LeetCode 201 Bitwise AND of Numbers Range 位运算 难度:0
https://leetcode.com/problems/bitwise-and-of-numbers-range/
[n,m]区间的合取总值就是n,m对齐后前面一段相同的数位的值
比如
5:101
7:111
结果就是
4:100
class Solution {
public:
int rangeBitwiseAnd(int m, int n) {
int len = 0;
long long tmp = 1;
for(;tmp <= n || tmp <= m;len++){tmp<<=1;}
int ans = 0;
for(int i = len - 1;i>=0;i--){
if(((1<<i) & n) == ((1<<i) & m))ans |= (1<<i)&m;
else break;
}
return ans;
}
};
LeetCode 201 Bitwise AND of Numbers Range 位运算 难度:0的更多相关文章
- leetcode 201. Bitwise AND of Numbers Range(位运算,dp)
Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers ...
- [LeetCode] 201. Bitwise AND of Numbers Range ☆☆☆(数字范围按位与)
https://leetcode.com/problems/bitwise-and-of-numbers-range/discuss/56729/Bit-operation-solution(JAVA ...
- Java for LeetCode 201 Bitwise AND of Numbers Range
Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers ...
- [LeetCode#201] Bitwise AND of Numbers Range
Problem: Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of al ...
- 【LeetCode】201. Bitwise AND of Numbers Range 解题报告(Python)
[LeetCode]201. Bitwise AND of Numbers Range 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/prob ...
- 【LeetCode】201. Bitwise AND of Numbers Range
Bitwise AND of Numbers Range Given a range [m, n] where 0 <= m <= n <= 2147483647, return ...
- 【刷题-LeetCode】201 Bitwise AND of Numbers Range
Bitwise AND of Numbers Range Given a range [m, n] where 0 <= m <= n <= 2147483647, return t ...
- Java 位运算2-LeetCode 201 Bitwise AND of Numbers Range
在Java位运算总结-leetcode题目博文中总结了Java提供的按位运算操作符,今天又碰到LeetCode中一道按位操作的题目 Given a range [m, n] where 0 <= ...
- 201. Bitwise AND of Numbers Range
题目: Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all num ...
随机推荐
- RabbitMQ 入门 Helloworld
1.介绍 RabbitMQ 是信息传输的中间者.本质上,他从生产者(producers)接收消息,转发这些消息给消费者(consumers).换句话说,他能够按根据你指定的规则进行消息转发.缓冲.和持 ...
- vs快捷键
原文地址 ctrl是强制功能键,shift有给项目增加功能作用 1. 窗口快捷键 : window Ctrl+W,W: 浏览器窗口 (window shopping ) Ctrl+W,S: 解决方案 ...
- jQuery3的新特性
前言:自从react,vue等方便的新框架出现后,好多大公司已经摒弃了jquery,但是大部分的公司还在使用,并且jquery的版本还在一直更新中.jquery2.x版本将不再支持IE6/7/8浏览器 ...
- Tutorial - Deferred Rendering Shadow Mapping 转
http://www.codinglabs.net/tutorial_opengl_deferred_rendering_shadow_mapping.aspx Tutorial - Deferred ...
- javascriptの循序渐进(一)
javascriptの循序渐进系列为<javascript高级程序设计>的读书笔记,记录了看书过程中觉得重点的地方和一些总结,为学习javascript打好基础. ------------ ...
- URL编码和解码工具
开发中发现需要进行URL的编解码,每次百度出来的还带广告而且比较慢,写了一个本地的工具,比较简单,希望对大家有帮助. <!DOCTYPE html PUBLIC "-//W3C//DT ...
- 获取Echarts的DataZoom的起始值
创建DataZoom拖动事件 myChart.on(ecConfig.EVENT.DATA_ZOOM, eConsole); //事件名, 相关联的方法名 var ecConfig = requi ...
- kali更新源
原文链接:http://www.cnblogs.com/dunitian/p/4712852.html kali2.0官方下载地址: https://www.kali.org/downloads/ 可 ...
- PBS 安装
How to install PBS Pro using the configure script. . Install the prerequisite packages for building ...
- 【图像】Matlab图像标定工具箱
参考教程: Matlab工具箱教程 http://www.vision.caltech.edu/bouguetj/calib_doc/ 摄像机模型 http://oliver.zheng.blog ...