hdu 4639 Hehe

http://acm.hdu.edu.cn/showproblem.php?pid=4639

每一段 "hehe..... " 相互独立  将每一段 "hehe..... "可以形成的种类 相乘

代码：

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<cmath>
#include<set>
#include<vector>
#include<list>
using namespace std;
 
typedef long long ll;
typedef pair<double,double>ppd;
const double PI = acos(-1.);
const double eps = (1e-9);
const int MOD=10007;
const int N=5005;
char s[N];
int sum[N];
int main()
{
    //freopen("data.in","r",stdin);
    sum[0]=sum[1]=1;
    sum[2]=2;sum[3]=3;
    for(int i=4;i<N;++i)
    sum[i]=(sum[i-3]+sum[i-2]*2)%MOD;
    int T;
    scanf("%d",&T);
    for(int c=1;c<=T;++c)
    {
        scanf("%s",s);
        int n=strlen(s);
        int ans=1;
        int num=0;
        for(int i=0;i<n;++i)
        {
            if(i+1<n&&s[i]=='h'&&s[i+1]=='e')
            {++num;++i;}
            else
            {
                if(num>=2)
                ans=(ans*sum[num])%MOD;
                num=0;
            }
        }
        if(num>=2)
        ans=(ans*sum[num])%MOD;
        printf("Case %d: %d\n",c,ans);
    }
    return 0;
}