[Ramda] Filter an Array Based on Multiple Predicates with Ramda's allPass Function
In this lesson, we'll filter a list of objects based on multiple conditions and we'll use Ramda's allPass
function to create a joint predicate from multiple, individual predicate functions.
const R = require('ramda'); const { allPass, propEq, lte, propSatisfies, filter } = R; const cars = [
{
name: 'suv',
doors: 4,
mpg: 19
},
{
name: 'sedan',
doors: 4,
mpg: 30
},
{
name: 'hybrid',
doors: 4,
mpg: 37
},
{
name: 'compact',
doors: 2,
mpg: 32
}
]; const mpgLte30 = propSatisfies(lte(R.__, 30), 'mpg');
const fourDoors = propEq('doors', 4);
const preds = allPass([
mpgLte30,
fourDoors
]);
const result = filter(preds)(cars);
console.log(result);
[Ramda] Filter an Array Based on Multiple Predicates with Ramda's allPass Function的更多相关文章
- [Ramda] Create an Array From a Seed Value with Ramda's unfold
In this lesson we'll look at how you can use Ramda's unfold function to generate a list of values ba ...
- Wideband Direction of Arrival Estimation Based on Multiple Virtual Extension Arrays
基于多重虚拟扩展阵列的宽带信号DOA估计[1]. 宽带DOA估计是阵列信号处理领域的一个重要研究方向.在DOAs估计的实际应用中,信号总是会被噪声破坏,在某些情况下,源信号的数量大于传感器的数量,因此 ...
- Resource Access Based on Multiple Credentials
A collection of multiple user credentials each associated with one of multiple different users is ob ...
- [Ramda] Filter, Reject and Partition
We'll learn how to get a subset of an array by specifying items to include with filter, or items to ...
- [ES2019] Use JavaScript ES2019 flatMap to Map and Filter an Array
ES2019 introduces the Array.prototype.flatMap method. In this lesson, we'll investigate a common use ...
- [Ramda] Declaratively Map Data Transformations to Object Properties Using Ramda evolve
We don't always control the data we need in our applications, and that means we often find ourselves ...
- [Ramda] Create a Query String from an Object using Ramda's toPairs function
In this lesson, we'll use Ramda's toPairs function, along with map, join, concatand compose to creat ...
- [Compose] 16. Apply multiple functors as arguments to a function (Applicatives)
We find a couple of DOM nodes that may or may not exist and run a calculation on the page height usi ...
- BLESS学习笔记
BLESS全称:Bloom-filter-based Error Correction Solution for High-throughput Sequencing Reads,即基于布隆过滤器的高 ...
随机推荐
- iOS界面生命周期过程具体解释
开发过Android的人都知道,每个Android界面就是一个Activity,而每个Activity都会有自己的生命周期, 有一系列方法会控制Activity的生命周期.如:onCreate(),o ...
- POJ--1753--Flip Game【DFS】
链接:http://poj.org/problem? id=1753 题意:一个4*4的方格,有白棋或者黑棋.每次操作是一个位置的颜色翻转,即白变黑.黑变白,而且与它相邻的四个位置的颜色也都跟着改变, ...
- hdu 4932
枚举差和差的1/2 #include <cstdio> #include <cstring> #include <algorithm> using namespac ...
- 关于hadoop hdfs里文件为啥上一级大小是0,进去又有大小问题解释?
问题 好像跟平时的理解不一样,外边是0,进去就是有大小了? 答:hdfs具体文件是针对具体文件的,不是文件目录. 文件夹大小为0,不是里面所有内容为0.
- jquery点击完一个按钮,并且触发另一个按钮
$a.click(function(){ $b.trigger('click'); });
- Maven学习总结(18)——深入理解Maven仓库
一.本地仓库(Local Repository) 本地仓库就是一个本机的目录,这个目录被用来存储我们项目的所有依赖(插件的jar包还有一些其他的文件),简单的说,当你build一个Maven项目的时候 ...
- 【部分原创】python实现视频内的face swap(换脸)
1.准备工作,按博主的环境为准 Python 3.5 Opencv 3 Tensorflow 1.3.1 Keras 2 cudnn和CUDA,如果你的GPU足够厉害并且支持的话,可以选择安装 那就先 ...
- Codeforces 232A - Cycles (构造 + 思维)
题目链接: 232A - Cycles(点击打开) 题意: 要构成一个存在 \(k\) 个三元环的图,需要多少个点,输出顶点数 \(n\),并输出图. 题解: 题目中的任何图都可以用 \(90\)~ ...
- JS学习笔记 - fgm练习 2-5 - 函数传参 设置div样式
练习地址:http://www.fgm.cc/learn/lesson2/05.html <script> window.onload = function(){ var oDiv = d ...
- 【Codeforces Round #299 (Div. 2) D】Tavas and Malekas
[链接] 我是链接,点我呀:) [题意] 给你n个位置,然后让你从某些位置开始的|p|个位置,填上p这个字符串. 问你填的时候是否会发生冲突->输出0 否则输出最终n个位置组成的可能的字符串的总 ...