a letter and a number

描述we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

 import java.util.Scanner;
 
 public class Main {
     public static void main(String[] args) {
         Scanner scanner=new Scanner(System.in);
         int T;
         char s[]=new char[1];
         int result;
         int number;
 
         T=scanner.nextInt();
         while(true){
             if(T==0)
                 break;
             T--;
 
             s=scanner.next().toCharArray();
             number=scanner.nextInt();
 
             if(s[0]>='a' && s[0]<='z'){
                 result=-(s[0]-'a'+1)+number;
             }
             else
                 result=(s[0]-'A'+1)+number;
 
             System.out.println(result);
         }
     }
 }