[LeetCode&Python] Problem 728. Self Dividing Numbers

A self-dividing number is a number that is divisible by every digit it contains.

For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0.

Also, a self-dividing number is not allowed to contain the digit zero.

Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible.

Example 1:

Input:
left = 1, right = 22
Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]

Note:

• The boundaries of each input argument are 1 <= left <= right <= 10000.

Brute-Force!!!

class Solution:
    def selfDividingNumbers(self, left, right):
        """
        :type left: int
        :type right: int
        :rtype: List[int]
        """
        result=[]
 
        for num in range(left, right+1):
            strnum=str(num)
 
            flag=True
 
            for digit in strnum:
                if digit=='0':
                    flag=False
                    break
 
                if num%int(digit) !=0:
                    flag=False
                    break
 
            if flag:
                result.append(num)
 
        return result