fromkeys() keys() values() items()

 fromkeys()
 
 >>> dict1={}
 >>> dict1.fromkeys((1,2,3))#会自动为没有赋值的值建立none
 {1: None, 2: None, 3: None}
 >>> dict1.fromkeys((1,2,3),'number')＃将前一个括号分别与后面结合成项
 {1: 'number', 2: 'number', 3: 'number'}
 >>> dict1.fromkeys((1,2,3),('one','two','three'))＃将前面括号分别后后面括号整体结合组成项
 {1: ('one', 'two', 'three'), 2: ('one', 'two', 'three'), 3: ('one', 'two', 'three')}
 >>> dict1.fromkeys((1,3),'good')＃试图修改上一步中，1和3的值，但是结果是新建一个字典，内涵1和3，如果名称相同则会覆盖之前的
 {1: 'good', 3: 'good'}
 
 >>> dict1.fromkeys((1,2,3),('one','two','three'))
 >>> dict1.fromkeys((1,3),'数字')＃名称相同则会覆盖之前的
 
 fromkeys()＃列举32个赞
 
 >>> dict1 = dict1.fromkeys(range(32),'赞')
 
 keys()＃打印键
 
 >>> for eachkey in dict1.keys():
 print(eachkey)
 
 values()＃打印值
 
 >>> for eachvalue in dict1.value():
 print(eachvalue)
 
 items()# 打印项
 
 >>> for eachValue in dict1.values():
 print(eachValue)
 
 get（）函数
 
 >>> dict1.get(31)
 '赞'
 >>> dict1.get(32)
 >>> print(dict1.get(32))
 None
 >>> dict1.get(32,'木有')＃前面找不到时就打印后面的内容
 '木有'
 >>>