canvas 连线曲线图封装
- $.fn.hChart=function (opt) {
var setting=$.extend({
className:'',
data:[]
},opt);
var tbody=this;
var className=setting.className;
var arr=setting.data;
var spanEl=function (le) {
if(le>0){
return '<span class="'+className+'">'+le+'</span>';
}else {
return Math.abs(le);
}
}
for (let i=0;i<arr.length;i++) {
var str='<tr id="'+className+'_'+i+'">';
for(let js in arr[i].arr){
str+='<td>'+spanEl(arr[i].arr[js])+'</td>';
}
str+='</tr>';
$(str).appendTo(tbody);
}
var arr=[];
$.each($("."+className,tbody),function () {
var setoff=$(this).offset();
var jo={"top":setoff.top,"left":setoff.left,id:"canvas_"+$(this).parent().parent().attr("id"),w:$(this).width(),h:$(this).height()};
arr.push(jo);
});
for(let a=arr.length-1;a>0;a--){
var c=document.createElement("canvas");
var wLeft=tbody.offset().left;
var wTop=tbody.offset().top;
var st=arr[a];
var pr=arr[a-1];
var cTop=Math.min(st.top,pr.top);
var cLeft=Math.min(st.left,pr.left);
var cw,cuLeft,ch,cuTop,mToLeft,mToTop,liToLeft,liToTop;
var activeH=st.h/2;
if(st.left<pr.left){
cw= pr.left-st.left-st.h;
cuLeft= st.left-wLeft+st.h;
ch=st.top-pr.top;
cuTop=pr.top-wTop+activeH;
mToLeft=pr.left-cLeft;
mToTop=pr.top-cTop;
liToLeft=st.left-cLeft;
liToTop=st.top-cTop;
}else if(st.left==pr.left){
cw= st.w;
cuLeft=st.left-wLeft;
ch=(st.top-pr.top)/2+5;
cuTop=pr.top-wTop+st.h;
mToLeft=cw/2;
mToTop=pr.top-cTop;
liToLeft=cw/2;
liToTop=st.top-cTop;
}else{
cw=st.left-pr.left-st.h;
cuLeft=st.left-wLeft-cw;
ch=st.top-pr.top;
cuTop=pr.top-wTop+activeH;
mToLeft=pr.left-cLeft;
mToTop=pr.top-cTop;
liToLeft=st.left-cLeft;
liToTop=st.top-cTop;
}
c.style.position='absolute';
c.style.top=cuTop+"px";
c.style.left=cuLeft+"px";
c.width=cw;
c.height=ch;
c.id=arr[a].id;
let cx=c.getContext("2d");
cx.strokeStyle="red";
cx.moveTo(mToLeft,mToTop);
cx.lineTo(liToLeft,liToTop);
cx.stroke();
$(c).appendTo(tbody);
}
}
- })(jQuery);
- var arr=[
{"arr":[-3,-2,-5,-4,7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,-4,-7,9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,8]},
{"arr":[3,-2,-5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,-4,-7,-9,1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,7,-9,-7,-8,-8]},
{"arr":[3,-2,-5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,-4,7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,-4,-7,9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,8]},
{"arr":[3,-2,-5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,-4,-7,-9,1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,7,-9,-7,-8,-8]},
{"arr":[3,-2,-5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,-2,-5,4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]},
{"arr":[-3,2,-5,-4,-7,-9,-1,-6,-8,-3,-2,-5,-4,-7,-9,-7,-8,-8]}
];- $("#tbody").hChart({
className:'active',
data:arr
});
canvas 连线曲线图封装的更多相关文章
- canvas 连线曲线图
<!DOCTYPE html><html><head> <meta charset="utf-8"> <meta name=& ...
- 兼容IE浏览器的canvas画线和圆圈
1.新建test.html文件,代码如下: <!DOCTYPE html><html><head> <meta charset="utf-8& ...
- canvas 画线
一.canvas是基于状态的绘图环境 1.canvas是基于状态的绘制 context.moveTo(100,100); context.lineTo(700,700); context.lineWi ...
- canvas绘制线和矩形
###canvas绘制矩形 HTML中的元素canvas只支持一种原生的图形绘制:矩形.所有其他的图形的绘制都至少需要生成一条路径 1.绘制矩形 canvas提供了三种方法绘制矩形: ----> ...
- uniapp 封装 request 并 配置跨域,( 本地 + 线上 + 封装 )
找到上面这个 文件,不管是用 命令创建 还是 用 HBX 创建,都一样会有这个文件的,然后跟着截图复制粘贴就好了. // 这是配置本地能跨域的,或者你可以直接让后端给你设置请求头,避免了跨域. &qu ...
- canvas sprite动画 简单封装
function SpritCtx(img, size, pos, turnTime, totalCount, ctx) { size = size || {}; pos = pos || {}; / ...
- canvas连线特效
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...
- canvas 添加线和删除线 及获取相关位置信息源码
其他相关链接: https://github.com/lusase/lineDrawer.git https://www.jb51.net/css/359062.html https://www.jb ...
- HTML5之Canvas绘图实例——曲线图
实现正弦.余弦和正切函数画图(如下图):调试环境:Firefox
随机推荐
- NGUI 使用Grid自动排列UI
1,NGUI->Create Grid 2,把需要排列的UI放到Grid下边,对Grid进行参数设置
- 带你学C带你飞!
C语言免费课程推荐:带你学C带你飞! 想学习C语言,首先就要了解什么是C语言: C语言是一门通用计算机编程语言,应用广泛.C语言的设计目标是提供一种能以简易的方式编译.处理低级存储器.产生少量的机器码 ...
- luoguP4921 情侣?给我烧了! 组合数_容斥原理_计数问题
Code: #include <cstdio> #include <algorithm> #include <cstring> #define setIO(s) f ...
- How Many Partitions Does An RDD Have
From https://databricks.gitbooks.io/databricks-spark-knowledge-base/content/performance_optimization ...
- BZOJ 3676 [Apio2014]回文串 (后缀自动机+manacher/回文自动机)
题目大意: 给你一个字符串,求其中回文子串的长度*出现次数的最大值 明明是PAM裸题我干嘛要用SAM做 回文子串有一个神奇的性质,一个字符串本质不同的回文子串个数是$O(n)$级别的 用$manach ...
- Shell(二)运算符
基本运算符 Shell 和其他编程语言一样,支持多种运算符,包括: 算数运算符 关系运算符 布尔运算符 字符串运算符 文件测试运算符 原生bash不支持简单的数学运算,但是可以通过其他命令来实现,例如 ...
- java源码之TreeMap
Map的单元是对键值对的处理,之前分析过的两种Map,HashMap和LinkedHashMap都是用哈希值去寻找我们想要的键值对,优点是理想情况下O(1)的查找速度. 那如果我们在一个对查找性能要求 ...
- POJ 3696
这里面的一个转换的小技巧很重要,把888...8转换成(10^x-1)/9*8.神来之笔,佩服. 这样有(10^x-1)/9*8=L*p得10^x-1=L*p*9/8,设m=9*L/gcd(L,8). ...
- 关于Servo项目中Rust代码行数的数据来源
我两个月之前的一篇博客<为什么我说Rust是靠谱的编程语言>(下面简称原文),在当中"6. 两个半大型成功案例"一节.我以前写道: Servo: 下一代浏览器渲染引擎( ...
- cloudstack给已有zone加入物理网络
默认情况下,假设zone建立完后.cloudstack是不提供加入物理网络接口的. 基础架构- 域 - 物理网络 以下仅仅有我们创建zone的时候加入的物理网络 假设想在这个基础上加入一个物理网络是没 ...