Timus Online Judge 1001. Reverse Root

Input

The input stream contains a set of integer numbers A_i (0 ≤ A_i ≤ 10¹⁸). The numbers are separated by any number of spaces and line breaks. A size of the input stream does not exceed 256 KB.

Output

For each number A_i from the last one till the first one you should output its square root. Each square root should be printed in a separate line with at least four digits after decimal point.

Sample

input	output
1427 0   876652098643267843 5276538	2297.0716 936297014.1164 0.0000 37.7757

译文：

输入：

输入一个整数数组，这个数组中每个整数的取值范围为0<= Ai <=10的18次方。这些数字被一些空格和换行符分隔。输入的内存限制为256KB。

输出：

倒序输出数组的平方根。每个平方根结果保留最后四位小数。

==========================

第一次code:

 import java.math.BigDecimal;
 import java.math.RoundingMode;
 import java.util.Scanner;
 
 public class Main
 {
     public static void main(String[] args)
     {
         Scanner input = new Scanner(System.in);
         long[]a = new long[1000000000];
         int i;
         for (i=0; input.hasNext(); i++)
         {
              a[i] = input.nextLong();
         }
         for(i--;i>-1;i--)
         {
                         /**
                         *   Math.sqrt()  :  对数据求平方
                         *   BigDecimal适用于大型数据计算，精确度高
                         */
             BigDecimal   b   =   new   BigDecimal(Math.sqrt(a[i]));
             System.out.println(b.setScale(4,RoundingMode.HALF_UP).toString());
         }
     }
 }
     

-------------------------------------我是万恶的分割线---------------------------------------------------------------------------------------------------------

/*

题目稍微修改一下，首先输入一个数，定义数组大小，然后倒序输出该数组的平方根。

*/

 import java.math.BigDecimal;
 import java.math.RoundingMode;
 import java.util.Scanner;
 
 public class Main
 {
     public static void main(String[] args)
     {
         Scanner input = new Scanner(System.in);
         int n =input.nextInt();
         run();
     }
     public static void run()
     {
         Scanner input = new Scanner(System.in);
         long[]a = new long[n];
         int i;
         for (i=0; i<n; i++)
         {
              a[i] = input.nextLong();
         }
         for(i--;i>-1;i--)
         {
             BigDecimal   b   =   new   BigDecimal(Math.sqrt(a[i]));
             System.out.println(b.setScale(4,RoundingMode.HALF_UP).toString());
         }
     }
 }