ACboy needs your help again!

Time Limit : 1000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other)
Total Submission(s) : 36   Accepted Submission(s) : 29

Font: Times New Roman | Verdana | Georgia

Font Size: ← →

Problem Description

ACboy was kidnapped!!  he miss his mother very much and is very scare now.You can't image how dark the room he was put into is, so poor :(. As a smart ACMer, you want to get ACboy out of the monster's labyrinth.But when you arrive at the gate of the maze, the monste say :" I have heard that you are very clever, but if can't solve my problems, you will die with ACboy." The problems of the monster is shown on the wall: Each problem's first line is a integer N(the number of commands), and a word "FIFO" or "FILO".(you are very happy because you know "FIFO" stands for "First In First Out", and "FILO" means "First In Last Out"). and the following N lines, each line is "IN M" or "OUT", (M represent a integer). and the answer of a problem is a passowrd of a door, so if you want to rescue ACboy, answer the problem carefully!

Input

The input contains multiple test cases. The first line has one integer,represent the number oftest cases. And the input of each subproblem are described above.

Output

For each command "OUT", you should output a integer depend on the word is "FIFO" or "FILO", or a word "None" if you don't have any integer.

Sample Input

4
4 FIFO
IN 1
IN 2
OUT
OUT
4 FILO
IN 1
IN 2
OUT
OUT
5 FIFO
IN 1
IN 2
OUT
OUT
OUT
5 FILO
IN 1
IN 2
OUT
IN 3
OUT

Sample Output

1
2
2
1
1
2
None
2
3

Source

2007省赛集训队练习赛(1)
 #include <stdio.h>
#include <stdlib.h>
#include <string.h> int main()
{
int N,FIFO,FILO,b[],i,j,T,sign[],sum;
scanf("%d",&N);
while(N--)
{
scanf("%d%s",&T,sign);
if(strcmp(sign,"FIFO")==)
{
i=;
j=;
while(T--)
{
scanf("%s",sign);
if(strcmp(sign,"IN")==)
{
scanf("%d",&b[i]);
i++;
}
else if(strcmp(sign,"OUT")==)
{
if(i==j)
{
printf("None\n");
continue;
}
printf("%d\n",b[j]);
j++;
} }
}
else if(strcmp(sign,"FILO")==)
{
i=;
j=;
while(T--)
{
scanf("%s",sign);
if(strcmp(sign,"IN")==)
{
scanf("%d",&b[i]);
i++;
}
else if(strcmp(sign,"OUT")==)
{
if(i==)
{
printf("None\n");
continue;
}
i--;
printf("%d\n",b[i]);
}
}
}
}
return ;
}

ACboy needs your help again!的更多相关文章

  1. hdu 1702 ACboy needs your help again!

    题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1702 ACboy needs your help again! Description ACboy w ...

  2. (hdu step 8.1.1)ACboy needs your help again!(STL中栈和队列的基本使用)

    题目: ACboy needs your help again! Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K ...

  3. hdu 1712 ACboy needs your help

    ACboy needs your help Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Ot ...

  4. hdu 1712 ACboy needs your help 分组背包

    转载请注明出处:http://blog.csdn.net/u012860063 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1712 Problem ...

  5. hdoj 1702 ACboy needs your help again!【数组模拟+STL实现】

    ACboy needs your help again! Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K ( ...

  6. HDU 1712 ACboy needs your help 典型的分组背包

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1712 ACboy needs your help Time Limit: 1000/1000 MS ( ...

  7. ACboy needs your help(HDU 1712 分组背包入门)

    ACboy needs your help Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Ot ...

  8. ACboy needs your help again!--hdu1702

    ACboy needs your help again! Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K ( ...

  9. 【泛化物品】【HDU1712】【ACboy needs your help】

    ACboy needs your help Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Ot ...

  10. HDU 1712 ACboy needs your help(包背包)

    HDU 1712 ACboy needs your help(包背包) pid=1712">http://acm.hdu.edu.cn/showproblem.php? pid=171 ...

随机推荐

  1. VS2013中使用QT插件后每次重新编译问题

    环境 系统:win7 64位旗舰版 软件:VS2013.QT5.5.1-32位.Qt5 Visual Studio Add-in1.2.4 概述 使用QT Visual Studio插件打开pro项目 ...

  2. hive-1.2.1安装步骤

    一.Hive安装和配置 1.先决条件 已经安装好hadoop-2.4.1,hbase-1.0.0. 2.下载Hive安装包 当前Hive可到apache官网下载,选择的是hive-1.2.1.运行: ...

  3. 用VB把xlsx转换为xls

    Sub Test()Dim wb As Workbook, mPath As String, f As StringApplication.DisplayAlerts = FalseApplicati ...

  4. Design Pattern——Factory_DP

    namespace TEST { //用于生成一个对应的操作类,这个工厂只是用来产生操作类的,不做其他只用 public class Factory { public Operate GetOpetr ...

  5. ARM裸板调试思路总结、笔记

    1. 点灯 2. 串口打印 3. JTAG调试器3.1 命令行调试 3.2 源码级别的调试前提a. 程序必须已经重定位好,位于它的链接地址a.1 如果程序的链接地址是SDRAM, 使用openocd初 ...

  6. Gulp构建

    整理自 https://markpop.github.io/2014/09/17/Gulp%E5%85%A5%E9%97%A8%E6%95%99%E7%A8%8B/ 已经有package.json 第 ...

  7. hbase伪分布

    1.编辑 conf/hbase-env.sh来告知HBase java的安装路径.在这个文件里你还可以设置HBase的运行环境,诸如 heapsize和其他 JVM有关的选项, 还有Log文件地址,等 ...

  8. Oracle杀死死锁进程

    查杀系统死锁的sql,最近想改造成存储过程,如下: CREATE OR REPLACE PROCEDURE HERO_KILLLOCKSESSION (OUT_COUNT OUT NUMBER, OU ...

  9. jQuery复习:第二章&第三章

    第二章 一.选择器 1.层次选择器 $(“ancestor descendant”)选取ancestor元素里的所有后代元素 $(“parent > child”)选取parent元素下的chi ...

  10. dplyr 数据操作 数据排序 (arrange)

    在R中,我们在整理数据时,经常需要对数据排序,以便数据增强数据的可读性. 下面我们来看下dplyr中的,arrange函数 arrange(.data, ...) 跟filter()类似,arrang ...