排序,贪心,简单)
1070 Mooncake (25 分) Mooncake is a Chinese bakery product traditionally eaten during the Mid-Autum ...
- PAT 甲级 1032 Sharing (25 分)(结构体模拟链表,结构体的赋值是深拷贝)
1032 Sharing (25 分) To store English words, one method is to use linked lists and store a word let ...
随机推荐
- UVA.136 Ugly Numbers (优先队列)
UVA.136 Ugly Numbers (优先队列) 题意分析 如果一个数字是2,3,5的倍数,那么他就叫做丑数,规定1也是丑数,现在求解第1500个丑数是多少. 既然某数字2,3,5倍均是丑数,且 ...
- bzoj1878: [SDOI2009]HH的项链(主席树/离线+BIT)
这题有离线和在线两种做法. 离线:将查询区间按左端点排序,预处理出所有数下一次的出现位置,一开始将所有第一次出现的数a[i]++,之后当扫到这个数的时候a[next[i]]++,相当于差分,给之后 ...
- 【树形DP】【P1351】 【NOIP2014D1T2】联合权值
传送门 Description 无向连通图 \(G\) 有 \(n\) 个点, \(n-1\) 条边.点从 \(1\) 到 \(n\) 依次编号,编号为 \(i\) 的点的权值为 \(W_i\) ,每 ...
- 将微服务注册到Eureka Server
一.微服务程序编写 1.在已写好的微服务程序中添加pom依赖: <dependency> <groupId>org.springframework.cloud</grou ...
- Leetcode 703. 数据流中的第K大元素
1.题目要求 设计一个找到数据流中第K大元素的类(class).注意是排序后的第K大元素,不是第K个不同的元素. 你的 KthLargest 类需要一个同时接收整数 k 和整数数组nums 的构造器, ...
- POJ 3254 状态压缩 DP
B - Corn Fields Crawling in process... Crawling failed Time Limit:2000MS Memory Limit:65536KB ...
- Moodle简介
Moodle简介 一.概述 Moodle是Modular Object-Oriented Dynamic Learning Environment(模块化面向对象动态学习环境)的简称,中文译名为魔灯, ...
- Java设计模式の单例模式
-------------------------------------------------- 目录 1.定义 2.常见的集中单例实现 a.饿汉式,线程安全 但效率比较低 b.单例模式的实现:饱 ...
- Babel 和 PostCss 的一些基本配置
Babel 是一个javascript编译器,PostCSS 是一个样式转换工具.两者都可以看作是一个转化平台,我们可以在上面使用一些插件,来达到想要的代码转化.几乎每个前端项目都要使用它们. Bab ...
- windows版本redis下载安装
官方网站:http://redis.io/ 官方下载:http://redis.io/download 可以根据需要下载不同版本 在官方下载网页中有一个window版本的说明,说redis官方没有wi ...