Description

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:

Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.

So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A''B''C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

  • One line with the word W, a string over {'A''B''C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
  • One line with the text T, a string over {'A''B''C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1
3
0

Source

【分析】
模板
 /*
宋代李之仪
卜算子·我住长江头
我住长江头,君住长江尾。日日思君不见君,共饮长江水。
此水几时休,此恨何时已。只愿君心似我心,定不负相思意。
*/
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <vector>
#include <utility>
#include <iomanip>
#include <string>
#include <cmath>
#include <queue>
#include <assert.h>
#include <map>
#include <ctime>
#include <cstdlib>
#include <stack>
#define LOCAL
const int MAXN = + ;
const int INF = ;
const int SIZE = ;
const int MAXM = + ;
const int maxnode = 0x7fffffff + ;
using namespace std;
int l1, l2;
char a[MAXN], b[MAXN];
int next[];//不用开太大了..
void getNext(){
//初始化next数组
next[] = ;
int j = ;
for (int i = ; i <= l1; i++){
while (j > && a[j + ] != a[i]) j = next[j];
if (a[j + ] == a[i]) j++;
next[i] = j;
}
return;
}
int kmp(){
int j = , cnt = ;
for (int i = ; i <= l2; i++){
while (j > && a[j + ] != b[i]) j = next[j];
if (a[j + ] == b[i]) j++;
if (j == l1){
cnt++;
j = next[j];//回到上一个匹配点
}
}
return cnt;
} void init(){
scanf("%s", a + );
scanf("%s", b + );
l1 = strlen(a + );
l2 = strlen(b + );
} int main(){
int T; scanf("%d", &T);
while (T--){
init();
getNext();
printf("%d\n", kmp());
}
/*scanf("%s", a + 1);
l1 = strlen(a + 1);
getNext();
for (int i = 1; i <= l1; i++) printf("%d ", next[i]);*/
return ;
}

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