1017 A除以B (20 分)

#include <iostream>
#include <string>
using namespace std;
int main() {
    string num;
    int a, b, m;
    cin >> num >> m;    // 一个为字符串一个为整形数字避免了麻烦的处理
    int len = num.size();
    a = (num[] - '') / m;
    b = (num[] - '') % m;
    if (len ==  || (len >  && a != ))   // 判断数字的第一个是否为零，位数为1的情况，不为1的情况
        cout << a;
    for (int i = ; i < len; i++) {
        a = (b *  + (num[i] - '')) / m;
        cout << a;
        b = (b *  + (num[i] - '')) % m;
    }
    cout << " " << b;
    return ;
}