281. Zigzag Iterator
题目:
Given two 1d vectors, implement an iterator to return their elements alternately.
For example, given two 1d vectors:
v1 = [1, 2]
v2 = [3, 4, 5, 6]
By calling next repeatedly until hasNext returns false
, the order of elements returned by next should be: [1, 3, 2, 4, 5, 6]
.
Follow up: What if you are given k
1d vectors? How well can your code be extended to such cases?
Clarification for the follow up question - Update (2015-09-18):
The "Zigzag" order is not clearly defined and is ambiguous for k > 2
cases. If "Zigzag" does not look right to you, replace "Zigzag" with "Cyclic". For example, given the following input:
[1,2,3]
[4,5,6,7]
[8,9]
It should return [1,4,8,2,5,9,3,6,7]
.
链接: http://leetcode.com/problems/zigzag-iterator/
题解:
Zigzag Iterator。最简单的就是用两个index分别遍历两个list,然后用一个boolean变量来控制何时遍历哪一个list。 好像我这么做是有问题的,应该用Interator<>来做。
Time Complexity - O(n), Space Complexity - O(1)
public class ZigzagIterator {
private int length;
private int index1 = 0;
private int index2 = 0;
private List<Integer> list1;
private List<Integer> list2;
private boolean useList2; public ZigzagIterator(List<Integer> v1, List<Integer> v2) {
this.length = v1.size() + v2.size();
list1 = v1;
list2 = v2;
if(list1.size() == 0) {
useList2 = true;
}
} public int next() {
if(!useList2) {
if(index2 < list2.size()) {
useList2 = true;
}
return list1.get(index1++);
} else {
if(index1 < list1.size()) {
useList2 = false;
}
return list2.get(index2++);
} } public boolean hasNext() {
return (index1 + index2) < length;
}
} /**
* Your ZigzagIterator object will be instantiated and called as such:
* ZigzagIterator i = new ZigzagIterator(v1, v2);
* while (i.hasNext()) v[f()] = i.next();
*/
Reference:
https://leetcode.com/discuss/57961/o-n-time-%26-o-1-space-java-solution
https://leetcode.com/discuss/63037/simple-java-solution-for-k-vector
https://leetcode.com/discuss/58012/short-java-o-1-space
https://leetcode.com/discuss/71857/clean-java-solution-works-for-k-lists
281. Zigzag Iterator的更多相关文章
- [LeetCode] 281. Zigzag Iterator 之字形迭代器
Given two 1d vectors, implement an iterator to return their elements alternately. Example: Input: v1 ...
- [LeetCode#281] Zigzag Iterator
Problem: Given two 1d vectors, implement an iterator to return their elements alternately. For examp ...
- 281. Zigzag Iterator z字型遍历
[抄题]: Given two 1d vectors, implement an iterator to return their elements alternately. Example: Inp ...
- 【LeetCode】281. Zigzag Iterator 解题报告 (C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 deque 日期 题目地址:https://leetc ...
- [Locked] Zigzag Iterator
Zigzag Iterator Given two 1d vectors, implement an iterator to return their elements alternately. Fo ...
- Zigzag Iterator II
Description Follow up Zigzag Iterator: What if you are given k 1d vectors? How well can your code be ...
- [LeetCode] Zigzag Iterator 之字形迭代器
Given two 1d vectors, implement an iterator to return their elements alternately. For example, given ...
- Zigzag Iterator
Given two 1d vectors, implement an iterator to return their elements alternately. For example, given ...
- LeetCode Zigzag Iterator
原题链接在这里:https://leetcode.com/problems/zigzag-iterator/ 题目: Given two 1d vectors, implement an iterat ...
随机推荐
- c语言参数类型
今天看ntcip源码时看到,函数参数有点不一样.在函数实现时,没有括号中没有指明参数类型.注意这里说的是函数实现,不是说函数声明.这里在函数列表括号后面做了类型的说明,以前看到过,没想起来,今天做个记 ...
- Log4J配置文件说明
Log4J的配置文件(Configuration File)就是用来设置记录器的级别.存放器和布局的,它可接key=value格式的设置或xml格式的设置信息.通过配置,可以创建出Log4J的运行环境 ...
- 最大后验估计(MAP)
最大后验估计是根据经验数据获得对难以观察的量的点估计.与最大似然估计类似,但是最大的不同时,最大后验估计的融入了要估计量的先验分布在其中.故最大后验估计可以看做规则化的最大似然估计. 首先,我们回顾上 ...
- Careercup - Microsoft面试题 - 5752271719628800
2014-05-10 20:31 题目链接 原题: Given an array of integers and a length L, find a sub-array of length L su ...
- 【Merge Sorted Array】cpp
题目: Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Not ...
- sudo su 提示没有配置JDK environment
sudo su 提示没有配置JDK environment 最近工作遇到一问题,我通过SecureCRT远程登录服务器,部署web应用.将变更文件替换后,我需要切换到root用户,重启Tomcat.所 ...
- Nginx问题总汇
http://blog.csdn.net/llnara/article/details/8691049 关键字: open var run nginx pid failed 产生原因:添加模块,重编译 ...
- 【BZOJ】【2301】problem b
莫比乌斯反演/容斥原理 Orz PoPoQQQ PoPoQQQ莫比乌斯函数讲义第一题. for(i=1;i<=n;i=last+1){ last=min(n/(n/i),m/(m/i)); …… ...
- Linux常用命令大全(转载)
系统信息 arch 显示机器的处理器架构(1) uname -m 显示机器的处理器架构(2) uname -r 显示正在使用的内核版本 dmidecode -q 显示硬件系统部件 - (SMBIOS ...
- URAL题解—不断跟新中
1014:简单题,忘了0的情况可以是10,== 1219:找呀找规律,满足N*(N-1)/2+1=X;就是1 的情况了