Given a string S and a string T, count the number of distinct subsequences of T in S.

A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE" is a subsequence of "ABCDE" while "AEC" is not).

Here is an example:
S = "rabbbit", T = "rabbit"

Return 3.

解题思路:

dp问题,弄清递推公式即可,参考Distinct Subsequences@LeetCode ,JAVA实现如下:

	public int numDistinct(String s, String t) {
if (t.length() == 0)
return 1;
int[] dp = new int[t.length() + 1];
dp[0] = 1;
for (int i = 0; i < s.length(); i++) {
int last = 1;
for (int j = 0; j < t.length(); j++) {
if (dp[j] == 0)
break;
int temp = dp[j + 1];
if (s.charAt(i) == t.charAt(j))
dp[j + 1] += last;
last = temp;
}
}
return dp[t.length()];
}

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