经典SQL问题：Top 10%

学生表：

create table hy_student(
   id number(4,0) primary key,
   name nvarchar2(20) not null,
   score number(3,0) not null)

充值：

insert into hy_student
select rownum,dbms_random.string('*',dbms_random.value(1,20)),dbms_random.value(0,100)
from dual
connect by level<201
order by dbms_random.random

第一步把学生按成绩逆序排列：

select * from hy_student order by score desc

第二步给加伪列：

select rownum as rn,a.* from (select * from hy_student order by score desc) a

最后就可以检出前10%的精英了：

select b.* from (select rownum as rn,a.* from (select * from hy_student order by score desc) a) b where b.rn<= (select count(*) from hy_student)/10

结果：

--2020-04-02--

以上用到的全部SQL：

create table hy_student(
   id number(4,0) primary key,
   name nvarchar2(20) not null,
   score number(3,0) not null)
 
insert into hy_student
select rownum,dbms_random.string('*',dbms_random.value(1,20)),dbms_random.value(0,100)
from dual
connect by level<201
order by dbms_random.random
 
commit;
 
select * from hy_student order by score desc
 
select rownum as rn,a.* from (select * from hy_student order by score desc) a
 
select b.* from (select rownum as rn,a.* from (select * from hy_student order by score desc) a) b where b.rn<= (select count(*) from hy_student)/10