hdu 1015 dfs
"The item is locked in a Klein safe behind a painting in the second-floor library. Klein safes are extremely rare; most of them, along with Klein and his factory, were destroyed in World War II. Fortunately old Brumbaugh from research knew Klein's secrets and wrote them down before he died. A Klein safe has two distinguishing features: a combination lock that uses letters instead of numbers, and an engraved quotation on the door. A Klein quotation always contains between five and twelve distinct uppercase letters, usually at the beginning of sentences, and mentions one or more numbers. Five of the uppercase letters form the combination that opens the safe. By combining the digits from all the numbers in the appropriate way you get a numeric target. (The details of constructing the target number are classified.) To find the combination you must select five letters v, w, x, y, and z that satisfy the following equation, where each letter is replaced by its ordinal position in the alphabet (A=1, B=2, ..., Z=26). The combination is then vwxyz. If there is more than one solution then the combination is the one that is lexicographically greatest, i.e., the one that would appear last in a dictionary."
v - w^2 + x^3 - y^4 + z^5 = target
"For example, given target 1 and letter set ABCDEFGHIJKL, one possible solution is FIECB, since 6 - 9^2 + 5^3 - 3^4 + 2^5 = 1. There are actually several solutions in this case, and the combination turns out to be LKEBA. Klein thought it was safe to encode the combination within the engraving, because it could take months of effort to try all the possibilities even if you knew the secret. But of course computers didn't exist then."
=== Op tech directive, computer division, 2002/11/02 12:30 CST ===
"Develop a program to find Klein combinations in preparation for field deployment. Use standard test methodology as per departmental regulations. Input consists of one or more lines containing a positive integer target less than twelve million, a space, then at least five and at most twelve distinct uppercase letters. The last line will contain a target of zero and the letters END; this signals the end of the input. For each line output the Klein combination, break ties with lexicographic order, or 'no solution' if there is no correct combination. Use the exact format shown below."
#include <stdio.h> #include <iostream> #include <string> #include <string.h> #include <cmath> #include <math.h> #include <algorithm> using namespace std; #define Maxn 1000 int aim; int dir[Maxn]; bool visit[Maxn+1]; int Aim[Maxn]; string A; bool flag; bool cmp(int a,int b) { return a > b; } void dfs(int T) { if (flag) { return ; } if (T == 5) { if ( Aim[0] - pow(Aim[1],2) + pow(Aim[2],3) - pow(Aim[3],4) + pow(Aim[4],5) == aim) { flag = true; printf("%c%c%c%c%c\n",Aim[0]+'A'-1,Aim[1]+'A'-1,Aim[2]+'A'-1,Aim[3]+'A'-1,Aim[4]+'A'-1); } return ; } for(int i = 0; i < A.length(); i++) { if (!visit[i]) { Aim[T] = dir[i]; visit[i] = true; dfs(T+1); visit[i] = false; } } } int main() { while(cin >> aim >> A) { if (aim == 0) { break; } flag = false; for (int i = 0; i < A.length(); i++) { dir[i] = A[i] - 'A' + 1; } sort(dir,dir+A.length(),cmp); for (int i = 0; i < A.length(); i++) { if (flag) { break; } memset(visit,false,sizeof(visit)); Aim[0] = dir[i]; visit[i] = true; dfs(1); } if (!flag) { printf("no solution\n"); } } }
YOXUZ
GHOST
no solution
hdu 1015 dfs的更多相关文章
- HDOJ(HDU).1015 Safecracker (DFS)
HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1 ...
- HDU 5143 DFS
分别给出1,2,3,4 a, b, c,d个 问能否组成数个长度不小于3的等差数列. 首先数量存在大于3的可以直接拿掉,那么可以先判是否都是0或大于3的 然后直接DFS就行了,但是还是要注意先判合 ...
- hdu 1015 Safecracker 水题一枚
题目链接:HDU - 1015 === Op tech briefing, 2002/11/02 06:42 CST === "The item is locked in a Klein s ...
- Snacks HDU 5692 dfs序列+线段树
Snacks HDU 5692 dfs序列+线段树 题意 百度科技园内有n个零食机,零食机之间通过n−1条路相互连通.每个零食机都有一个值v,表示为小度熊提供零食的价值. 由于零食被频繁的消耗和补充, ...
- hdu 1015(DFS)
Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total ...
- HDU 1015 Safecracker【数值型DFS】
Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total ...
- HDU 1015 Safecracker (DFS)
题意:给一个数字n(n<=12000000)和一个字符串s(s<=17),字符串的全是有大写字母组成,字母的大小按照字母表的顺序,比如(A=1,B=2,......Z=26),从该字符串中 ...
- HDU 5877 dfs+ 线段树(或+树状树组)
1.HDU 5877 Weak Pair 2.总结:有多种做法,这里写了dfs+线段树(或+树状树组),还可用主席树或平衡树,但还不会这两个 3.思路:利用dfs遍历子节点,同时对于每个子节点au, ...
- hdu 4751(dfs染色)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4751 思路:构建新图,对于那些两点连双向边的,忽略,然后其余的都连双向边,于是在新图中,连边的点是能不 ...
随机推荐
- Qt中使用信号和槽的一点心得
信号(Signal)与槽(Slot)-Qt中的典型机制 这一篇文章中都说得很详细了,这里不再重复,只说一点在实际使用中可能会遇到的问题. 1.一个信号不要同时连接几个槽函数,不然执行的顺序是随机的,最 ...
- ES 中文分词
一.大名鼎鼎的中文插件IK的安装配置 1. 在插件目录中建立IK的目录 mkdir $ES_HOME/plugins/analysis-ik 2. 下载IK 的类库jar 文件到IK目录 cd $ES ...
- canvas 之 - 精灵 钟表动画
<!doctype html> <html> <head> <meta charset="utf-8"> <title> ...
- windows phone 之笔势
笔势: Windows Phone 用户可以使用触控笔势与他们的手机进行交互.触控笔势被定义为用户在触摸屏上使用单个或多个手指发起的运动.Windows Phone 上支持的控件都可以识别笔势.这些控 ...
- Vim自动补全神器:YouCompleteMe(转)
转自:http://blog.jobbole.com/58978/ 可能会有一段时间写linxu,免不了用vim,留着,找时间实操之 原文出处: marchtea 的博客 第一次听说这个插件还是在偶然 ...
- Apache server-status
1.找到apache配置文件:httpd.conf 2.打开模块: LoadModule status_module modules/mod_status.so 3.在文件末尾处加上以下代码: ...
- 2016022609 - redis哈希命令集合
参考:http://www.yiibai.com/redis/redis_hashes.html Redis的哈希值是字符串字段和字符串值之间的映射,所以他们是表示对象的完美数据类型 在Redis中的 ...
- 百度云推送 pem
1. p12证书导出 在钥匙串访问中选中推送证书,导出为个人信息交换文件(.p12格式). 选择文件格式.文件名和保存路径. 输入导出密码. 2. pem证书生成 将p12证书文件转换成pem证书文件 ...
- 常用原生JS兼容性写法汇总
1.添加事件方法 addHandler:function(element,type,handler){ if(element.addEventListener){//检测是否为DOM2级方法 elem ...
- LightOj_1104 Birthday Paradox
题目链接 题意: 若一年有n天, 问至少需要多少个人才能满足其中两个人生日相同的概率大于等于0.5? 思路: 经典问题:生日悖论 换成其互斥事件:m个人, 每个人生日都不相同的概率 ≤ 0.5 时最小 ...