求其中同一个主叫号码的两次通话之间间隔大于10秒的通话记录ID

求其中同一个主叫号码的两次通话之间间隔大于10秒的通话记录ID

例如：6，7，8，9，10条记录均符合

ID 主叫号码 被叫号码      通话起始时间            通话结束时间            通话时长

1  98290000 0215466546656 2007-02-01 09:49:53.000 2007-02-01 09:50:16.000 23

2  98290000 021546654666  2007-02-01 09:50:29.000 2007-02-01 09:50:41.000 12

3  98290000 021546654666  2007-02-01 09:50:58.000 2007-02-01 09:51:12.000 14

4  68290900 0755133329866 2007-02-01 10:04:31.000 2007-02-01 10:07:13.000 162

5  78290000 0755255708638 2007-02-01 10:48:26.000 2007-02-01 10:49:23.000 57

6  78290000 0755821119109 2007-02-01 10:49:39.000 2007-02-01 10:52:55.000 196

7  78290000 035730928370  2007-02-01 11:30:45.000 2007-02-01 11:31:58.000 73

8  78290000 0871138889904 2007-02-01 11:33:47.000 2007-02-01 11:35:00.000 73

9  68290000 035730928379  2007-02-01 11:52:20.000 2007-02-01 11:54:56.000 156

10 68290000 0298521811199 2007-02-01 12:44:45.000 2007-02-01 12:45:04.000 19

将数据复制到记事本，保存为time.txt，导入到数据库，生成表[time]，然后可做测试。得到三个方法：

--方法一
select distinct * from(
SELECT a.* FROM dbo.[time] a left join dbo.[time] b
ON a.phone=b.phone
WHERE a.id<b.id
AND DATEDIFF(second,a.st,b.et)>10
UNION ALL
SELECT a.* FROM dbo.[time] a left join dbo.[time] b
ON a.phone=b.phone
WHERE a.id>b.id
AND DATEDIFF(second,b.st,a.et)>10) a
order by id,phone

--方法二
SELECT
distinct
a.* FROM dbo.[time] a left join dbo.[time] b
ON a.phone=b.phone
WHERE a.id<>b.id
AND (DATEDIFF(second,a.st,b.et)>10 or DATEDIFF(second,b.st,a.et)>10)
order by id,phone

--方法三
select * from dbo.[time] t
where exists(select 1 from dbo.[time] where id<>t.id
and phone=t.phone
AND (DATEDIFF(second,st,t.et)>10 or DATEDIFF(second,t.st,et)>10))

我最喜欢方法三，采用exists语句。网上的许多SQL面试答案，通常用IN之类，极少用EXISTS，可能是习惯问题。

这道面试题，是从网上一篇文章里抄过来，作者给出的答案是：

SELECT DISTINCT a.* FROM dbo.hc a left join dbo.hc b

ON a.主叫号码=b.主叫号码

WHERE a.id<>b.id AND (DATEDIFF(second,a.通话起始时间,b.通话结束时间)>10 AND

DATEDIFF(second,b.通话起始时间,a.通话结束时间)>10)

我觉得在这里用 AND 是有问题的。

参考文章：

http://blog.sina.com.cn/s/blog_63041bb80101a8mn.html