HUD1686(KMP入门题)
Oulipo
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 8732 Accepted Submission(s): 3526
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.
#include<cstdio>
#include<cstring>
using namespace std;
char W[],T[];
int lenW,lenT;
int next[];
void getnext()
{
int i=,k=-;
next[]=-;
while(i<lenW)
{
if(k==-||W[i]==W[k])
{
i++;
k++;
next[i]=k;
}
else k=next[k];
}
}
int KMP()
{
getnext();
int i=,j=;
int cnt=;
while(i<lenT)
{
if(j==-||W[j]==T[i])
{
i++;
j++;
}
else j=next[j];
if(j==lenW)
{
cnt++;
j=next[j];//若两个不同的匹配中有交集则j=next[j],若没有交集j=0;
}
}
return cnt;
}
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
memset(next,,sizeof(next));
scanf("%s%s",W,T);
lenW=strlen(W);
lenT=strlen(T);
printf("%d\n",KMP());
} return ;
}
字符串Hash
#include<cstdio>
#include<cstring>
using namespace std;
typedef unsigned long long ull;
const ull B=;
const int MAXN=;
char a[MAXN],b[MAXN];
int lena,lenb;
ull t;
ull ah;
ull bh[MAXN];
void getah()
{
for(int i=;i<lena;i++)
t*=B;
for(int i=;i<lena;i++)
ah=ah*B+a[i];
}
void getbh()
{
ull h=;
for(int i=;i<lena;i++)
h=h*B+b[i];
bh[]=h;
for(int i=lena;i<lenb;i++)
bh[i-lena+]=bh[i-lena]*B+b[i]-b[i-lena]*t;
}
int KMP()
{
int cnt=;
memset(bh,,sizeof(bh));
getah();
getbh();
for(int i=;i<lenb-lena+;i++)
if(ah==bh[i]) cnt++;
return cnt;
}
int n;
int main(){ while(scanf("%d",&n)!=EOF)
{
while(n--)
{
ah=;
t=;
scanf("%s",a);
scanf("%s",b);
lena=strlen(a);
lenb=strlen(b);
printf("%d\n",KMP());
}
} return ;
}
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