codeforces 559A(Gerald's Hexagon)
Description
Gerald got a very curious hexagon for his birthday. The boy found out that all the angles of the hexagon are equal to . Then he measured the length of its sides, and found that each of them is equal to an integer number of centimeters. There the properties of the hexagon ended and Gerald decided to draw on it.
He painted a few lines, parallel to the sides of the hexagon. The lines split the hexagon into regular triangles with sides of 1 centimeter. Now Gerald wonders how many triangles he has got. But there were so many of them that Gerald lost the track of his counting. Help the boy count the triangles.
Input
The first and the single line of the input contains 6 space-separated integers a1, a2, a3, a4, a5 and a6 (1 ≤ ai ≤ 1000) — the lengths of the sides of the hexagons in centimeters in the clockwise order. It is guaranteed that the hexagon with the indicated properties and the exactly such sides exists.
Output
Print a single integer — the number of triangles with the sides of one 1 centimeter, into which the hexagon is split.
Sample Input
1 1 1 1 1 1
6
1 2 1 2 1 2
13
Hint
This is what Gerald's hexagon looks like in the first sample:
And that's what it looks like in the second sample:
程序分析:
题目大意:给出一个等角六边形的六条边长(都为整数厘米),按与边平行划线,问最多会分成多少个边长为1的小三角形
六边形的全部都被分为了小三角形,所以用六边形的面积/三角形的面积就是三角形的数量
六边形的面积:设六条边长为a[1]到a[6]
等角六边形的对边平行,连接两个对边的定点,就得到一个梯形和两个三角形,梯形的上底是a[4],下底是a[1],高由划红线的地方算出a[3]*sin(PI/3.0)+a[2]*sin(PI/3.0),这样就可以算出梯形的面积,其余的两个三角形的面积为a[2]*a[3]*sin(PI/3.0)/2, a[5]*a[6]*sin(PI/3.0)/2
小三角形的面积:1*1*sin(PI/3.0)/2.0 ;所以这个题目的重点就是找到计算公式就OK了。
程序代码:
#include<stdio.h>
double a[] ;
int main() {
int i ;
double s ;
for(i = ; i <= ; i++)
scanf("%lf", &a[i]) ;
s = (a[]+a[])*(a[]+a[]) + a[]*a[]+ a[]*a[];
printf("%d\n", (int)(s+0.5)) ;
return ;
}
codeforces 559A(Gerald's Hexagon)的更多相关文章
- codeforces 559a//Gerald's Hexagon// Codeforces Round #313(Div. 1)
题意:面积是sqrt(3)/4的多少倍? 做延长线 #pragma comment(linker,"/STACK:1024000000,1024000000") #include& ...
- Codeforces 559A Gerald's Hexagon 数三角形
题意:按顺序给出一个各内角均为120°的六边形的六条边长,求该六边形能分解成多少个边长为1的单位三角形. 把单位三角形面积看做1,实际上就是求六边形面积.随便找六边形的三条互相不相邻的边,分别以这三条 ...
- Codeforces Round #313 (Div. 1) A. Gerald's Hexagon
Gerald's Hexagon Problem's Link: http://codeforces.com/contest/559/problem/A Mean: 按顺时针顺序给出一个六边形的各边长 ...
- Codeforces Round #313 (Div. 2) C. Gerald's Hexagon 数学
C. Gerald's Hexagon Time Limit: 2 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/559/pr ...
- Codeforces Round #313 (Div. 1) A. Gerald's Hexagon 数学题
A. Gerald's Hexagon Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/559/p ...
- 【41.43%】【codeforces 560C】Gerald's Hexagon
time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard o ...
- Codeforces Round #313 (Div. 2) C. Gerald's Hexagon
C. Gerald's Hexagon time limit per test 2 seconds memory limit per test 256 megabytes input standard ...
- Gerald's Hexagon
Gerald's Hexagon Gerald got a very curious hexagon for his birthday. The boy found out that all the ...
- Codeforces 559A 第六周 O题
Description Gerald got a very curious hexagon for his birthday. The boy found out that all the angle ...
随机推荐
- pyVmomi入门
简要说明 pyVmomi is the Python SDK for the VMware vSphere API that allows you to manage ESX, ESXi, and v ...
- gitlab使用入门
第一步:安装git软件 方法:百度git 点击下载,然后双击安装,一直点下一步即可. 第二步:设置用户名和邮箱 方法:在桌面上点鼠标右键,选择Git Bash,然后分别运行命令 git confi ...
- nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException
You should autowire interface AbstractManager instead of class MailManager. If you have different im ...
- css table 布局
使用CSS表格 CSS表格能够解决所有那些我们在使用绝对定位和浮动定位进行多列布局时所遇到的问题.例如,“display:table;”的CSS声明能够让一个HTML元素和它的子节点像table元素一 ...
- nefu 462 fib组合
nefu 462 fib组合 (斐波那契数列的通项公式以及推倒过程) 分类: 数学2014-05-21 10:27 190人阅读 评论(0) 收藏 举报 题目链接:http://acm.nefu.ed ...
- iOS:原生二维码扫描
做iOS的二维码扫描,有两个第三方库可以选择,ZBar和ZXing.今天要介绍的是iOS7.0后AVFoundation框架提供的原生二维码扫描. 首先需要添加AVFoundation.framewo ...
- linux:如何修改用户的密码
1.首先,要用CRT软件连接Linux系统. 2.首选,确认是用root用户登录系统的. 输入命令: id ,查看登录用户信息. 3.若修改root自己的密码,直接输入 passwd . 输入两遍,新 ...
- windows系统操作类和演示程序(关机,关闭显示器,打开屏幕保护程序,打开光驱等)
/// <summary> /// 系统控制类,关机,关闭显示器,打开屏幕保存程序等 /// </summary> public class SystemPowerContro ...
- POJ 3630 Phone List(trie树的简单应用)
题目链接:http://poj.org/problem?id=3630 题意:给你多个字符串,如果其中任意两个字符串满足一个是另一个的前缀,那么输出NO,否则输出YES 思路:简单的trie树应用,插 ...
- web 性能优化指南阅读笔记
1.关于拥塞预防算法 PRR-比例降速,RFC6937 规定的一个新算法,其目标是改进丢包后的恢复速度,谷歌测量结果:该算法改进丢包造成的平均连接延迟减少了3%-10%.PRR是linux 3.2+内 ...