Two Bases CodeForces - 602A （BigInteger c++long long也可以）

哇咔咔 卡函数的

标记一下 c++和java的进制转换函数都是1-36进制的

c++ long long暴力就过了。。。

自己写一个就好了

import java.math.BigInteger;
import java.util.*;
import java.util.Arrays.*;
public class Main {
    static final int maxn = ;
    public static void main(String[] args) {
        Scanner cin = new Scanner(System.in);
        String str1 = new String();
        int n = cin.nextInt();
        int m = cin.nextInt();
        BigInteger a = BigInteger.ONE;
        for(int i=n-; i>=; i--)
        {
            str1 = cin.next();
            a = a.add(change(str1, m, i));
        }
        n = cin.nextInt();
        m = cin.nextInt();
        BigInteger b = BigInteger.ONE;
        for(int i=n-; i>=; i--)
        {
            str1 = cin.next();
            b = b.add(change(str1, m, i));
        }
        if(a.compareTo(b) == )
            System.out.println("=");
        else if(a.compareTo(b) < )
            System.out.println("<");
        else
            System.out.println(">");

    }
    public static BigInteger change(String str, int m, int i){
        BigInteger c = new BigInteger(str);
        c = c.multiply(new BigInteger(""+m).pow(i));
        return c;
    }

}